ฝัง
- เผยแพร่เมื่อ 31 ม.ค. 2016
- View full lesson: ed.ted.com/lessons/can-you-sol...
Your expedition finally stands at the heart of the ancient temple. But as you study the inscriptions in the darkness, two wisps of green smoke burst forth. The walls begin to shake. The giant sandglass begins flowing with less than an hour before it empties, and a rumbling tells you that you don’t want to be around when that happens. Can you use math to escape the temple? Dennis E. Shasha shows how.
Lesson by Dennis E. Shasha, animation by Artrake Studio.
![พบรัก - INK WARUNTORN [Official MV]](http://i.ytimg.com/vi/n2wjOYVC38Y/mqdefault.jpg)
"ignore the duo"
proceeds ro set both on fire
🤣aaaahhaaaa
copy
Rin it’s at 3:29
Instructions unclear, ignited them instead
“to”
"Ignore the duo"
*burns duo with torch*
Ignore the duo, ignite the duo. Same difference.
thats how you ignore people, you burn them
I liked all four of these, They were really funny.
Free fire squad with you friend in a nutshel
i know how to ignite them!
*BURN THEM AT THE STAKE!*
wait you said ignore? i thought you said ignite....
Step 1: check if the curse has green eyes
Step 2: compliment their eyes
the altar does though
This is so overused ngl, it was funny at first but not anymore
@@milkimusic6683 green smoke, green eyes, I see a connection
Alright, I'm taking your eyes until you can behave and learn how to use them
They do lol
Me: Dennis, did you find the exit?
Dennis: Ozo.
lol I remember this
Too bad you still don't know what that means
@@Boilermakers270 frrrrr I wanna know so bad😭
The nostolgia 😭
UwU
Why are all these riddles always set in deadly gruesome situations. Give me a riddle about serving cake to children at a birthday party for once.
Chuuey lol
But you have 10 cakes, and 9 are poisoned, and 1 is safe. You must find which cake is safe in under 30 minutes or the children will explode.
Chuuey the mind works better with greater stakes.
We need to raise the steaks
Men surpass themselves in critical situations.
There's another solution. If you just tell the group to NOT come back if they find the exit (regardless of how you split it up), you could just notice who never came back when you return and go down their path. This works because you said the possessed members only have their "communication" hampered, their actual actions (Like, leaving the cave), are supposedly kept in tact.
My thought process is that the two liars actions are not influenced by the curse, only their "communication". I am trying to override this issue by turning an action into an inadvertent communication.
but image there is a trap in only of the tunnels and they die or something? this way is guaranteed
Cucas 360 I don't think the way mentioned in the video is guaranteed if there is a trap in one of the tunnels. I don't think that variable was accounted for. Maybe I'm wrong.
Genius
+Cucas 360 In fact, now that I think about it, the method in the video does NOT work if there is a trap in one of the paths. The criteria for solving this riddle was "ensure you ALL escape". If there's a trap and any of them dies, then not everyone escapes.
Another solution would be to agree that the group which finds the exit just walks out, then the rest can see which path no one came back from since he said "the curse ONLY affects their communication" therefore not their movement
that was my conclusion as well
Communication can be non verbal
I am *unreasonably* proud of myself for figuring this one out.
Step 1: confirm you have green eyes.
Step 2: ask the spirits if you can leave
Findlay Upward A-HA-HAAAA
Wrong Riddle plus u don’t have green eyes
"If nobody comes in 15 minutes we're legally allowed to leave"
Findlay Upward Nice other riddle reference Ozo
Ops wrong riddle !!!
This is why you always bring milks for your students. Milks can cure any potion effects.
Hahahhahahaa minecraft
Lol Minecraft
yes
Thank you for existing and making good jokes. I needed that
Lol
This riddle needs a sequel about the other expedition!
That'd be nice.
I guess there is an easier way:
As the curse only affects the communication the lead the leader can split the group in 2,3,3 and ask them to find the exit. And tell them that the group which finds the exit has to make 1 person stay at the exit and the rest should come back. In this way the group which has the missing person has found the correct exit.
