@@bjornfeuerbacher5514 yeah If you use the polar form, you will end out seeing that you chan multiply 2*pi*n+1, because the revolutions that you can do are infinitely!!! Yeah, after all, it has sence (Not sarcastic)
So let me get something straight you're telling me 1/n=x when you're making substitution to solve the Reimanin sums to a integral form? Man I should be practicing this more i had to take minute comprehend this.
One important mistake to avoid is not changing the top right part to √(n^2 +1) 😂
Hahah
I also did that
At first, i have a thought of -i^2=1 for this problem, anyway i is not the imaginary unit for this one problem😃
Thank you for allowing us to download🙏
Can you make a video on surface integrals for my calc 3 class?
I always watch. Thank your for give some knowledge.
Very cool!
I thought that I=sqrt(-1)
In the context of summations it’s usually just a iteration variable
So sqrt(-1) is going from 0 to infinity? Yes, makes lots of sense. :D
@@bjornfeuerbacher5514 yeah
If you use the polar form, you will end out seeing that you chan multiply 2*pi*n+1, because the revolutions that you can do are infinitely!!!
Yeah, after all, it has sence
(Not sarcastic)
Until i saw the limits
A 'c' is passing
???
So let me get something straight you're telling me 1/n=x when you're making substitution to solve the Reimanin sums to a integral form? Man I should be practicing this more i had to take minute comprehend this.
No, 1/n = delta x, not 1/n = x.
0th
Erm what the sigma?