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Is it because D-glucose’s hydroxyl groups are in equatorial position, so it is more stable in that conformation?
Exactly 💯
amazing explanation, u saved me once again!
I'm so happy to hear that!
What happens to the purple “H” that’s attached to the red “O” that attacks?
Good question! The red "O" becomes deprotonated in solution and loses that purple "H". It is no longer a part of the structure when glucose is drawn as a Haworth projection.
This really helps me thank u sm ❤
You're so welcome!
Is it because D-glucose’s hydroxyl groups are in equatorial position, so it is more stable in that conformation?
Exactly 💯
amazing explanation, u saved me once again!
I'm so happy to hear that!
What happens to the purple “H” that’s attached to the red “O” that attacks?
Good question! The red "O" becomes deprotonated in solution and loses that purple "H". It is no longer a part of the structure when glucose is drawn as a Haworth projection.
This really helps me thank u sm ❤
You're so welcome!