How about this: ((8/x)+(3/y))/(3x+8y)? I am able to solve it, but I have no idea if it had excluded value(s) or how to find it/them. I know I canceled out 3x+8y, but I'm not sure if that counts as an excluded value. And for my final answer I got 1/xy, so would xy be an excluded value because it is a denominator? Also, would x or y have these excluded values, or just x (or just y) has excluded values? THIS IS SO CONFUSING.
1/xy is the correct simplification. So you have that part down. For the excluded values, remember we cannot divide by zero. x, y, z, q or whatever variable you have is just a place holder. It represents some unknown. In the case of something simple such as: 1/(x + 3), what can x not be equal to? x cannot be -3, since replacing x with -3 leads to a denominator of 0. So in your original denominator 3x + 8y, x and y cannot be any value that would lead to a denominator of zero. So anything that satisfies 3x + 8y = 0 would be excluded. Since this is a linear equation in two variables, there are an unlimited number of ordered pairs that would satisfy that equation. If we had (-8,3), we would get a denominator of zero as an example. So long story short. You can find your restricted values by setting the denominator equal to zero and solving. The solutions to that equation are the restricted values, since they would result in a denominator of zero.
what if the problem is like this: (Change the sign, write 3 rational expression of) 3x-5y / y ? -x/y-4x ? and -x-6x/-4 ? how to solve these? please help :)
Is the whole thing raised to that power? (x + 2 / x)^(2 + 6x + 8) Or is it something else? Also you have capital X and lowercase x which is technically two different variables. Not sure if that is a typo. Let me know and I can try and help out.
I normally use Microsoft One Note, but in this particular video I used Microsoft Journal.
3:52 the most satisfying square
Glad to hear that! :)
How about this: ((8/x)+(3/y))/(3x+8y)? I am able to solve it, but I have no idea if it had excluded value(s) or how to find it/them. I know I canceled out 3x+8y, but I'm not sure if that counts as an excluded value. And for my final answer I got 1/xy, so would xy be an excluded value because it is a denominator? Also, would x or y have these excluded values, or just x (or just y) has excluded values? THIS IS SO CONFUSING.
1/xy is the correct simplification. So you have that part down. For the excluded values, remember we cannot divide by zero. x, y, z, q or whatever variable you have is just a place holder. It represents some unknown. In the case of something simple such as:
1/(x + 3), what can x not be equal to? x cannot be -3, since replacing x with -3 leads to a denominator of 0. So in your original denominator 3x + 8y, x and y cannot be any value that would lead to a denominator of zero. So anything that satisfies 3x + 8y = 0 would be excluded. Since this is a linear equation in two variables, there are an unlimited number of ordered pairs that would satisfy that equation. If we had (-8,3), we would get a denominator of zero as an example. So long story short. You can find your restricted values by setting the denominator equal to zero and solving. The solutions to that equation are the restricted values, since they would result in a denominator of zero.
You're Boss keep teaching!!!
Thanks, I'm glad you found it helpful!
what if the problem is like this: (Change the sign, write 3 rational expression of)
3x-5y / y ? -x/y-4x ? and -x-6x/-4 ? how to solve these? please help :)
Anytime you have a fraction, you use the following rules: -a/b = a/-b = -(a/b)
You make it so easy. My professor says so much, making the whole problem complicated.
I'm glad you found the video helpful! 😎
What program u use to write in the video?
I answered above, but I guess it didn't link to your comment. Anyway I used Microsoft Journal / Microsoft One Note for all videos.
Really nice video I got it all.
Thank you :)
Thank You for your video
You are very welcome. 😎
Thank you so much!!!This made it so clear!!!!!!!!!!!!!
You are very welcome! 😎
How come you didnt factor for the problem at4:38
4:38
There's nothing to factor?
Thank u sooooooooooo much man!
You are very welcome!
1-:09 - Why did it turn 4?
btw im in 7th Grade ;-;
What's the time marker? Nothing is happening at 1:09.
What if it's like this tho? 5/4 and also 1/4???
What's the problem written out? I'm not sure what you are doing with those two fractions.
If I'm wrong at my assignment, I'm blaming myself and my headache because I didn't listen to my teacher :")
Meh it happens, good luck with your studies :)
thank you soooooo much !
You are very welcome!
how to solve X+2/x to the power of 2+6X+8?
Is the whole thing raised to that power?
(x + 2 / x)^(2 + 6x + 8)
Or is it something else? Also you have capital X and lowercase x which is technically two different variables. Not sure if that is a typo. Let me know and I can try and help out.
wow thank you
You are very welcome!
i want to go back to kindergarten
Those were the good times! You even get a mat to sleep on! :)