How to Make 12 Volt Auto Cut off Battery Charger Circuit
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- เผยแพร่เมื่อ 17 ส.ค. 2023
- #12vbatterycharger #batterycharge #autocutbatterycharger
How to Make 12 Volt Auto Cut off Battery Charger Circuit
-- Circuit In the video
How to Make 12 Volt Auto Cut off Battery Charger Circuit
This is a simple circuit that will effectively charge your 12V batteries without overcharging.
The circuit contains 2 LEDs and that will be indicating charging and full charge.
Required Components
1. 12V Relay
2. TL431A Shunt Regulator Chip
3. 1N4007 Diode
4. 1N5408 1W Diode (or 2A , 3A rectifire diode)
5. LED (Red, Green)
6. 2.2K Resistor
7. 470 Ohm Resistor
8. 1K Resistor
9. 12V Battery
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How to Make 12 Volt Auto Cut off Battery Charger Circuit
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Cheap and efficient circuit
Thanks
wow good one
Thanks
Good and very simple circuit
Yeah
Thanks and welcome
Thanks
Awesome
Soo simple
👍 Fantastic explanation sir, However I have doubt. I wanted to know what is the purpose of connecting input positive to left end of coil( diode cathode) and common terminal of relay. I have seen this same circuit in many TH-cam videos but none have explained this much in detail. I am really enjoying the content that you post in every video.👏🙏 Sir you are the best teacher so far to me. Also can you show how current flows in before and after battery charging.
Positive terminal is connected to one end of the coil and negative end will receive the coil thru the shut regulator that is cathode ( 3rd pin). The relay will switch on and off by the shunt regulator. The poitive end is connected to the center pin of the relay terminal. In one terminal red led is connected(Normally Open) and the other terminal green led is connected. In red led terminal we are conencting 1N 5408 and to battery. So current will flow from center pin of relay to normally open terminal and then to 1N 5408 and to battery positive terminals and negative terminal of the battery is connected to the negative supply of charger. Tl431 is independend of the charging current flow. It will only control whether to charge or not that is acutally decided by the resistor divider circuit.
Thanks you very much for loving my video. I will always try to keep the quality of my videos. :)
@@TechInsert Thankyou for your reply. The coil of the relay is energized, when by input positive and negative from Tl431 3pin and relay switches from NC to NO thereby red led lights up indicating battery is charged. Sir am i correct? Then again why is relay common pin is given positive input?
@@sridharkrishnappanavanerth3388 coil terminals has no connection with NO and NC. They have connection with common terminal only. If ur not connecting it to the common, then u will not get supply to the no and NC terminals and no charging will happen
@@tabm7644 Thanks Tabm . The reply is absolutely correct
@@TechInsert Thanks for this reply
Awesome project 🇧🇷😊👍great 👏👏👏 subscribed !
Thank u very much
How to modify this circuit for18 volt 21 volt and 36 volt
This is not a voltage regulator circuit. This is an auto cutoff circuit. If you are using a 6v or 12v or 24v or 36v battery, then just connect this circuit between charger and battery. This circuit will auto cutoff the battery from charger when the battery becomes fully charged. This will prevent overcharge problem and thus increase in life span of battery.
Thanks Uldane.
Do u need a voltage regulator using tl431
Good one and excellent
Thanks
Good one
Thanks
Awesome circuit
Thanks
Good job
Thank you
Very Nice
Thanks
Nice
Thanks
Very nice video good job but i want to do a circuit of 220v inputs charging circuit and outputs 12v circuit thank you
How much current do you want? or what is tthe ampere(Ah) of the battery and what is the type of battery I mean lead acid, Li-Ion that type?
Whether u mean transformer-less power supply?
This is auto cuoff circuit
Upko follow korke meine vo ek banaya hai! Sab kuch thik hai lekin voltage adjust nohi hoga ! Ish circuit ka ehi ek disadvantage hai ? Nohi to bohut hi simple circuit hai. Thank you.
@@anantalalsarkar3323 I tested this with 6V emergency light battery and 12V LIFe battery. Which battery you tried?
