Bredt's Rule - Explained with Proof | Applications | Problems | IITian Explains
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- เผยแพร่เมื่อ 11 ต.ค. 2024
- In its original form, Bredt's Rule stated that bridged ring systems and pinane cannot have a double bond at the bridgehead position .
In principle, the Bredt’s rule is simply a consequence of the strain induced by a planar bridgehead carbon.
A few key concepts to keep in mind when understanding the Bredt’s rule are -
A double bond comprises one sigma bond and a one π bond.
The pi bond is formed by the overlap of p-orbitals. Therefore these p-orbitals must be on the same planar. If they are not, the chances of an overlap are negligible and the bond formed will be unstable.
A double bond on a bridgehead would be equivalent to having a trans pi double bond on a ring, which is not stable for small rings (fewer than eight atoms) due to a combination of ring strain, and angle strain (nonplanar alkene).
Bridged bicyclic compounds can only exhibit a double bond at a bridgehead position if one of the rings has at least eight carbon atoms
And therefore, bridgehead double bonds are unstable due to poor orbital overlap.
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IITian Explains
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Hi sir...I have a doubt
[Ni(CO)4] is a determined experimentally to be diamagnetic in nature.
VBT : Forcefully pairs the 4s^2 electrons
CFT : As CO is a strong field ligand...pairing is done.But 2 electrons are left unpaired due to Aufbau Principle in the dz^2 & dx^2-y^2?
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sir bahut badiya se topic samajh aa gaya.
Mentos In more than 8 membered bridge head system bredts rule is not applicable
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28:30 Sir I think the order is incorrect, did you forget that N can give electrons in resonance more easily than Oxygen so, please correct me wherever I was wrong, BTW thank you for this lecture
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Not for Mains Only for Advanced examination
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