That was quite descriptive, thanks. One can incorporate reverse voltage protection in place of the shottky diode as you have the P channel fet in place already to reduce power losses and heat even further, with a diode and a resistor between outputs (Vcc and GND) to the gate of the n-channel fet **I think** would do it - though, it will need a bit more thought than this (maybe a second n-fet?) in order to keep the power consumption during low battery condition to a minimum as the current circuit does already.
Thanks for the comment. N channel MOSFETs are better used as low side switches. An N MOSFET does not just turn on with a "high" on the gate. The gate has to be higher in potential than source. For instance if the source has 10v on it then gate needs like >12v to turn on. Hope that makes sense
@@ForceTronics what would you think about increasing R1 to a much higher value? For my circuit 100k is 1.7ms vs 4.7M is .08s on time which is much slower but that way we limit the current loss even more through the NPN mosfet
Hm. Both MOS-fets is N-channel in the diagram. But I understand the diagram. I couldn't find a P-channel MOS-Fet in Eagle ether.... Thanks for sharing.
I am sure it could be. Just need to setup the right resistor divider network. My videos are meant to be examples that others can modify to fit their application
Thanks a ton for this video. Personally I'm gonna use a XC61CN voltage detector, PMOS AO3401A and NMOS BSS138. I noticed you use a 5Mohm resistor. If I understand correctly, when this is fed to the NMOS it's going to charge the input capacitance of the NMOS anyway, so a big resistor shouldn't be a problem? All the best! Thanks again
Glad the video was useful. Yeah you got it, 5Mohm resistor serves as a pullup unless the cutoff is triggered. High value is chosen to reduce current flow as much as possible with the pullup function still working. You can play with higher values to see if they do the job and further reduce current flow from the battery
It is not profitable enough for me to build and sell these circuits. We provide the video free to help you design your own. If you want ForceTronics to design a custom one for you go to our website and fill out a request. We charge $90 US per hour for design work
![[005] How M18 batteries communicate with tools](http://i.ytimg.com/vi/q7spzrIbdKY/mqdefault.jpg)
That was quite descriptive, thanks.
One can incorporate reverse voltage protection in place of the shottky diode as you have the P channel fet in place already to reduce power losses and heat even further, with a diode and a resistor between outputs (Vcc and GND) to the gate of the n-channel fet **I think** would do it - though, it will need a bit more thought than this (maybe a second n-fet?) in order to keep the power consumption during low battery condition to a minimum as the current circuit does already.
Great videos man, juat curious why you use one mosfet to control another instead of just using an nchanel mosfet and the high signal to open it
Thanks for the comment. N channel MOSFETs are better used as low side switches. An N MOSFET does not just turn on with a "high" on the gate. The gate has to be higher in potential than source. For instance if the source has 10v on it then gate needs like >12v to turn on. Hope that makes sense
@@ForceTronics that makes a lot of sense and im designing a circuit using information from your video! thanks for the great explanations
@@ForceTronics what would you think about increasing R1 to a much higher value? For my circuit 100k is 1.7ms vs 4.7M is .08s on time which is much slower but that way we limit the current loss even more through the NPN mosfet
You can use any resistor value you want. Just need to make sure enough current is getting to the gate of the mosfet to turn it on. @@Jan-gj8bm
Great job! If we have any solution to deal with voltage regulator draining battery... It would be great too!
Hm. Both MOS-fets is N-channel in the diagram. But I understand the diagram.
I couldn't find a P-channel MOS-Fet in Eagle ether....
Thanks for sharing.
Nice explanation, can this circuit be modified to monitor a 144 volt battery to shut down at approximately 90voltd?
I am sure it could be. Just need to setup the right resistor divider network. My videos are meant to be examples that others can modify to fit their application
Thanks a ton for this video. Personally I'm gonna use a XC61CN voltage detector, PMOS AO3401A and NMOS BSS138.
I noticed you use a 5Mohm resistor. If I understand correctly, when this is fed to the NMOS it's going to charge the input capacitance of the NMOS anyway, so a big resistor shouldn't be a problem?
All the best! Thanks again
Glad the video was useful. Yeah you got it, 5Mohm resistor serves as a pullup unless the cutoff is triggered. High value is chosen to reduce current flow as much as possible with the pullup function still working. You can play with higher values to see if they do the job and further reduce current flow from the battery
Waiting for the part 2
Part 2 is available
Hello how can I order the circuit please
It is not profitable enough for me to build and sell these circuits. We provide the video free to help you design your own. If you want ForceTronics to design a custom one for you go to our website and fill out a request. We charge $90 US per hour for design work