How to Solve Difficult Projectile Motion Problems (Angled Launch from a height)

This video goes over examples of projectiles launched at angles from various heights or launched to some height. These are typically harder problems in physics.

[@medicisounds1384]

So i tried it a slight different way. One that i find easier
I first Max Heigh Ball reaches using -- H= V^2 Sin^2(THETA) / 2g
After i got my Max Height of 7.15769 meters
I then used that to find TIME. t= sqrt(2(H + h) / g
with this i got time of 1.2086 seconds
After i used this formula to find RANGE R= Vx t
Vx being V* Cos 37
My final answer was 14.4 m with roundings
Im still learning physics! But i just figured it out this way and thought it was easier for me
thank you

[@medicisounds1384]

I know my answer was off by 2 meters but hey is physics ever exact ;) LOL

[@HowToPhysics]

This is a totally acceptable way to solve the problem! When using sin and cos, error will propagate if you round the decimals so being off by 2m sounds reasonable.

[@kendrasweetheart2320]

What is another way to answer part c

[@mamudouconateh8308]

Thank you so much

[@HowToPhysics]

Glad I could help!

[@yin873]

for b, how do you know y = 0 rather than y-naught is equal to 0

[@HowToPhysics]

Great question! You can set your initial height to zero but if you do that your answer for the final height will end up being negative since it is below the initial height. That works but I prefer to use the ground or final position as zero so that when I find the initial height (y naught) I get a positive number. Either way works if you ignore the negative and just look at the magnitude of your answer. Hope this helps!

[@kotlin7554]

thx@@HowToPhysics

[@user-mb4or8ep8e]

Sir , which equations are you using ? can you please make a video of the equations used so that we can understand.

[@anzarv]

SUVAT.