Reciprocal Space 2: Condition for Diffraction
ฝัง
- เผยแพร่เมื่อ 17 ก.ย. 2024
- Physics of Materials by Dr. Prathap Haridoss,Department of Metallurgical & Materials Engineering,IIT Madras. For more details on NPTEL visit nptel.iitm.ac.in
1. The translated content of this course is available in regional languages. For details please visit nptel.ac.in/tr...
The video course content can be accessed in the form of regional language text transcripts, books which can be accessed under downloads of each course, subtitles in the video and Video Text Track below the video.
Your feedback is highly appreciated. Kindly fill this form forms.gle/XFZh...
Sir, Thank you so much for your wonderful lectures. It is hard to find people like you who teach the concepts so much in detail in the UG/PG level. Your sincerity and dedication will definitely pay off.
This person has enough potential to write a renowned solid state physics book.
+Nidhin Sathyan He wrote ir already. Physics of materials: Essentials concepts of solid-state physics. Dr. Prathap Haridoss
the way prof. has explain its too good any body can understand thanks a lot prof who presented this topic in very simple manner
Maharshi Ray I think the lectures are excellent, they helped me understand the subject. If you want you can always watch them on vlc player and speed them up to 1.5x or 2x ;)
you can do that (x1.5) here
Best! Nptel lectures are much better than any other online platforms.
for p=3 q=5 r=7 if we take h=0.5, k= 0.5, l= Any integer , we will get
hp+kq+lr = integer
Yes !.. Good question.. how then the hkl values must be always intergers?
This is amazing!
I really appreciate your lecture sir. It helps me a lot to understand the concepts of solid state physics which is my major subject this term.
Nicely Explained! I appreciate the effort!
Thanks a lot. I was looking for a basic lecture like this.
41:41 why should h, k, l be integers only? For example, if p, q, r are all even numbers, and h=k=l=0.5, then also we get the sum as integer value.
Because hp + kq + lr should be an integer regardless of the values you choose for p, q, and r. Suppose you choose h = k = l = 0.5 and p = q = r = 2, but I can now choose p = 1, q = 2, and r = 2 and hp + kq + lr won't be an integer anymore.
In order to ensure that hp + kq + lr is an integer regardless of the values chosen as p, q, and r, the values of h, k, and l should be integers.
Very helpful Lectures.....Thankyou
It doesn't sense that at 41:30, where he says h,k,l must be integers for the sum (hp+kq+lr) to be integer where p,q,r are integers. This is not a true statement because for all integers greater than 1 let h=1/p, k=1/q, l=1/r then we have (hp+kq+lr)= (1+1+1)=3 which is at integer. Yet clearly we have chosen non-integer values for h,k,l and the statement remains true. So his conjecture is incorrect, h,k,l do no have to be integers for the sum (hp+kq+lr) to be an integer.
Quite late here but it might be useful for others watching the video. sum(hp+kq+lr) is an integer for ANY integral values of p, q and r, not just one set of (p,q,r). Thus, each of (h, h, l) have to be integers.
@@srikanthmnb thanks bro,great job
owesome thank u
Thank You :)
awesome'
two problems
1. Path difference has dimensions of area
2. if 2a vector is taken in real space its position in real space will be 1/(2a) in a direction perpendicular to the a vector
so I will have a non integer multiple of b vector (which has a magnitude of 1/a in reciprocal space
I LOVE YOU!!!
in fcc arrangement for the atoms at the middle of the face of the cell the values of p,q and r are not integers
@Auysh mishra in FCC or bcc lattice we define primitive vectors for primitive cell which are formed of either lattice points of faces(in case of FCC) or the centre points ( in case of bcc) .
Sir the lecture is amazing but video quality is very poor 😓
Good. But I had to play the whole video on X1.25speed,...... too slow.
man you are too slow you are repeating a lot of times
tooooooooo slow ! please avoid repeating the same arguments over n over again !
Kindly improve ur english literally Fed up toooo slow