You have no idea what u have just done ..am able to solve questions within seconds..not exaggerating..within seconds..I haven't studied the topic before but once I started with other TH-cam channels, it was difficult for me to analyse with the equation..my brain used to heat up...after ur video trust me am able to solve all kinds of problems, even data sufficiency questions 700 level questions within seconds...and I have not used the algebraic formula anywhere...you have made it so easy..I can't thank you enough ..thank you sir....
Hi Anushka! We are glad you found it useful. 😀 Stay tuned for more such videos. Kindly subscribe to our TH-cam channel here >> bit.ly/CrackVerbal-YT & press the 🔔 icon to not miss out on any notifications from us.
At 34:40 how does one say with conviction that the observed cyclicity and no means no for all such cycles? What can you please say explain the math behind it
Hi ! The idea is to detect a pattern! If the pattern holds true consistently for 3/4 data points - there must be a logic that creates this consistency - making it safe to conclude No as an inference ! For example in statement 1 here x = 12q + 6 = 6(2q+1) = 2*3(2q+1) 2q+1 is odd and so the power of 2 in x will be odd- thus x cannot be perfect square !
1:08:52 The task you are making up is different from the question before. Nobody is asking for the MIN value of d rather THE Value of d. You can obviously plug in different options for x and d before.
If n is an integer and n^4 is divisible by 32, which of the following could be the remainder when n is divided by 32? (A) 2 (B) 4 (C) 5 (D) 6 (E) 10 For this question how can we create list for n^4 ?
If the number of negative remainders there are makes the number even. Ergo, if you have (-1)^12, does that make the remainder a positive 1, no need to switch to the complement positive remainder?
@Rajesh Prasad, minimum possible remainder is 3. How? 64.12 * y = x, value of y should be such that, last two digits when multiplied by 12 should be 00, 12*25=300, so Ymin=25. So, 64.12 * 25 = 1603.00. 1603 / 25 = 64 Remainder 3
an easier way to solve such questions would be ( 64.12 can be opened up as 64+0.12 , and 0.12 is 12/100 and simplifying that would make it 3/25 , so the conclusions you can come up here is , the Reminder is a multiple of 3 and the divisor a multiple of 25 , )hope that helps
Hey Nesma, Its not 38 raised to a squared that is -1, its 38^a^2 divided by 13 that is -1, for say 39 divided by 13 is remainder 0 , and 38 divided by 13 is remainder of -1 or 6 , both are same , but its easier to use -1 here , does that make sense , let me know , and cheers ^^
@crackverbal_Prep how do you know at 1:02:00 that x=24? from the condition you can derive from x/d having a remainder of 24, is that x is 24, not that x= 24. right? what's the reasoning behind how you developed the problem?
x = 24 is the minimum value of "x" based on the condition given in the question. Let me explain! In the given question stem, it is mentioned that "x" is a positive integer and when divided by "d" leaves the remainder "24". If we write this using the division rule, we get x = d(divisor)*q(quotient)+ 24(remainder). So, when q = 0, we will get the minimum value of "x" which is 24. Hope this helps!
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Aditya, you have to get more videos out there man. You're the best quant teacher I've come across by far.
You are one of the best teachers I came across...Thanks a ton for this webinar
You have no idea what u have just done ..am able to solve questions within seconds..not exaggerating..within seconds..I haven't studied the topic before but once I started with other TH-cam channels, it was difficult for me to analyse with the equation..my brain used to heat up...after ur video trust me am able to solve all kinds of problems, even data sufficiency questions 700 level questions within seconds...and I have not used the algebraic formula anywhere...you have made it so easy..I can't thank you enough ..thank you sir....
What are brilliant session this was! Kudos to you Aditya!
possibly one of the best quant instructors I have come across ...
Amazingly explained, I now feel really well prepared for remainder questions. Thank you!!
Hey! We are glad you found it useful
Very comprehensive coverage and teaching method is just amazing. Thank you sir.
Thankyou! Glad you liked it :)
This video has been so helpful and easy to understand. Tackling such problems is a breeze now.
