🔥 *PHD SERIES PLAYLIST* - bit.ly/3cQSxPT 👀 Links - MUST WATCH!! 👀 🚀 Master PDF File for Physics PYQs and Concept Videos - bit.ly/2ZKb5Of 🔥 GOLD Mine Link - bit.ly/2VhOGFF
In your previous videos I just commented you to make a video on two block problems and you made it so quickly sir. Thank you so much. your efforts are highly appreciated.
legends never comment in any educational platform. they just study, like, subscribe and giving millions and billions of love and thanks from their heart....❤
@@samairamalik3404No, gravitational force acts downwards. To understand normal force imagine you are pushing a wall, the force you give while pushing a wall is defined, we can call it F(human) signifying a human is giving a pushing force. But, the wall will not move, why? because of a multitude of factors and forces, there are too many to take into account but we know that the normal force always manages to equate the force we give on the wall. That is what normal force is, when a rigid body is immovable a normal force is said to act opposite to it. Hope i helped
My teacher made this concept so tough like it was something out of this planet 😞😭 😭😑😑😑 then i xame here and sir you made it soo simple to understand and made us feel the concept ❤❤❤❤❤❤❤ thank you sir ... # learn like never before is so true 😉
I missed the lecture of two block friction in my coaching centre and was struggling until through his past students I came to know about him, extremely grateful for the work he is doing for JEE aspirants. Explanantion was good and now I have some confidence to go through module questions and DPP's.
Awesome sir great explanation, i found second approch of these questions and now i feel more confident on this topic. Great Content and great efforts sir.
I am dropper student ... I hate physics since I started preparing for jee ... And I advanced physics ke kaaran hi mera selection nhi ho paya and abhi bhi muje physics itni pasand nhi thi bas jabarjasti karta tha par abhi 1 mahine pehele aapka channel Mila and u made it very easy and I started loving physics and I am now top scorer in physics in my mocks .. thank you so much sir ❤❤❤..love u sir
Note for my future reference - First step, second step for friction ques uk We have 2 categories Jaha F neeche Wale par lage Jaha F upar Wale par lage For no. 1 F max corresponds to f limiting for upar wala Final step me F = m sys (a max) [that chotu upar wala box can tolerate) When F exceeds F max neeche wala aur upar wale ka FBD alg-alg banake solve Karo! Ese me koi confusion hoga hi ni! Ki neeche Wale box ki final Force ea me m sys hoga ki m box etc etc For no. 2 F max corresponds to f limiting of lower box Here don't u dare forget ki f static is self adjusting so acc to values in ques they can ask F min and F max both!.. F max corresponds to f limiting F min corresponds to f kinetic (for lower box) Baki all well!..😁👍
I just want to send a hundred thousand thank you's to this man ❤ Love you sir and Tq so much boht help hua isse ☺ Please Phd series mai aur bhi imp topics karwa dena
Sir from the bottom of my heart I literally say thank you for clearing this concept as it scratched my head to understand. But now I understood the approach to solve such problems only because of you 🙏🙏🙏 thank you so much sir, ❤🙏🙏🙏
9:17 Sir, I think that the acceleration on the orange/ yellow block in the free body diagram will be on the left direction as it is pseudo acceleration.
@@mohitgoenka99 Thanks a lot sir, ye topic abhi tak clear nahi hua tha, ab sab clear hai 🔥, btw sir I am neet aspirant to neet ke liye koi separate playlist hai kya? 🤔
At 20:14 what if I applies a force of 27N f1m(maximum static friction is 25N) therefore making fbd for the case we get 2N as the net forward driving force with acc=0.4 m/s² But that same 25N (frictional force) would be acting on 10kg block also and the resisting force there equals 15N and hence as a result 10N is the net force.. therefore acceleration should be 1m/s² Then sir how can the range be 15 to 30N.. correct me if I am wrong anywhere
sir only becuse of you i am feeling confident in physics even after studying for 1 year from pw i am not feeling that confident but after founding your chanel 1 month before my physics had become so much strong
Sir please make such videos which will explain important topics in short.... Just like projectile motion....It will be really helpful... Thank u for this one🤩😇😇
Sir this lecture was awesome and gajbestic ❤️❤️💗❤️💗❤️💗❤️💗 And one request 🔥🔥🔥 Please make a PhD series on power questions including on water motor's power please sir 🙏🏻🙏🏻🙏🏻🙏🏻
all set sir love u im a dropper i scored 97 tile in physics in my mains first attempt but still had doubts now i might even score 100tile thank you very much!!!
