What is the answer for this question mam? Consider a 2000x2000 image I, where all pixels in the left half (first 1000 columns) are white and those in the right half (last 1000 columns) are black. A new image (Inew) of the same size is formed from I by shuffling the pixel locations. Let D denotes the Euclidean distance between I and Inew. What is the total number of possible Inew images? What is the average of D across all these possible Inew images?
Euclidean distance is minimum distance between two pixels. No matter whether they are black or white. To calculate Euclidean distance you need to know row number and column number of both pixels.
straight and clear explanation mam. Thank You.
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Fantastic explanation mam
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well explain THANKS
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good explaination maam
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Excellent Mam
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clear
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What is the answer for this question mam?
Consider a 2000x2000 image I, where all pixels in the left half (first 1000 columns) are white and those in the right half (last 1000 columns) are black. A new image (Inew) of the same size is formed from I by shuffling the pixel locations. Let D denotes the Euclidean distance between I and Inew. What is the total number of possible Inew images? What is the average of D across all these possible Inew images?
Euclidean distance is minimum distance between two pixels. No matter whether they are black or white. To calculate Euclidean distance you need to know row number and column number of both pixels.
Can you justify it completely mam?
For that question...