Thank you for this episode. I have short question whether my assumption is correct. One says that the time delay resolution is higher, the more bandwidth is available. But what is the relation behind that? Is it because the symbol duration is then smaller (Ts = 1/B) and you need the full symbol to get the delay time?
Yes, you are onto the right answer. Suppose you transmit a single pulse and listen to the echos. The shorter the pulse is, the larger is the chance that you can separate the two echos. The shorter a pulse is, the wider the bandwidth becomes. A Dirac pulse has infinite bandwidth, while practical pulses have a bandwidth inversely proportional to their duration.
@@WirelessFuture Some introductory session on capacity of current processors used at base stations can be very enlightening or any expected transitions to reconfigurable chips to accommodate ML for 6G systems. Sorry to be crude but I largely work on algorithm end.
![Ep 24. Q&A With 5G and 6G Predictions [Wireless Future Podcast]](http://i.ytimg.com/vi/gZyswMQASA4/mqdefault.jpg)
![Ep 24. Q&A With 5G and 6G Predictions [Wireless Future Podcast]](/img/tr.png)
![Ep 22. Being Near or Far in Wireless [Wireless Future Podcast]](http://i.ytimg.com/vi/7aVCtTgyMx4/mqdefault.jpg)
![Ep 36. 6G from an Operator Perspective [Wireless Future Podcast]](/img/n.gif)
nice to hear such scholars' discussion.
These kinds of podcasts play a main role in developing knowledge in the field of wireless communications thank you for sharing!
Very informative. Thank you very much for the podcast.
Thank you all for this episode. Although my research field is not concentrated on wireless localizaton, this is still very enlightening!
Thanks for useful episode. Could you please discuss about ways & challenges of implementation from sub 6GHz to 300GHz frequencies?
thank you all so much
Thank you for this episode. I have short question whether my assumption is correct.
One says that the time delay resolution is higher, the more bandwidth is available. But what is the relation behind that? Is it because the symbol duration is then smaller (Ts = 1/B) and you need the full symbol to get the delay time?
Yes, you are onto the right answer. Suppose you transmit a single pulse and listen to the echos. The shorter the pulse is, the larger is the chance that you can separate the two echos. The shorter a pulse is, the wider the bandwidth becomes. A Dirac pulse has infinite bandwidth, while practical pulses have a bandwidth inversely proportional to their duration.
Thanks for the series, wondering if hardware will be covered in any future episodes?
That is certainly possible. What is it more precisely that you would like us to cover?
@@WirelessFuture Some introductory session on capacity of current processors used at base stations can be very enlightening or any expected transitions to reconfigurable chips to accommodate ML for 6G systems. Sorry to be crude but I largely work on algorithm end.
learn model based processing ( classical method)) and data driven processing (i.e. machine learning and neural network) both are required...