hello sir ur channel has helped me a lot through out my jee preparation abhi advance ki padhai kar rahi thi toh socha phd series dekh lu aapke concenptual videos dekhe physics padhne main maja aane lagta hai aur samajhta bhi hai thank u sir for the support ur providing i will 100% suggest it to my juniors and pray 2 god that it grows more 🧿🧿💗💗
At 17:00 when applying the eqn We r applying for lower block Then i guess there total mass shd be 10+5 =15 not only 10 Plz correct me if im going wrong anywhere
im a dropper student and i was struggling with this topic ..not just this but various other in physics...this channel provides the best content ive ever seen quick reveisons and detailed analysis of core topics ..this has helped me alott i scored 97 percentile in physics in my first attempt but still had doubts struggling for a good logical explanation but now having doubts all cleared by this sole channel the only channel i find seriously helpful i feel like i might score 100 tile this year
Thankuuu v3ry much sir,❤❤ these questions looked like monsters to me in 11 th but now ,i find them very easy, this topic is all abt just forces nd we have to seee how ndwhere they r acting acc to accerlation or equilibrium , really thx u i understood the concept finally!
In the last case The max friction on 5kg BLOCK is 25N HOW IT WILL JUST MOVE AT 15N Btw IT WAS AN AWESOME SESSION LOVED IT❤❤❤❤❤ Thank You So Much Sir🙏🙏🙏🙏🙏
bro try to understand, only one block is not moving, the whole system is moving.... (the moment F becomes larger than fmax i.e 25, both blocks will then start moving at seperate acceleration)
🔥 *PHD SERIES PLAYLIST* - bit.ly/3cQSxPT
👀 Links - MUST WATCH!! 👀
🚀 Master PDF File for Physics PYQs and Concept Videos - bit.ly/2ZKb5Of
🔥 GOLD Mine Link - bit.ly/2VhOGFF
Gold mine or master pdf me difference kya h?
@@parthsarathidixit5648 Master PDF is just for PYQs (JEE Main) and Concept videos but GoldMine is overall channel educational content
@@mohitgoenka99 ok
Sir Three Block systems Or more than that With Graphs
@@parthsarathidixit5648 33eeee33333y
In your previous videos I just commented you to make a video on two block problems and you made it so quickly sir. Thank you so much. your efforts are highly appreciated.
You are most welcome
Sir rotation ka revision lec bana do
@@naveengupta2862 Tera kaam bhi done Hogaya bro 👌🔥
dude can u say the full form of this PHD series
@@aryanabhilesh11 PHoDu series
legends never comment in any educational platform. they just study, like, subscribe and giving millions and billions of love and thanks from their heart....❤
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
@@samairamalik3404No, gravitational force acts downwards. To understand normal force imagine you are pushing a wall, the force you give while pushing a wall is defined, we can call it F(human) signifying a human is giving a pushing force. But, the wall will not move, why? because of a multitude of factors and forces, there are too many to take into account but we know that the normal force always manages to equate the force we give on the wall. That is what normal force is, when a rigid body is immovable a normal force is said to act opposite to it. Hope i helped
@@zero0bb you did help!! thanks
You are not a legend then.
@@zero0bbLol,that's wrong.
My teacher made this concept so tough like it was something out of this planet 😞😭 😭😑😑😑 then i xame here and sir you made it soo simple to understand and made us feel the concept ❤❤❤❤❤❤❤ thank you sir ... # learn like never before is so true 😉
I missed the lecture of two block friction in my coaching centre and was struggling until through his past students I came to know about him, extremely grateful for the work he is doing for JEE aspirants. Explanantion was good and now I have some confidence to go through module questions and DPP's.
ONLY ONE THING.....
This is one of the best PHYSICS CHANNEL IN INDIA❤️❤️❤️❤️
This channel is going to have millions of subscribers...
Thanx for lovely comment dear.
Thank you sir all crystal clear
Awesome sir great explanation, i found second approch of these questions and now i feel more confident on this topic. Great Content and great efforts sir.
Glad to hear that
You made this concept crystal clear to me.
One of the best Physics teacher i have ever found....👍
Glad to hear that
Again , aaj topic ko revise kiya , aaj phir bolunga iss topic pe isssse achha video kisi ne banaya nahi hai ..
