A very good demonstration of hyperbolae. Though of course, actual LORAN (and GEE the older system most similar to LORAN in being based on time difference of arrival instead of phase difference) didn't know the X and Y position of the ship. Instead two different hyperbolae were used, and the ship's (or aircraft's, in the case of GEE) location was determined by finding the intercept points of the two hyperbolae.
the key question is that, in the coordinate composed by these two stations, how could the ship knows its (x value) 100 miles of the Y axle east side? even both the stations don't know.
The position of the stations is known ahead of time (e.g., using tables/charts). One also needs to know the distance to each station (e.g., using signal correlation to determine propagation delays). It follows that we must know this already (in the system mentioned) to understand the "difference (in propagation delay) between the signals" discussed in the video. With this information we can then plot a triangle, its three nodes being the ship and the two stations, which we use to solve X and Y by (extensions of) Pythagorean theorem.
i have doubts also. you cannot suppose x =100 or any value. because the ship could be in any location, then there are many different "a" value. then there will be different hyperbolic curves.
@@LikeColorBlue Correct - really the ship is at the intersection of a number of hyperbolic curves, created by multiple transmitters. The really hard bit is solving the system of equations this produces - something which I'm currently struggling with!
Kudos on the verbal demonstration of the audio emissions. I really liked it.
Thank you! At 7:50 : How would you know "x"? If you had a GPS, this would make this whole exercise pointless.
This saved my day. An excellent example of LORAN
I like this guy. I have been having a tough time understanding this. Thank you this helped a lot.
A very good demonstration of hyperbolae.
Though of course, actual LORAN (and GEE the older system most similar to LORAN in being based on time difference of arrival instead of phase difference) didn't know the X and Y position of the ship. Instead two different hyperbolae were used, and the ship's (or aircraft's, in the case of GEE) location was determined by finding the intercept points of the two hyperbolae.
the key question is that, in the coordinate composed by these two stations, how could the ship knows its (x value) 100 miles of the Y axle east side? even both the stations don't know.
Makes sense
@@bernalfiesaysip8791 I have the same doubt. Have you found any solution?
@@md.amirulislam7371 not yet, im having some doubts too
The position of the stations is known ahead of time (e.g., using tables/charts). One also needs to know the distance to each station (e.g., using signal correlation to determine propagation delays). It follows that we must know this already (in the system mentioned) to understand the "difference (in propagation delay) between the signals" discussed in the video. With this information we can then plot a triangle, its three nodes being the ship and the two stations, which we use to solve X and Y by (extensions of) Pythagorean theorem.
A very good demonstration
The old companies like LORAC and DECCA Survey used these principles.
Yeah, turn on the Closed Captions if you really want to nail down the spelling of the sound effects. ;-)
Hello, I have some doubts. Could you help me, please?
i have doubts also. you cannot suppose x =100 or any value. because the ship could be in any location, then there are many different "a" value. then there will be different hyperbolic curves.
@@LikeColorBlue Correct - really the ship is at the intersection of a number of hyperbolic curves, created by multiple transmitters. The really hard bit is solving the system of equations this produces - something which I'm currently struggling with!
Great application! 😊
Awesome video
thank you
KILLS THE SATALLITE SHIT