PPGS Lesson 5.8 | Aerodynamics: Turning Flight

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  • เผยแพร่เมื่อ 26 ธ.ค. 2024

ความคิดเห็น • 21

  • @muhammadmasterminders
    @muhammadmasterminders 2 ปีที่แล้ว +4

    It can't be any better than this with Mike Thompson! He's so natural and makes learning very easy

  • @Afghan-pilot
    @Afghan-pilot 10 หลายเดือนก่อน +2

    Thanks mike you makes easy to learn

  • @rapinncapin123
    @rapinncapin123 5 หลายเดือนก่อน +1

    This is some great instruction

  • @Hasan-tu6mb
    @Hasan-tu6mb 10 หลายเดือนก่อน

    Thankss Mike

  • @DanieleCaputo-g7d
    @DanieleCaputo-g7d 21 วันที่ผ่านมา +1

    The Elevator!

  • @jason401.
    @jason401. 2 ปีที่แล้ว +2

    Subscribed!

  • @alexormulea
    @alexormulea 2 ปีที่แล้ว +2

    I'm in

  • @theminertom11551
    @theminertom11551 ปีที่แล้ว +1

    At 4:23 the explanation becomes confused. Yes, the horizontal component of lift turns the airplane but it is the vertical component of lift which keeps it going in level flight. At 4:54 you state that it is the elevators that create the extra horizontal lift in order to maintain level flight. The elevators create a vector in the opposite direction to the resultant load, as is depicted in the picture that you show but that "new" vector contains both a horizontal and vertical component. While the horizontal component of the vector causes the turning centripetal force it is the vertical component keeps the airplane flying level. th-cam.com/video/7tWOyOu-QG4/w-d-xo.html

  • @kdr955
    @kdr955 7 หลายเดือนก่อน

    In your diagram the “horizontal component” opposes “centrifugal force”.
    These forces are equal and opposite, cancelling each other out.
    Your aircraft wouldn’t turn, it would fly straight ahead.

    • @daffidavit
      @daffidavit 7 หลายเดือนก่อน

      The wing is in "balanced" flight with respect to an air mass. Not with respect to the ground. Thus it turns in the direction that the wing is bank because lift it forcing it to turn in that direction. Centrifugal force is a "resultant" force created because the wing is turning. Because its "balanced" the wing maintains a constand "G" in the balanced turn depending on its degree of bank. If the turn were unbalanced, the wing would increasingly accelerate in the turn creating increasing "Gs", as if pulling back more and more on the stick in a fixed banked turn. Also, since the wing is not flying with respect to the ground, although an observer on the ground might think so, it's detached from the ground, so the oncoming air is at the same airspeed along the entire span of the wing. Thus, both wingtips are flying at the same airspeed in a level constant banked turn, contrary to old legends that die hard. But that's an argument for another day.

    • @kdr955
      @kdr955 4 หลายเดือนก่อน

      @@daffidavit Aviation word salad.

    • @daffidavit
      @daffidavit 4 หลายเดือนก่อน

      @@kdr955 Then why don't you try and explain where the center of a constant altitude backed turn is in your own words since you seem to have the answer?

    • @kdr955
      @kdr955 4 หลายเดือนก่อน

      Everyone is better off just not watching these TH-cam “instruction” videos.

    • @kdr955
      @kdr955 4 หลายเดือนก่อน

      There’s no vetting or quality control to these videos. Any jackass can call himself an “instructor” and publish garbage.