Thank you so much sir ❤
most welcome dear
keep learning
Sir says very very important concept at 13:40 😊
I am dropper student ... I hate physics since I started preparing for jee ... And I advanced physics ke kaaran hi mera selection nhi ho paya and abhi bhi muje physics itni pasand nhi thi bas jabarjasti karta tha par abhi 1 mahine pehele aapka channel Mila and u made it very easy and I started loving physics and I am now top scorer in physics in my mocks .. thank you so much sir ❤❤❤..love u sir
Did u appeared for jee 2024??
5:50 Fmax = 75N,
fmax = fl = 25N & acc of the system = 5 m/s^2
Even if the applied force is greater than 75N, Fl = 25N.
Never understood two block system in 11th now in 12th finally understanding it Thanks sirr...🙏🙏
always has doubt in when it will move together and when not and the way you explained is absolutely incredible I got it all thankyou so much
Majo aa gaya sir aap itna relat kaise ker lete hai ke humko kya problem aa rahi hai ❤❤ very very thanks 🙏🙏 you sir ❤❤
Note for my future reference -
First step, second step for friction ques uk
We have 2 categories
Jaha F neeche Wale par lage
Jaha F upar Wale par lage
For no. 1
F max corresponds to f limiting for upar wala
Final step me F = m sys (a max) [that chotu upar wala box can tolerate)
When F exceeds F max neeche wala aur upar wale ka FBD alg-alg banake solve Karo! Ese me koi confusion hoga hi ni! Ki neeche Wale box ki final Force ea me m sys hoga ki m box etc etc
For no. 2
F max corresponds to f limiting of lower box
Here don't u dare forget ki f static is self adjusting so acc to values in ques they can ask F min and F max both!..
F max corresponds to f limiting
F min corresponds to f kinetic (for lower box)
Baki all well!..😁👍
thanks buddy these takeaways are helpful
Ur written statement helped ❤️
good
Am I the only one who, first likes the video then watch it🤗
(Edit-bring more videos of concept which are being repeated)
This 2 block system is my favorite because my teacher didnt teach us this concept but some how after fighting 1hr i learned this concept by my own
Great Dear
change your teacher bro
Same here bro
Great explanation sir...-"friction a necessary evil."
sir kya mast padhate ho aap !!! charan sparsh!!
I dont know whether it will come to neet But I will definitely say this is the BESTEST video about 2 block problems... on YT
just wow!!
lovely dear
my concept is crystal clear sir.
now can easliy find direction of friction from the miniature visualization u did. in the start
dil se thankyou sir ye concept ekdum chamakgaya hai bahut problem hoti...in dealing these type of questions... thankyou
welcome dear
keep learning
Thank you for uploading this video sir.. was looking forward to your mechanics concepts 😁
Most welcome 😊
Most Valuable channel for JEE ASPIRANTS
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
Is type mai to bhut problem definite aati thi pahle but sir ab ye mera strength ban gya
Thanku sir 🙏 ☺
I just want to send a hundred thousand thank you's to this man ❤ Love you sir and Tq so much boht help hua isse ☺ Please Phd series mai aur bhi imp topics karwa dena
Sure dear. Check the playlist to find many topics
Sir thank you so much for this amazing session it cleared my whole concept about friction between two blocks 💖😊
pure gold....india owes you
greatEST EXPLANATION of two block system ever !!
well done dear
keep solving & learning
#learnlikeneverbefore
Sir from the bottom of my heart I literally say thank you for clearing this concept as it scratched my head to understand.
But now I understood the approach to solve such problems only because of you 🙏🙏🙏
thank you so much sir, ❤🙏🙏🙏
Best content of physics in whole youtube ❤️❤️❤️❤️
Best channel for physics on youtube👍🏻👍🏻👍🏻
Thanku sir just bcz of u i got 97 percentile in physics 🙏
Thanks a lot sir bht prblms arhi thi friction m aj clr hogya very nice explanation ❤️🙌🔥
Sir ji hame quality education dene aur visualise krke padhane ke liye thanx..🙏
You are most welcome dear
You made it crystal clear. Thank you sir 😊✨.
You are most welcome
THANK YOU SIR FOR THIS AMAZING PHD SERIES SACH ME PHD KRA DI AAPNE CONCEPT KI........
Most welcome dear
Sir jiiii.....kamaal karte ho sir ji aap. Thank u soooo much sir
Most welcome dear
9:17 Sir, I think that the acceleration on the orange/ yellow block in the free body diagram will be on the left direction as it is pseudo acceleration.
