Beautiful explanation sir, i was confusing how did u get the 5 metres because i self this since nine years ago after watching the video the second times i now recurred that moment is focused multiply perpendicular distance. Thanks 👍👍
Thanks for the great explanation. Just one question: Am I correct that the direction of the bending moment depends on the direction of the load? So you could say, if there is a load negative to the Y-axis (as in your video), the Momentum M_A is anticlockise. If the load is in positive Y-direction, M_A is clockwise?
@@Eurocoded Thank you, sir! Unfortunately, not everything has been clear so I commented straight under the linked video. Hopefully, you can help me there!
Hi Miss - 100kN force is acting downwards. Therefore, R_A reaction should be in the opposite direction (i.e. upwards). R_A is drawn as acting upwards. Hence, R_A is positive.
when you have converted the UDL to point load and placed it in the centre of its load span. Can it be placed at any point on that span? and be added to another point load that would occur at 'C'?
nicholas peak In this example, converted UDL is applied 5m from A. If you offset this point to a different location (example: to C) you will then need to counter the change in moment resulting from shift of converted UDL. Then you can add the converted UDL to another point load applied at C. Example: Imagine the same beam arrangement with another point load of 50kN applied at C. If you shift the converted UDL to C then the lever arm becomes 7m when taking moments about point A, resulting in 700kNm bending moment about A. But in reality, it should be 500kNm (5m x 100kN). Therefore, we can add an external anti-clockwise bending moment of 200kNm to counter the additional 200kNm (700-500) resulting from shifting the converted ULD. Then you can take the sum of two point loads at C as 150kN. I don’t recommend above method for this sort of beam arrangement. It would be much simpler to look at equilibrium with two point loads applied at two different locations. However, sometimes you will need to adopt above method depending on the arrangement.
If you are referring to the moment resulting from 100kN, it is not equal to 0 because the lever arm is not 0. Moment of a force = force × lever arm. In this example both the force and the lever arm are not equal 0.
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Thank you for the explanation! This was short and clear. Very helpful.
You are most welcome.
Thank u sir
Clear and effective explanation
You’re welcome 😃
thanks, clear and fast explanation!
You’re welcome 😃
Beautiful explanation sir, i was confusing how did u get the 5 metres because i self this since nine years ago after watching the video the second times i now recurred that moment is focused multiply perpendicular distance. Thanks 👍👍
How would you do this if the distributed load was a semicircle?
Calculate the area under the stress distribution and place the load at the centre of that area i.e. centre of the circle.
Thanks for the great explanation. Just one question: Am I correct that the direction of the bending moment depends on the direction of the load? So you could say, if there is a load negative to the Y-axis (as in your video), the Momentum M_A is anticlockise. If the load is in positive Y-direction, M_A is clockwise?
Tranefine you’re welcome. Watch this video where I have given a detailed answer 👉🏽 th-cam.com/video/6SJiDkYkOLs/w-d-xo.html
Tranefine let me know if the video answered your question 👍🏽
@@Eurocoded Thank you, sir! Unfortunately, not everything has been clear so I commented straight under the linked video. Hopefully, you can help me there!
Tranefine check out my comment under the linked video. Hopefully that will clear things up for you.
Eurocoded - it was definitely helpful, thank you!
Thanks for your explanation. Am I correct that the beam will fail when MA is greater than RA?
Question please where is the 5m coming from.... distance ya RA... haven't got tht please......
Shouldn't the reaction Ra force in the y direction be negative?
Hi Miss - 100kN force is acting downwards. Therefore, R_A reaction should be in the opposite direction (i.e. upwards). R_A is drawn as acting upwards. Hence, R_A is positive.
Sir at the fixed support A ,can we take RA support downward and moment MA clockwise. Please reply
Short and clear
Greetings Sir, have you done a video on frame reactions?
when you have converted the UDL to point load and placed it in the centre of its load span. Can it be placed at any point on that span? and be added to another point load that would occur at 'C'?
nicholas peak In this example, converted UDL is applied 5m from A. If you offset this point to a different location (example: to C) you will then need to counter the change in moment resulting from shift of converted UDL. Then you can add the converted UDL to another point load applied at C.
Example: Imagine the same beam arrangement with another point load of 50kN applied at C.
If you shift the converted UDL to C then the lever arm becomes 7m when taking moments about point A, resulting in 700kNm bending moment about A. But in reality, it should be 500kNm (5m x 100kN). Therefore, we can add an external anti-clockwise bending moment of 200kNm to counter the additional 200kNm (700-500) resulting from shifting the converted ULD. Then you can take the sum of two point loads at C as 150kN.
I don’t recommend above method for this sort of beam arrangement. It would be much simpler to look at equilibrium with two point loads applied at two different locations. However, sometimes you will need to adopt above method depending on the arrangement.
Where did you get that 5m
Thank you sir ,,
You’re welcome
Thanks
You are welcome
Sir please how did u have 5 meters
Why is moment not equal to 0 about A?
If you are referring to the moment resulting from 100kN, it is not equal to 0 because the lever arm is not 0. Moment of a force = force × lever arm. In this example both the force and the lever arm are not equal 0.
@@Eurocoded why Ma is CCW?
Are you sri lankan?
Hi Charitha - you’re the second one to ask on TH-cam. Looks like I sound Sri Lankan on my videos. 🇱🇰👍🏻
❤🇩🇿