*affects
Its correct but not exactly easier
Just send people out in groups and tell them to not return if they find the exit.
+Anastasia Shveytser (AnastasiaSh) but the possessed ones are only affected by communication not by action
+Anastasia Shveytser (AnastasiaSh) There is no 5th exit, there are only 4 exits + the path the artifact that you all just came from.
that was also my solution. Discard one of the doors, make 3 groups of 3 persons, if any of the groups finds the correct one they should go and wait outside as a signal. If all of them return, they should all take the fourth tunnel.
doesnt work because what if they lie and dont come back
Yeah but then two students might suicide by not coming back. Or two might come back from different tunnels. Not coming back when it isn't the exit or coming back when it is would be the equivalent of lying. So as long as u go one two three three, this would work, but two students might die.
you know you're not cursed, but why would everyone trust you?
why would they know about the curse?5
oh, no one else saw them knock the thing down or whatever?
Simeon Gavalov They didn't see the inscription saying the temple is cursed.
Simeon Gavalov cuz they dint know about any possessions so
*you're
My dad came up with another solution: As there are 9 of us in total, 3 go into each door (you also go into one with other 2 poeple) and the last door you can know through the process of elimination.
So many lazy people
This won't work though.
The cursed students may lie only sometimes, so we have no idea whether they are lying or telling the truth at any given time. If only one student of either trio is arguing with the other two, does this mean that:
a) he is cursed and is lying, while the other two students from the trio are telling the truth (and the other cursed is in a different group) OR,
b) he is not cursed, is telling the truth and the other two from the same trio are the cursed, paired together and lying?
It would be impossible to determine and we would have two doors to eliminate, which means our chance of survival would be 50 / 50. (Which is easily solved if we pair together the two students from our own trio and we go alone.)
@@DISCO-munication 2 groups of 4 would also work.
@@mehrunez4838 It doesn't work. At 2:21 they explain why two groups of four won't do the trick.
My dad had the same idea lol
Lesson learned: actually pay attention to who bumps into something or you won’t be able to trust anyone but you.
Also keep a map.
Plot twist: someone remembered the way, but they were cursed. If you asked them again they would say I did
Just keep flipping over the timer when it’s gonna run out lol
beeg smort
Brayn zise : Ultra Large
@@lurifos9576 lmao
just how do they flip that giant timer?
@@Jhanlie16 Good question.
The problem is, that you yourself can't prove too the others that you aren't the cursed one.
*to
And you were the one that read the inscriptions - the others didn't
Don't tell them about the inscriptions or you're all screwed
@thematiux t amogus
Doesn’t matter. They can apply the same logic to see who is cursed
@@superrooster18 No, because the leader could be lying about the tunnel he explored, and you don't have enough information to check if he is.
I was thinking that you can have everyone go their seperate ways but they MUST bring something from the outside of they made it outside, and it must be exclusive to only outside, so when we meet up, if one person from a group has something from the outside then I know that they aren't cursed. But if a group has none they found the altar.
Was my thought as well
I love this idea they could grab a flower or grass
@@rigidkiwilll1668 yeah
They are cursed and has the powers to create anything u said them to bring from outside 😢
I was thinking like what if you split into three and then tell them that if they find the exit, don't go back. So if 2 groups go back, we know that the path the other group took was the exit. And then if all groups go back, then the path you all didnt take is the exit.
TED comes up with the most creative riddles
What if one of the guys was trolling and lied even if they weren't cursed.
The Doich
Then they're an idiot and just killed them selves and their friends.
The Doich No one would be that stupid.
Then what if the troll stabs everyone and runs in the right direction.
Sorry, no trolls. This is a group of smart nerds. (Smart nerds who get an early deploma)
The Doich Where's the weapon?
Just run fast as fuck boi
Use code _ _ _ _
KEEM
Keemstar will in 3 minutes tops scout out all the possible exits
EenGamer that's what I'd say
Exactly
Nice puzzle. Solved it!
