Simplification of Boolean Expression Using Boolean Algebra Rules | Important Question 4
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- เผยแพร่เมื่อ 6 ต.ค. 2024
- In this video, we are going to discuss some more questions on simplification of boolean expressions using boolean algebra rules.
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subscribed, nice question and sample calculation, nice and easy thanks
Thanks brother they are really benefecial ...doing a great job ...thanks alot
Thank you for what you do
Excellent rendition
Thanks bhai
Thank you so much sir
Thanku brother
Yes
May God bless you
Thanks 👍
with the first question you could have just use 3 lines to solve the problem
thanks
great examples
sir first problem can be solved in 3 steps only.
thank u so much sir!
5:31 you forgot the A’ from A’B the solution is supposed to be
A+A’(B+D+C)
No he don't forget it...there was a rul that a+a'b =a+b
Even with your result there is absorption law to use, and it will be a+b+c+d
Even with your result there is absorption law to use, and it will be a+b+c+d
Darun
Nice
ABC[AB+C'(BC+AC)] please simplify this
Nice bro
Hi there
Low sir is Aand bar x + bar A and x is equal to bar Ax + Ax,,,, asap plsss🙂🙂🙂
my guy
I thought the absorption law is
x+xy= x. And x(x+y) = x. Why did he use the complement
x(1+y) banta hai not x(x+y) dekho gor se
I didn't get it also
Nice bro just upload it 1.25x fast please thanks
U have made error D should be under a bar