Nice job, Sleuth! Thanks for featuring my puzzle. I think my favourite deduction is where the 3 goes in box 7, by using the renban in boxes 4 and 7 to eliminate r7c2.
13:16 for me. Some digits were possible to get easier way also. Box 4 renban with 8 digit 6 was forced by that renban from box 1 as that forces another renban to place 6 into one exact row to forcing 6-s location pretty much over entire field.
A trick that I used repeatedly here was finding the cells that can see every cell of a longer renban, and eliminating the required digits from the renban from those cells. For example, for a while you had "459" pencilled into r7c4 and r8c7, and you knew that one of them had to be a 5. That meant that r7c789 and r8c456 couldn't contain a 5. That could corner mark a 5 into box 8, and reveal a 14 pair in row 7, which then bounces back into box 8. There were a few other times this type of non-conventional elimination helped speed my solve along. My time today was 14:02, solver number 2199.
Nice job, Sleuth! Thanks for featuring my puzzle. I think my favourite deduction is where the 3 goes in box 7, by using the renban in boxes 4 and 7 to eliminate r7c2.
Thank you for the puzzle and series Blobz. They’ve been tougher than expected thus far but looking forward to them!
That was my favorite deduction too. Thanks for the puzzle!
Great puzzle for a foggy morning
31:23 ... I enjoyed that journey through the Misty Mountains!
12:42 what a beautiful puzzle. Another one from the great Lord of The Rings! 😍
13:16 for me. Some digits were possible to get easier way also. Box 4 renban with 8 digit 6 was forced by that renban from box 1 as that forces another renban to place 6 into one exact row to forcing 6-s location pretty much over entire field.
27:41 for me, solver 2171. Nice one, I like how the mist lifts at the end :)
Yeah really cool touch!
A trick that I used repeatedly here was finding the cells that can see every cell of a longer renban, and eliminating the required digits from the renban from those cells. For example, for a while you had "459" pencilled into r7c4 and r8c7, and you knew that one of them had to be a 5. That meant that r7c789 and r8c456 couldn't contain a 5. That could corner mark a 5 into box 8, and reveal a 14 pair in row 7, which then bounces back into box 8. There were a few other times this type of non-conventional elimination helped speed my solve along.
My time today was 14:02, solver number 2199.
Clever!
I need to watch the video because I'm not sure how you would solve this without that technique which I used continuously throughout the solve
54:52 here. Struggled quite a lot, but I had to support Gandalf!
He can come handy!
41:01 - Happy with that.
The clues were hidden in the mist…