I'm never going back to that temple. I'm so glad I saw this video! We all got out safely.
Step 1: Confirm that all the students and yourself have green eyes
Step 2: Ask to leave the temple
LMAO
But they don't have green eyes
the dictator is back
Overrated riddle
I see this green eyes joke everyone but i dont get it, where is it from
3:14 *PLOT TWIST*
HE ESCAPES AND LEAVES THEM BEHIND
But then when the group return, they could go down the only path with no one standing by it.
or she, could be a she.
@@sarahsequeira9181 Or neither, could be neither
@@theteutonking3306 yea thats the easy way, tell them if they find the exit leave
@@theteutonking3306 it could also mean they died 😂
This feels like Among Us with extra steps
Red is SUS!
I literally have watched 15 of these, and I cannot figure any of them out
*C R E W M A T E*
*There is 2 Imposters among us*
*are
*impostors
Suddenly this is a relevant joke. Very good.
@@Hans5958 thank you for doing my job
@@Hans5958 isn't imposter correct as well?
@@ARandomSpace it's from 2 months ago, they made the joke when among us peaked. there is no "suddenly".
* the room begins to shake *
Me, laying down on the ground: hey you guys this feels like a back massager
Lol
u were 100% one of the idiots who bumped into the altar, but honestly, me too
hehe... nice one @Miller Blaylock.... lonely crab... :-]
*lying down
Love this riddle
Love how with every ted ed riddle we always come up with a loophole 🤪🤪🤪 we’re so smartttt
Ted-Ed: It takes 20 minutes to get to the exits
Me: it takes me 1 hour to get out of my bed
Draco Granger-Snape ikr
@Draco Granger-Snape simp
...
I know it's silly, but the tropey setups are such a nice touch for all these. Really gets me emotionally engaged to problem solve!
I only watch for the setups sometimes. Just makes ‘em a bit more interesting.
Alternate ending: You tell your friends about your plan and now you have friends
I love how the altar is secretly the symbol for pi
Plot twist:
You yourself get possesed and the whole group dies.
Yes.
Plot twist:they just had to ask the spirits to leave because they all had green eyes
Look up cross examined
The curse be like:
There are two imposters among us
lol
You know what to do: 3:30
Terrible joke
i like how 9 people went throught the tunnel but dont remeber where the exit was
I finally got one of these riddles correct lol
here's my answer:
as you know you're not cursed, you stay in the middle and you don't move. As the curse only affects your communication and not what you do, you tell everyone that if they find the exit, they leave. You divide the groups into 3, 3 and 2 and wait for all the groups to come back and you go down the path that the group which didn't return went down. This way everyone is saved
Would the rest of the students trust you that you aren't cursed though? All they knew is that you could lie to them and lead them all to a dead end.
@@nqh4393 from what i perceive from the video and see from reading other comments, other people don't know about the curse it's only you. Plus, we're the leaders of the expedition! they'll trust us for sure :)
This is really smart!
Isn’t there only 9 including yourself?
@@roejogan8683 yeah there are 9 people including us
You could also divide all groups into 3, including the trio you're in, and leave 1 path unexplored. This would create the same concept of answering with confidence for the students. If none of the explored paths show up as the exit, you know it's the unexplored path.
No you can't - I've explained PLENTY of times why that wouldn't work!
@@Inkyminkyzizwoz why
@@idontknowmuch3441 Because if one group came back split then you wouldn't know how many people in it were lying, which would leave two paths uncertain - that one and the unexplored one
@@Inkyminkyzizwoz There is no way for a group to be split. There is always going to be two people saying one thing in a trio. If no other trio is disagreeing then listen to the single. If not then listen to the two people.
@@SuperDestroyerFox No, because you don't know how many people in the split group are lying
First one I have figured out in my head.
My mind would never think of a plan that advanced in so little time
+Foxtrot2021 The real problem is that in real life you don't even know that there is a unique solution which brings you to the exit
+OZIWAN exactly
+Foxtrot2021 I got to it in 1 minute.
