Que emocionante assistir a esse vídeo! Ensinar é realmente um dom divino! Sou professora de Matemática há 15 anos! Há dias em que penso em desistir! Mas assistir a esse vídeo, com tanto amor e cuidado, me faz repensar o porquê escolhemos ser Professor!
This is what I would expect: If it is a totally elastic collision, then kinetic energy (a scalar) as well as momentum (a vector) is conserved and we get one answer by solving the momentum and kinetic energy equations together. Mass is factored out in doing this, of course. If it is a partially elastic collision, some unknown proportion of kinetic energy is lost and we can state the relative velocities after collision and that is it. If it is a totally inelastic collision, the bodies stick together and remain stuck together, and both are now at rest since the total momentum remains zero. On top of that are the two cases for whether the initial velocities are in opposite directions or in the same direction with the faster object catching up with the slower object. I hope this makes sense. What boggled my mind when I was in high school physics class was the situation where the bodies are traveling relative to one another while sliding frictionlessly on the surface of a third body which is also in motion. Now, how does one figure the kinetic energy involved, even if a totally elastic collision is stipulated? In what framework, that of the third body or of a stationary observer? Does it matter? This isn't even a relativistic speeds question.
Summary of collisions: Since there is no F(ext) in the total system during collison, just apply conservation of momentum. e=0 in perfectly inelastic collision and e=1 for perfectly elastic collision. THIS IS JUST A VERY SHORT SUMMARY. U NEED TO WORK WITH ENERGIES TOO!!
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current junior in college and your videos helped me pass my physics course this semester, thank you professor Feng!
I feel like these are gonna be my new comfort vids. Thanks grampy
I fell in love with your teaching. I love you grandpa ❤️
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When I am not tired I will come to this video. When you are so good at what you are doing ..this is what u become
Wish I had you as a physics teacher when I was in still in school, I love the way you explain everything. You are awesome!
problem solved masterfully, thank you for your knowledge master, greetings from Brazil
Que emocionante assistir a esse vídeo! Ensinar é realmente um dom divino! Sou professora de Matemática há 15 anos! Há dias em que penso em desistir! Mas assistir a esse vídeo, com tanto amor e cuidado, me faz repensar o porquê escolhemos ser Professor!
The humble plus sign is among the oldest agreed-upon mathematical symbols but only came into general use around 1360.
What an intelligent and humble man ❤ Keep it up!!!
This is what I would expect:
If it is a totally elastic collision, then kinetic energy (a scalar) as well as momentum (a vector) is conserved and we get one answer by solving the momentum and kinetic energy equations together. Mass is factored out in doing this, of course.
If it is a partially elastic collision, some unknown proportion of kinetic energy is lost and we can state the relative velocities after collision and that is it.
If it is a totally inelastic collision, the bodies stick together and remain stuck together, and both are now at rest since the total momentum remains zero.
On top of that are the two cases for whether the initial velocities are in opposite directions or in the same direction with the faster object catching up with the slower object.
I hope this makes sense.
What boggled my mind when I was in high school physics class was the situation where the bodies are traveling relative to one another while sliding frictionlessly on the surface of a third body which is also in motion. Now, how does one figure the kinetic energy involved, even if a totally elastic collision is stipulated? In what framework, that of the third body or of a stationary observer? Does it matter? This isn't even a relativistic speeds question.
Thank you for this lesson ! You are a great help and amazing teacher!
I loved the lecture. Very inspirational.
got referred to you by bprp ... 🔥🔥was looking for math and found gold in this physics video
I love your classes!
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Thank you for your wisdom and knowledge!
Hey man you are the best and BRILLIANT!
you are such a great teacher! thank you for sharing your knowledge.
Awesome!!!🇧🇷🇧🇷
Great vid once again, sir.
Thank you for making our learning fun and easy! You are an inspiration. We are so lucky to have you as our teacher💐❤️
THANK YOU SI MUCH FOR THIS! I have a big test tomorrow ❤
Learning so much from you. Thank you.
Learning so much. Thank you.❤
i've got the ap physics test in 4 hours and there is no better way to study than with your videos :)
Very interesting problem, New subscriber sir!!
Great one ❤
I really enjoyed this video!
Summary of collisions:
Since there is no F(ext) in the total system during collison, just apply conservation of momentum. e=0 in perfectly inelastic collision and e=1 for perfectly elastic collision. THIS IS JUST A VERY SHORT SUMMARY. U NEED TO WORK WITH ENERGIES TOO!!
Thank you!! This was very helpful :)
good onee
Amazing thank so so much, it is so useful
you are so inspirational, thank you for explaining these concepts!
Thank you that you like it.
thank you for this helpful lecture!
Thank you teacher!
Thank you, sir!
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Thank you!
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Very nice
Yayyy thankyou Sir ❤
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Thanks sir❤
Hell yes
Mathematics' reliance on notation is essential to the abstract concept it explores. 0:18
Because mathematics is the same all over the world, math can act as a universal language. 18:00
Sir , i have one physics question that i couldn't solve these last 2 years, if possible where can i send it to you ?
Yes please send
Complex numbers are helpful in finding the square root of negative numbers. 25:52
Thank you Professor Feng. How do I join your Maths class?
If you just watch, then just watch. You don’t need to join.
Is that what you like, just watch?
Truly yours,
FENG
@@ycmathematicsphysicsandche5659 Okay, thank you Prof.
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先是动量量守恒，后应有动能守恒。动量有方向所以是向量有正负号。动能无方向，所以是标量。这是宏观物体。微观粒子只有动量守恒却无动能守恒。
magnifique
❤
Very nice