@dylanmercergo7853 This is shown at 5:38 in the video. Additionally, this was taught with more detail a few lesson ago. th-cam.com/video/imhBilySH7E/w-d-xo.htmlsi=bxklDZ562iMoeVY2 Here is a quick overview: 1) Write each denominator as a product of prime factors 3 is prime, (x - 2) doesn't factor, and 36 = 2^2 * 3^2 2) Form a product of all the different prime factors. Each factor should have as exponent the greatest exponent that appears on that factor. So you need two factors of 3, two factors of 2, and one factor of (x - 2). This means the LCD is 36(x - 2).
![Complex Fractions [fbt] (Simplifying Complex Fractions)](/img/n.gif)
Please explain why the 2nd problem has 36 as one of the lcd rather than 12?
What's the time marker of the problem you are stuck on?
@@Greenemath From 5:20 Sir Greene. Thanks for your time. Appreciate it!
@dylanmercergo7853
This is shown at 5:38 in the video. Additionally, this was taught with more detail a few lesson ago.
th-cam.com/video/imhBilySH7E/w-d-xo.htmlsi=bxklDZ562iMoeVY2
Here is a quick overview:
1) Write each denominator as a product of prime factors
3 is prime, (x - 2) doesn't factor, and 36 = 2^2 * 3^2
2) Form a product of all the different prime factors. Each factor should have as exponent the greatest exponent that appears on that factor.
So you need two factors of 3, two factors of 2, and one factor of (x - 2). This means the LCD is 36(x - 2).
@@Greenemath GOODNESS GRACIOUS! Thank you so much Sir Greene. I'm actually on this type of lesson on my Math Text.
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