+Foxtrot2021 Indiana Jones will
Split them into 1(you)-4-4 or 2-2-2-3 or 2-3-4 and tell your students if you find the exit only one should come back, the other(s) stay outside, as the curse affects only communication and not survival instincts this will work without all that thinking :)
3:53
Next riddle: Find out who's arm got cut off.
Imagine if one of the two possessed student knew which exit was the correct but lied about not knowing lol
I love the thumbnails can you solve…. No teded I can’t. I never can 😂
“Don’t worry about the possessed students attacking or otherwise harming other students”
Like this is actually happening in real life
What he means is don't factor that into the equation. He's not telling you that you shouldn't be anxious about it.
Nuh uh this happened to my buddy Ed last year
The problem is that your other group members won't trust you to go explore alone.
If you don't mention the curse, it won't be a problem. Just assume the role of leader, split the groups of people into 3 and 2, and send them off, telling them to report back whether it is the exit or not. Of course, it's no guarantee, but people in a panic tend to divert responsibility to somebody else in dangerous situations (To avoid the risk of it being their fault if anyone dies), especially if there is someone willing to be a leader.
+Ryan Jewell What if the you meant all of you?
yeap, if you where the one bewitched
no because im pretty sure you were the only one to see the cursed sign, or atleast that was shown in the video. so no one else would know about the curse and accuse u of being possessed. if im right lol
You are the only one who knows of the curse. The 2 guys who were infected would have no idea about the curse. Only communication is affected by green gas. Not that they are possessed and want every one to die in there.So they have no reason not to trust you going alone.
Finally, an easy Ted riddle
One other thing you could do is just tell each group “If you find the exit don’t come back.” If the curse only affects communication it wouldn’t force the possessed to come back in and then everyone just takes the path that did not have a returning group (as long as you keep track of who went where). While there is a risk that something could happen to keep multiple groups from returning, that could still happen in any scenario anyway so the risk is not much different.
Communication can be non verbal, so would include things like that
@@Inkyminkyzizwoz But that would kinda tell who the cursed was then, since its only the cursed coming back
@@thebrazillianguytm2186 Not necessarily
@@Inkyminkyzizwoz It works just fine
If you sent 3 people to the exit and only 2 or 1 came back, that means they found the exit
And if all groups dint found the exit, you know what the Duo os the cursed one, so you can go where they went just fine
@@thebrazillianguytm2186 Not necessarily. The ones that didn't come back could be cursed and not found the exit
Me keeping this in mind in case I end up in a cursed ancient temple with my 8 colleagues one day
With a curse and also 4 hallways
@Kizaco 5 hallways
Well, you could just tell them not to return if they find the exit.
You said it only affects COMMUNICATION. This is MOVEMENT.
Returning studemts might lie about not finding the exit when they actually did
One Day I'll die The returning students will never find the exit if they do as he says and the curse only affects communication so they will.
9999 IQ
Yes thats what I thought at first
would lead to a coordination problem with delayed/late groups
This is the first (and probably last one) I found!
This was one of the easier riddles, figured it out almost instantly. Still really fun tho!
"don't worry about the possessed students attacking or otherwise harming the others. This curse only affects their communication." WORDS CAN HURT TOO
Sadly I don't think I have the brains to figure this out in an hour, let alone under stress and panic. I'm sure Indiana Jones can haha
It's even worse. 60 minutes - 20 minutes exploring - 20 minutes reporting back - 20 minutes escaping = 0 minutes thinking. We'd all lose.
+George Cataloni "it would take ABOUT 20 minutes" you could be quick
Abel Judah If we're gonna be technical: "less than 1 hour".
+George Cataloni well, i guess we'll never know how much thinking time we really have
+boy638 I'm sure they can. I solved it in less than 3 minutes. They are at a temple, so I'm guessing they are smarter than me.
The 20 minutes time for using the exit path was for a "fast pace". This is a life or death situation. They will run like race horses.