Sir aapka explanation to itna achcha hai ki iit phodne ka confidence agya hai thank you so much sir for such a wonderfull content
So nice we need teacher like him
16:21 acc of the system = 1 m/s^2, Fmax = 30N.
Range of applied force: 15 - 30N.
Thanks sir for this video bcz this concept become more strong only of u ....
20:54 thankyou😮😮😮🎉❤
Crystal clear concept 🚀🚀
Best physics teacher ❤ great sir.
keep learning dear
#learnlikeneverbefore
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
thank you so much sir. hats of to all your efforts.
Sir friction naso me bas gaya hai lecture dekh ke, maza aa gaya❤❤
Thnx sir is topic me bahut dikkat thi 🙏🙏🙏
Crystal clear 2 block system problems 😊thnks a lot of sir❤❤
well done dear
keep learning
@@mohitgoenka99 sir Aaj Mera test tha advance ka mere se NLM ke spring k concept k ques nhi bnn rhe the mere se kchh tips bta dejia kaise krun..??
I am in love with this channel great content. Also is it possible to increase the size of that red pointer it will be helpful plz
this channel is soooo underrated ,I really like the phd series they were very useful thank u so much sirr...
#learnlikeneverbefore
Your concepts are just lit 🔥, finally found this channel 🔥❤
Thanx dear & welcome to Eduniti
@@mohitgoenka99 Thanks a lot sir, ye topic abhi tak clear nahi hua tha, ab sab clear hai 🔥, btw sir I am neet aspirant to neet ke liye koi separate playlist hai kya? 🤔
@@surajmundhe2489 No dear but our PhD and revision series are equally relevant for you all
@@mohitgoenka99 okk sir ❤I definitely follow them, then 🔥✌
@@surajmundhe2489 bhai kaisa rha neet aapka
Got 95 marks in jan attempt...
Now targeting for 100 marks in April ❤❤
Thank you so much sir 🙏
excellent dear
wish you best
Just 1.25 question more (5 marks)😅
@@anjangamming6943which shift ?
@@AbhinavT26 27 ||
@@anjangamming6943probably he attempted all and did one ques worng
DHANYAWAD GURUJI🙏🙏🙏🙏🙏...
i am feelling very confident sir ...aap to ekdum GOD aur GOAT(greatest of all time) ho sir❤❤❤❤❤❤❤❤❤❤❤❤💙💙💙💙💙💙💙
This is the most underrated channel and you are a star sir ..thank you very much for this beautiful class sir 🙏🙏
Going on way completion of syllabus and this marvelous series I sway helping a lot ♥️♥️♥️♥️♥️♥️❤️❤️❤️❤️❤️❤️❤️💕💕💕
Excellent
Oh nice you cleared my doubt thank u so much ❤️
At 20:14 what if I applies a force of 27N f1m(maximum static friction is 25N) therefore making fbd for the case we get 2N as the net forward driving force with acc=0.4 m/s²
But that same 25N (frictional force) would be acting on 10kg block also and the resisting force there equals 15N and hence as a result 10N is the net force.. therefore acceleration should be 1m/s²
Then sir how can the range be 15 to 30N.. correct me if I am wrong anywhere
Sir aapki wajeh se mujhe phy se pyar hua h❤
The most of all videos on two block systems I have ever watched is not so good as you taught in too depth from basic to advance. Thank you sir ❤❤❤❤
@@TheSarkar-k4g most welcome dear
Kemon achis
Tui abhiman na ?
@@Vagabond_0789
Yes , you can assume
finally, ye topic bhi ho gaya acche se..!!🚩🚩❤❤🙏🏻🙏🏻
Thankyou sir, my concept is crystal clear now, such a beautiful explanation.
Thankyou very much......
sir ye concept bohot tough lagta tha pehle lekin ab nahi thnnkyou so much sir
Really sir loved it a lottttt😍😍
After watching your videos I gain confidence and pyqs bhi easily solve ho jaate h, thanks a ton 🙏🏻
Thanks to you and my friend who suggested your channel for revision ❤
keep learning
#learnlikeneverbefore
Sir this was very relevant and helpful.
Enjoyed a lot and thank you for everything you did to us .
