Me watching and getting an add for math help :/ I ALREADY HAVE THE BEST HELP. They are trying to call videos like these "outdated" but math doesn't really get outdated
You can find the axis of symmetry (the vertical line that cuts the parabola into two symmetrical parts which also has the same x value as the vertex point) by finding the average between the two zeroes. Now you just substitute the x value of the axis of symmetry into the equation and solve. You will end up with a "y =" statement which is the y value of the vertex and since the axis of symmetry has the same x value as the vertex, you just use that x value for the vertex.
um so I watched the video from before and the 2 examples that you gave were ones with numbers multiplying with the x value on the second part of the standard form equation but this example at the start of the video has the x value by its self and you didn't show an example like that so if you want to know how to actually factor the equation use his video and another person video or maybe just another person video (sorry for the long comment)
I love you so much sir ;-; you have saved my brain from a meltdown
awesome!
I’m more confused, and I’m crying, but I’m not gonna dislike bc im not an asshole
i am
samee
me when math (all forms created by mankind outside of this video)
not excluding it unfortunately
Learned more in less than 5 minutes than in an entire math unit with a bad teacher, thanks!
Awesome with no ads whatsoever
Also if you want change the speed to 1.25x its worth it
Omg thanks he was talking so slow hehejjww
Such a sympathic guy im astonished
Thank you for making the function clear and fun 😊
thanks for savin me from all that confusion
Watch your video in class today help out a lot thx
Nice intro
Video also helped😀
You are a savior
Good video, helped alot
why doesnt nerdstudy have a video on standard form T_T i need it
Thanks a lot man.
Me watching and getting an add for math help :/ I ALREADY HAVE THE BEST HELP.
They are trying to call videos like these "outdated" but math doesn't really get outdated
how do i find the vertex point in a factored form of a quadratic equation?
You can find the axis of symmetry (the vertical line that cuts the parabola into two symmetrical parts which also has the same x value as the vertex point) by finding the average between the two zeroes. Now you just substitute the x value of the axis of symmetry into the equation and solve. You will end up with a "y =" statement which is the y value of the vertex and since the axis of symmetry has the same x value as the vertex, you just use that x value for the vertex.
Thank you :)
Who is here because your studying for ssat???? lol
um so I watched the video from before and the 2 examples that you gave were ones with numbers multiplying with the x value on the second part of the standard form equation but this example at the start of the video has the x value by its self and you didn't show an example like that so if you want to know how to actually factor the equation use his video and another person video or maybe just another person video (sorry for the long comment)
आप वीडियो कहां से बनाते हैं आप कहां के रहने वाले हैं
I love you bro
But what if an equation like this y=2(x-1)(x-5)
i have 1 iq and this is alien
this made no sense lmao
Math is like that. You eventually figure it out though.