I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change! Anyone Please help me to understand why sir told that kinetic energy will not change?!
He was just talking about the basic equation of Hamiltonian. The formula for KE remains same but PE changes as we are no longer assuming nucleus to be a point charge
He knows that. He's just using a simple model to get a rough estimate. I'm sure he will complicate things slowly and slowly and eventually add effects due to nuclear forces
Physics Lover I just want to say that we can't assume validity of Electrostatics inside nucleus. Since Nuclear force is a different kind of force we need not assume the form of electric field as we have in Electrostatics. Because Quantum effects become significant at nuclear radious I don't think we can assume validity of Electrostatic potential which is valid for large length scale.
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change! Please help me to understand why sir told that kinetic energy will not change?!
The only reason I can think of is the common one usually given when things are not very clear. That it’s more energetically favourable. Since the data is experimental we can’t even argue for a different possibility. We found the nucleus this way actually. And if you see since nuclear forces are short ranged and charge independent any orientation can be justified. Nature chose this one as the most favorable one and of course there are other forces acting as well which might have contributed to this.
Sir you said that nuclear force is short range force thats why , the nuclear density is all most same near about the centre , but its is not valid answer beacause it not mentioned any where that this short range nuclear force is produced only about centre not near of boundary . So my answer for this question is non central nature of yukawa potential , If I am not correct then please explain .
Indeed but here sir is just doing rough estimate. For rough estimate we can consider this: As we see density is uniform rather than high density towards the center that means there is not any center of attraction at the center. Means that each parts have the attraction but they are short ranges . Like each have a center of attraction. So the density can't be max on some places rather than others. And they are almost distributed. This is just a rough explanation . This lecture series is developing as we have developed historically.
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change! Please help me to understand why sir told that kinetic energy will not change?!
@@youtubeshortsviral1361 i dont remember to much but i think because there is no r in the expression. I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change! True. But in that context he is not talking about a moving electron, he is considering a situation where we consider the nucleus as some spherical distribution not a point charge.
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change! Please help me to understand why sir told that kinetic energy will not change?!
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change! Please help me to understand why sir told that kinetic energy will not change?!
Awesome the way He remove the error😍😍
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change!
Anyone Please help me to understand why sir told that kinetic energy will not change?!
He was just talking about the basic equation of Hamiltonian. The formula for KE remains same but PE changes as we are no longer assuming nucleus to be a point charge
sir because nuclear forces behave differently we cant make the assumption of electriostatic potential inside nucleus (37:50)
He knows that. He's just using a simple model to get a rough estimate. I'm sure he will complicate things slowly and slowly and eventually add effects due to nuclear forces
the effects due to nuclear forces will not be there as there is no effect of nuclear force on electron.
Physics Lover I just want to say that we can't assume validity of Electrostatics inside nucleus. Since Nuclear force is a different kind of force we need not assume the form of electric field as we have in Electrostatics. Because Quantum effects become significant at nuclear radious I don't think we can assume validity of Electrostatic potential which is valid for large length scale.
@@physicslover9227 I was saying that electron will not be affected by nuclear forces since nuclear forces do not act on electrons.
@@abrarfaiyaz6503 आई सहम
Very impressive.
Not 10^(-15) fm it is 10^-15 m or 1f.m
Yes 10to the power -15 m =1fm
Crystal clear.
Very helpful... Thanku sir 😃
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change!
Please help me to understand why sir told that kinetic energy will not change?!
sir is this useful to net exam
What is the diffusion layer
26:25 why then the distribution is not same everywhere? Why it is less in that 4.6a region?
The only reason I can think of is the common one usually given when things are not very clear. That it’s more energetically favourable. Since the data is experimental we can’t even argue for a different possibility. We found the nucleus this way actually. And if you see since nuclear forces are short ranged and charge independent any orientation can be justified. Nature chose this one as the most favorable one and of course there are other forces acting as well which might have contributed to this.
Sir a would be derived from theory we cant estimate it from the given equation...
Excellent
Sir you said that nuclear force is short range force thats why , the nuclear density is all most same near about the centre , but its is not valid answer beacause it not mentioned any where that this short range nuclear force is produced only about centre not near of boundary .
So my answer for this question is non central nature of yukawa potential , If I am not correct then please explain .
Indeed but here sir is just doing rough estimate. For rough estimate we can consider this:
As we see density is uniform rather than high density towards the center that means there is not any center of attraction at the center. Means that each parts have the attraction but they are short ranges . Like each have a center of attraction. So the density can't be max on some places rather than others. And they are almost distributed.
This is just a rough explanation . This lecture series is developing as we have developed historically.
at 37:12 i think it should be, E = (zer/4piR^3 epsilon-not) r^ ,
ah okay corrected at 41:57, nice catch sir
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change!
Please help me to understand why sir told that kinetic energy will not change?!
@@youtubeshortsviral1361 i dont remember to much but i think because there is no r in the expression.
I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change!
True. But in that context he is not talking about a moving electron, he is considering a situation where we consider the nucleus as some spherical distribution not a point charge.
At 0.28 it is in meter I think..
Can this video available in Hindi??
Oh my God what a lecture
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change!
Please help me to understand why sir told that kinetic energy will not change?!
there will be R^3 in denominator
thank you sir
someone had written these lectures?.. i need it
writing it
@@conceptsofphysics9610 would you send it to me when you finish it?
what is a?
It's useful of jee maind
Jee main
Ye jee mains level ka nhi h ye higher classes ke topics h ,bsc . physics.(hons)3 rd year me h hme ye topics
Nhi re
❤
Sir 0.1 P0 means it falls to 90% or it falls to 10%
manish khemnani of 10%
It means 90 % decrease in protons
Gm sir
I have one doubt, at 33:40 sir said that kinetic energy will not change, but why? I mean if electron is passing close to or at r=0 then it will change the magnitude or direction of velocity of electron and thus kinetic energy should also be change!
Please help me to understand why sir told that kinetic energy will not change?!
Me B. Bc. 3rd me hu mujhe
Hindi me please