These are good riddles
Really need to get out there
how did you not SEE who was possessed?
Michelle Vanessen
its a smoke + they only have torch to lit up the place + the building was quaking
Rowlet 01 I wonder how they did not notice GREEN smoke
Theyre all blue
Michelle Vanessen everyone's except you is an identical twin,otherwise i cant explain why you cant tell who's cursed.
They were possessed as you studied the inscriptions.
I was thinking you could just send 3 groups of 3 down three of the unknown paths. Tell the students that if they find the exit, just go out and don't come back. If when you arrive back in the center all or part of a group is missing..the path they took is the exit. If everyone is present, the unexplored path is the exit.
Nice
+Ravinian That's exactly what I came up with.
+Ravinian that actually makes a lot of sense
That's pretty smart
+Ravinian That wouldn't work because the cursed person could just stand at the end of the dead end path and now you wouldn't believe the people returning that it it was a dead end.
i didn't think about the fact that they would argue, and just i just firgured i could send 3 people down 3 hallways, and if none of them are the exit, the one that went unexplored must be it.
Laziness is often the path to despair. You have the time and the resources. Assuming is dangerous.
@@starsiaeve4649 wha-
Won't work because the possessed students only MIGHT lie! How many more times?
Pretty easy, I finally figured out one of your riddles my self.
And as you are done thinking
THE SANDGLASS HAS ALREADY FLOWED
If I found the exit I'm wouldn't be coming back
I said the exact same thing
and im distracted by their fingers
Call up the dean and tell him I need more grad students. Yes, again!
this one has so many valid solutions
No it doesn't
A lot of people are STILL suggesting three groups of three, so let me explain yet AGAIN why that wouldn't work:
The possessed students only MIGHT lie, so if only one group is split then you won't know whether there are two people lying in it or only one, meaning that there will be two pathways you're not certain about - that one and the unexplored one
There seem to be an awful lot of people asking what happens if both possessed students are in a trio and both lie. If that's the case then that trio will give an inconsistent answer, so that will account for at least one of the possessed students, meaning that both other groups will have at least one student that isn't possessed and will therefore tell the truth, and as those groups' answers will be consistent you therefore know that they're telling the truth
Good explanation. That's a long sentence there btw.
Basically, if one trio argues but others are consistent, both cursed would be in the trio.
If only one cursed was in the trio, another group would argue, in which case you can just trust the majority.
@@SacsachCCABP You're forgetting that the possessed ones only MIGHT lie, but the rest is correct
Or... since the curse only affects communication, tell whichever group that finds the exit to not return. And afterward just go to the tunnel without returning people?
谢昊天 actually a good answer.
I commented the same thing, before I saw your post. Brilliant minds think alike ;)
Thank you! I thought the same thing!
ion ion it only affects communication
ion ion you have to be within a group or you won't be trusted. There are four options and nine people, so yes, one tunnel is unexplored, and if a group has two liers that return, the thirs in group leaves and that tells everyone there's the exit.
I finally got one!
Yay! Got this one right after miserably failing the prisoners hat riddle🥴
same
Cute emoji.
Couldn't you just tell the people who find the exit to escape? Then when you all came back the people who didn't come back would let you know that they escaped and that that's the right path.
But if the liars were the ones who found the exit they could come back and say they didn't find the exit
they only lie when communicating, therefore they wouldn't come back.
But if everyone else said they didnt then you can know they are the two cursed ones because you know you aren't currsed
What if those two cursed students got paired together and came back saying they didn't find the exit. Or one of them was cursed and lying and the other one was telling the truth but u wouldn't know! Then u would have wasted time and probably none of you would make it out. Just my thought but that was pretty clever though😋
Miss Panda! The thing is this is a theoretical problem so everything is exact. Your always running at the same pace and no one is too scared and it isn't realistic. It is like a math problem.For example "Jeremy has 679 watermelons he sells 403 how many does he have left?" In a math problem it's 276 but in real life it is Why the fuck does he have 679 watermelons
What if the other students think you're the possesed one and want to go with you to make sure you aren't lying?