Hi Anushka! We are glad you found it useful. 😀
Stay tuned for more such videos. Kindly subscribe to our TH-cam channel here >> bit.ly/CrackVerbal-YT & press the 🔔 icon to not miss out on any notifications from us.
Amazing trainer
It's so clear to understand 😇😇thks sir 👍
At 34:40 how does one say with conviction that the observed cyclicity and no means no for all such cycles? What can you please say explain the math behind it
Hi ! The idea is to detect a pattern!
If the pattern holds true consistently for 3/4 data points - there must be a logic that creates this consistency - making it safe to conclude No as an inference !
For example in statement 1 here
x = 12q + 6 = 6(2q+1) = 2*3(2q+1)
2q+1 is odd and so the power of 2 in x will be odd- thus x cannot be perfect square !
best video on remainders
good webinar. was adjuvant fo me. number system really a ponderous part of gMAt test
Hi Ahmed,
We are glad you liked our session.! Thank you for your feedback.
Brilliantly explained!
We are glad you liked our session.! Thank you for your feedback.
1:08:52 The task you are making up is different from the question before. Nobody is asking for the MIN value of d rather THE Value of d. You can obviously plug in different options for x and d before.
If n is an integer and n^4 is divisible by 32, which of the following could be the remainder when n is divided by 32?
(A) 2 (B) 4 (C) 5 (D) 6 (E) 10
For this question how can we create list for n^4 ?
Awesome explanation..
We are glad you found this useful :)
If the number of negative remainders there are makes the number even. Ergo, if you have (-1)^12, does that make the remainder a positive 1, no need to switch to the complement positive remainder?
Thanks for explaining it very clearly. Quick question: x/y=64.12 then what is the remainder?
Rajesh Prasad 45...
We are glad you liked our session.! Thank you for your feedback.
@Rajesh Prasad, minimum possible remainder is 3. How?
64.12 * y = x, value of y should be such that, last two digits when multiplied by 12 should be 00, 12*25=300, so Ymin=25.
So, 64.12 * 25 = 1603.00.
1603 / 25 = 64 Remainder 3
an easier way to solve such questions would be ( 64.12 can be opened up as 64+0.12 , and 0.12 is 12/100 and simplifying that would make it 3/25 , so the conclusions you can come up here is , the Reminder is a multiple of 3 and the divisor a multiple of 25 , )hope that helps
Perfect ! Right?
Thank you for the amazingly well explained concept!
How does 121/4 give a remainder of 1?
1:30:13 16/5 is going to give me remainder 1 not remainder 6
yes thats right , a reminder can never be greater than the divisor ofcourse
how at 1:47:37 , 38^a^2 be equal to -1 I am confused sorry
Hey Nesma, Its not 38 raised to a squared that is -1, its 38^a^2 divided by 13 that is -1, for say 39 divided by 13 is remainder 0 , and 38 divided by 13 is remainder of -1 or 6 , both are same , but its easier to use -1 here , does that make sense , let me know , and cheers ^^
The rule of 5 or 10: unit digit became the reminder 47/5, then reminder should be 7... But it is 2, what am I missing, anyone?
Units digit 7: 7/5 - remainder 2
When 72/d gives remainder 22, d = 72-22 = 50. How do we get another value of d = 25 from this?
72/d , remainder = 22 implies, 72= dq+22, dq= 50. min value of 'd' is 25. so d can have 2 values, i.e 25 and 50.
@@dvsteja1 hey but min value of d could be 26,27 and so on till 71. Then why are divisor has be multiple of 25 always?
@crackverbal_Prep how do you know at 1:02:00 that x=24? from the condition you can derive from x/d having a remainder of 24, is that x is 24, not that x= 24. right? what's the reasoning behind how you developed the problem?
x = 24 is the minimum value of "x" based on the condition given in the question. Let me explain! In the given question stem, it is mentioned that "x" is a positive integer and when divided by "d" leaves the remainder "24". If we write this using the division rule, we get x = d(divisor)*q(quotient)+ 24(remainder). So, when q = 0, we will get the minimum value of "x" which is 24. Hope this helps!
you sound a looot like raj from the big bang theory