Because yof you I liked this concept 😀
Best video on friction ❤
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
Super explanation sir❤
I WILL COME BACK TO WATCH THIS VIDEO IN 2HRS !!🔥🤟
Bkk
Amazing explanation sir ji ❤️❤️
Amazing job done sir 👏 maza aagya poore concepts and questions solve hogye
good
sir only becuse of you i am feeling confident in physics even after studying for 1 year from pw i am not feeling that confident but after founding your chanel 1 month before my physics had become so much strong
Bhai apne kaise use kia sir ka channel thoda briefly describe krna? 🙏❤
Same condition bro thank God I found this channel
@@dharmakurmi1257 bro sir ka 20 days challenge follow Kiya hai Maine pyqs lagaye hai 2022 or 2023 or kuch chapters m 2021 ke bhi
Shout Out To Mohit sir gonna be my fav Physics teacher 🛐
Thank you so much sir for making this concept crystal clear!!! Love from Kerala❤
You're most welcome
Sir please make such videos which will explain important topics in short.... Just like projectile motion....It will be really helpful... Thank u for this one🤩😇😇
Noted
Tysm sir...I was struggling with this concept...but now it got crystal clear...❤
Sir this lecture was awesome and gajbestic ❤️❤️💗❤️💗❤️💗❤️💗
And one request 🔥🔥🔥
Please make a PhD series on power questions including on water motor's power please sir 🙏🏻🙏🏻🙏🏻🙏🏻
Thankssss sir mera confusion dur ho gya hai ❤❤❤
Phd without thesis
Only mohit sir can give this much help...
keep learning & solving
#learnlikeneverbefore
Clarity aa gayi, thank u sir!
thank u sm sirr...aaj se pehle itne achhe se smjh nhi aaya thaa friction
✔ day 17 dhanwad sirr..
Sir I know where students face problems thanks sir
all set sir love u im a dropper i scored 97 tile in physics in my mains first attempt but still had doubts now i might even score 100tile thank you very much!!!
hello sir ur channel has helped me a lot through out my jee preparation abhi advance ki padhai kar rahi thi toh socha phd series dekh lu aapke concenptual videos dekhe physics padhne main maja aane lagta hai aur samajhta bhi hai thank u sir for the support ur providing i will 100% suggest it to my juniors and pray 2 god that it grows more 🧿🧿💗💗
Amazing explanation, literally got the concept 👍🏻
At 17:00 when applying the eqn
We r applying for lower block
Then i guess there total mass shd be 10+5 =15 not only 10
Plz correct me if im going wrong anywhere
25-15 =10a equation is just written for lower block dear. I made FBD of both block separately.
So here mass be 10 kg only.
@@mohitgoenka99 thank u so much sir🙏👍
Learnt like never before❤
Very well explained. Thank you.
Glad it was helpful!
if i wll get iit i will surely tell in my interview that mr rajwant singh and mr mohit goenka are gems of physics
lovely dear
keep solving, learning and revising
#learnlikeneverbefore
atleast he has some dreams unlike u@@comradesofficialff8800
mili IIT?
@@AyushAwasthi_JEE2025 iit ism dhanbad
@@sameersamal1708 ohh congrats bro...btw rank?
im a dropper student and i was struggling with this topic ..not just this but various other in physics...this channel provides the best content ive ever seen quick reveisons and detailed analysis of core topics ..this has helped me alott i scored 97 percentile in physics in my first attempt but still had doubts struggling for a good logical explanation but now having doubts all cleared by this sole channel the only channel i find seriously helpful i feel like i might score 100 tile this year
If you got 97tile in phy why are you taking drop
Thankuuu v3ry much sir,❤❤ these questions looked like monsters to me in 11 th but now ,i find them very easy, this topic is all abt just forces nd we have to seee how ndwhere they r acting acc to accerlation or equilibrium , really thx u i understood the concept finally!
well done on completing it
keep learning and solving
sir maine abhi mock m two block system k ques m glti ki thi to m yha aagya mistake sudharne thank uh sir ab aage +4 always ...
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?
I'm from pw batch and friction was not clear i had doubts thanks sir 🔥 now I understood everything
No offense...but RJ sir is really overrated
In the last case The max friction on 5kg BLOCK is 25N HOW IT WILL JUST MOVE AT 15N
Btw IT WAS AN AWESOME SESSION
LOVED IT❤❤❤❤❤
Thank You So Much Sir🙏🙏🙏🙏🙏
Keep it up
same question
bro try to understand, only one block is not moving, the whole system is moving.... (the moment F becomes larger than fmax i.e 25, both blocks will then start moving at seperate acceleration)
thank you sir i was really struggling to understand how the friction goes in diff direction in two blocks contact really helped me alot
I have a q. in bth cases,5N also applies a downward normal force on 10kg right? we just ignore it bc its in vertical equi?