Interpreting M+ Peaks in Mass Spectrometry
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- เผยแพร่เมื่อ 10 ก.พ. 2025
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Due to the presence of different isotopes of an element in a compound, the parents ions responded differently. How about the daughters ions? As the individual parent ion will generate different daughter ions of different m/z values.
Amazing explanation
Life saviour!!
I think you might mixed up methyl butane MS with pentane from the previous video. The MS looks more like methyl butane one or am I wrong?
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Sir if it happens that we dont have m+1 how can we determine the molecular formula?
thank you a lot
Plz explain what will be the relative intensity of m m+2 m+4 peaks for 2Cl if present instead of Br
I have a doubt.
I agree that relative intensities of molecular ion peak involving both Br isotopes should be same.
The doubt is that why this m+2 peak. Is there for molecular ion peak and for other peaks such as base peak. Why don't we have M+2 base peak of same intensity
Pl. Answer
Thank you sir...
very helpful!
thank youu legend
I'm confused as to why pentane is displayed on the graph? I thought only ions were displayed? Pentane does not appear to have an electron removed. Can someone please explain??
I may be incorrect but the way it works aswell is such that sometimes the whole molecule just becomes an ion due to the way an electron hits the molecule (by just knocking off an electron whilst simultaneously not changing the molecule structure) that’s what they call the parent/molecular ion (in this case pentane)
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Thank you sir
But is there not a Chance that there are molekus that have 81br and 13C? So they weigh 125?
By the way thank you very much!
super
can anyone tell me that why secondary has more relative abundance than primary?
because its more stable
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Tnq sir
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why isnt the M+1 ion due to hydrogen isotopes? how exactly do you guys know m+1 peak is due to carbon isotopes?
I need answer to this too.
👍
Where 0.055 value come plz someone help me????
were trying to see how tall the M+1 peak is compared to the M Peak, so we mark our M peak as being 100% (it is 100% of its own height) we took the height of the M+1 peak (by viewing the vertical axis in this spectroscopy -in this case, we cant see it) and we divided it by the height of the M peak. That number is where the 0.055 is where that number comes from
5 carbons = 5 x 0.011 = 0.055 (Natural abundance of C-13 is 0.011 % ). Because the chance on 2 C-13 is negligible (0.0001%) this peak wasn't shown.
Why value pridict0.055......
It's a given value for each isotope...
Brilliant explanation
Thank you sir