Nice simple auto cutoff circuit, can I use 1/4 watt resistors or 1/2 watt??
1/4 is enough
I have tried this circuit and it works well, but I have to give an input dc volts of 14.4 to auto cut off at 14.2 volts which is the max limit for charging my car lead acid battery
Which resistor should I adjust and what value for it to cutoff at 13.8/13.9 volts
Your reply will be appreciated
I can help u finding this, replace 2.2 k resistor with 5K or 10K preset in series with 1K resistor or replace 470R resistor with 220R + 5K or 2.2K preset. Then adjust the preset for getting the cutoff for 13.8v
😊😊
Thanks
Namaste sir this circuit is working for 30 amps current charger or 15 amps charger pse explain
Both, this is not checking the output current. This one is checking the output voltage that is the battery voltage. So you can give any current to this circuit
Very nice circuit
What is the input voltage to the circuit and what is the cutoff voltage to the battery
If I need to cutoff voltage at 13.8 volts which resistor and what value should I use in your circuit
Thank you
You have to provide 13.8+0.7 volts as input. When the. Battery is fully charged then 431 will disconnect the relay
Thank you for your kind reply & help, shall try what you advise
I tried with input at 14.45 V but it still cuts off at 14.2 volts
I think the voltage divider resistors have to be changed
Please Sir what changes needed to charge lithium ion battery at 4.2V?
Please Sir could you help me with the formula for calculating the resistors to set a particular cutoff set voltage?
This circuit is for lead acid battery. For lithium batteries I recommend using balanced charging modules. Example tp4056 module
Van we use it with lithium batter 12 v?
No only with lead acid batteries. Lithium need bms for charging
Pls I will like to show u a circuit.
What of if we want to add a 10k tremot to the base of the transistor to set the cut-off voltage we want the circuit to stop charging when the battery reaches the set cutt-off voltage.
And sir the center pin move from NC to NO and we use NO as the output positive terminal for the battery. But when we want to set the cutt-off voltage using the 10k trimpot the NO become dienergized; meaning that we will have no out put right, and now we connect a battery of 11v that has an actual rated voltage of 12v.
Will the circuite charge?
Note: that the NO has no power since we have set the cutt-off voltage
We can provide a trimpot and it will work. But I prefer to use a mfr resistor coz small change in value will affect the output voltage
@@TechInsert
Am confuse about something
When the circuit is energized the middle pin move from NC to NO? Which means NC will have no power at it terminal. When the cut-off is set is the middle pin not suppose to move to NC?
Or is it that the power will start flowing when the battery is connected and is below the cut-off voltage.
Pls explain
Can we give 20v input?
Yes, need to change the voltage divider values
Please tell me how much voltage give to charge
14.2v
Can there be any resistance other than 470 R
And what mean 'R'
470R means 470 Ohm .. that is a standard notation
But you mentioned only the battery cut off system, but if we have to take two wire for 12v led or router, then please tell us from where the wire should be taken. please its a requst🙏🙏
@@bmsth6333 This is a bttery charger with cut-off system. In this circuit we cannot give load. Let me try whether i can redesign it for load control. Not sure but ill try and let u know
@@TechInsert please 🙏
hello you
Ss
Este circuito no trabaja ya lo hice nada trabaja con los componentes que mencionan por eso doy manita abajo
Lo hice y funciona bien con la batería libre de mantenimiento de 6 V de mi luz de emergencia. Algo anda mal en el circuito que has armado. Revisa otra vez, por favor
This will works fine. Something might be faulty or misplaced. This is very simple circuit and u can check this easily. Check the regulator, i have seen it is becoming faulty easily when we hold the soldering to its terminal for a long time.
Low and high cutoff cricuit please send to me thanking you
Will try to make
How you doing this without how cut off
Voltage divider determines the cutoff voltage. 431 is built for it
Does that mean if we set the cutt-off voltage NO will have no power supply showing that the output has reach it set full voyage so no power will be supply to NO.
and will charging start when a battery bellow the set cutt-off voltage?
@@davidolamide2655 since it is in no it will always disconnect the battery from charging until and unless we disconnect and connect the input supply which is actually resting the circuit