they dont know about the possession
In which case you can just leave them there to rot in hell for all you care...
you go with the group of two, do the same thing and then use process of elimination to figure out the forth tunnel
the Problem with testing 3 doors is you Need 3 sure "truths" (true sayings about a passage). if there´s a disagreement in just one of the gr.of 3 you never know if there´s 2 liars or just 1. i´ve tried such poss. too, but you Need 3 sure truths in any way wich leaves you at Groups of three or five and above and yourself for any door you wanna check if you wanna afford the possibility of a lie. Going with the others still gives you a poss of a lie only checking 3 doors wich leaves you at at best 2 sure truths with the System ( you might fall on 3 sure truths in a given case but the System doesn´t assure you of that)
My face is too disturbing for spirits to enter it.
These riddles are so sick
"trust me, im not possessed so ill just check out this one on my own" sounds like a great way to get everyone to not trust you
I love these riddles. Never stop doing them.
"None of this matters if you're lucky enough to find the exit yourself."
So long students, good luck!
Plot twist: you find the exit and dich everyone.
I would just look in the tunnel and see if there is an exit for each one
I’m rewatching all these riddles for the nostalgia and remembering when I watched this riddle a few years ago then couldn’t go to bed 👺
My 4th grade teacher would let us do these riddles as a warm up. :)
nostalgia?? they are not old :D
Same.
5 years is old mate
Yeah this one was kinda creepy lol
Me: *reads title*
Also me: “probably not.”
But I still watched it anyways.
Yet here you are...
FIRST ONE I SOLVED YET! Yay!🎉
Bump into the alter, Wow,fun.so exciting
wouldn't u run out of time by thinking?
You compensate by running faster
@@shishirgurung4427 then why not run faster in the first place
2:06 You literaly have 3 seconds to think
It would take around 5 to 10 mins to get the answer depending on the person
not after watching this video
But how would the 8 students know they can trust you?
You are the only one who saw the curse notice
+Abel Judah but how do they know,what if they thought you was lying because remember all 8 of them didn't see it.
+Science Power you don't have to tell them about the curse
+Abel Judah kool
You can lie to them and not tell them about the curse.
The first test, solution come up to my Mind in just a millisecond..
I was stuck for really long in the wrong approach of sending 0 students on one path, hoping to somehow get good enough of a ratio of truth-tellers in the other paths. Eventually it dawned on me that when I've sent 4 or 5 students to one path, splitting the remaining ones in the other two paths in any way is equivalent to sending all of them too on another single path, you cannot determine which of the two ways to go when there are 2 possessed among them. That completely ruled out sending 4 or 5 on a single path, making 3 the viable maximum per path.
I think there are three solutions to this problem. The first, obviously, is above, but I think there are two more:
1) Split into three groups of three and try three of the four paths. Tell them if they find an exit, go ahead and escape. If everyone returns, the exit must be path no one checked. Since three people are in each group, at least one person would escape if he found an exit, regardless of who he's paired with. If fewer than 9 people return, you know one of the explored paths is the exit. You can safely take the path fewer than 3 people returned on. If three are missing, all three were not cursed. If two are missing, then one was cursed and decided to to return to deceive the others, and you can ignore his testimony. If only one is missing, the two that returned are cursed, and you can ignore their testimony.
2) Split into three groups of three and try three of the four paths. When everyone returns, if there are two disagreements, then the cursed individuals are in two different groups and you can side with the majority in every case. If the majority of one group found an exit, take that path If the the majority in all three groups failed to find an exit, take the unexplored path. If there is only one disagreement, then both cursed individuals are in the same group, and you should side with the minority. If either one of the two consensus groups or the one minority found an exit, take that path. If they didn't, take the unexplored path.
Edit: I acknowledge the fault in my second solution below.
Scott Simmons 1) if only one returns you can't know whether the other two are telling the truth. So if they say, it's the wrong path, they could either be lying and the third one escaped or they are telling the truth and the third one is cursed.
I think you forgot that they could also be telling the truth.
Julia Hörmayer Sure, I don't know if they're telling the truth, but I don't need to know. I know that one didn't return, and that shows that this path is the exit. If it weren't the exit, then all three would return. He says that the curse only affects their communication--that is, they would lie. It does seem that the problem assumes that they would do as they're told.
However, if we allow that the cursed ones may hide to trick the others and deceive them, then I think we're still okay. If one returns and says "There's no exit on this path the other two are hiding," then if true, everyone else who returned would agree with the others in their respective groups, and we could safely identify the two who didn't return as cursed. If two return and say, "There's no exit on this path, the third is hiding," then if true, there would be at most one disagreement, and the truth tellers would be in the majority. In effect, that altered scenario 1 becomes almost identical to my scenario 2. The difference would be there are two ways to deceive--either by returning and lying or hiding.
Scott Simmons You're right I forgot about the part where it affects only the communication.
If it wouldn't though and one would come back and say that the other two in his group were hiding, he could also be lying.
Julia Hörmayer Yes, but now you have me rethinking my #2. Since it's possible one cursed person might decide to tell the truth, if there is only one disagreement, it could be that both cursed people are in the same group, or it could be that one cursed one is in that group and the other is telling the truth in a different group. If that's the case, then we would need to side with the majority, even if there's only one disagreement. I think I may need to retract my second solution. If there's only one disagreement, I'm not sure you could determine what the truth is, since only 3 of the 4 options were explored.
0:48 showing middle finger to the ceiling xD
Lmaooooo
This is why I will bring a paper to an abandoned temple so I can write it down just in case this happens
Me drilling through like a smartie
"Now... Which one of you named Loki?"
"Ahhh...Me?"
"Alright you can't be trusted"
🧐
Yes.
Do what 3:30 does
2:00
TedEd: Only effect their communication
Me: so would they swear for no reason?
Or talk in their ancient language?
Yayyyy I guessed another riddle by myself! 😊
This is the only riddle I've gotten correct so far. Feels good. Hahaha
3:30
Ted ed: “in either case ignore the duo”
Ted Ed: burns duo
Everyone go in a trio into the three paths. If all three don't agree then go in the passage no one went into yet and all leave together
that was my solution too...
but if there is two liars in the same group, there will be only one person saying the truth, right?
since the other groups all are honest, they wont be disagreeing within their own group.
ir there's one liar, there will be two groups disagreeing with each other.
so you can still tell where the liars are.
Say we used your method, what if both liars went into one trio, none of the trios found the exit, which is a 25% chance, but both liars said they'd found the exit? The two trios consisting of truthful people would say they hadn't found it, so you'd follow the trio where the majority said they had, and you'd go down their path and find a dead end. We're looking for a solution that works 100% of the time, and yours is not it.
Luke Davies
shit... right... thanks! i didn't think of that...
+Luke Davies not true bc if the group with the two possessed people said that it is an exit then you would know that that group had two of the possessed people because otherwise one would be in another group arguing with that trio
Isn't this riddle very relatable to AMONG US?
The cursed students are impostors.
Amazing
My thought was that u divide into 3 groups of 3 people and then u r sure that 2 cursed wont be alone
If noone found the exit is in the unknown path
That won't work because you don't know if the possessed will lie or not for example if a group of three come back and one group is arguing you will assume that the 2 who agree are both the possessed where as a possessed might be agreeing with a non possessed
@@ngjon but couldn't you change your anwser (in a sarcastic tone of course) if that happens so you could signal the other groups that you were right and that they are the liars, because there would be no reason for a second person to change their anwser, and that the ones possessed can only lie or tell the truth so they shouldn't be able to think of something like that (hope that made sense)
NGJon that’s a good point
@ngjon in short, once you have 2 contradictions, you can deduce everything else from there. In the absolute worst case, if you only have 1 contradiction, re-ask all groups until you find the 2nd.
Wait what if the exit is in the one without people and the cursed people are in a trio, then they both lie, so u trust them