Thank you! I have not learnt calculus yet, but you make it very easy to understand. Do you think you could do an integration challenge, or do you only make videos about finding the area?
How is this hard? The curves intersect at x=2: 9-x^2 = 3+x (3-x)*(3+x) = 3+x 3-x = 1 x=2 So just subtract and integrate from 0 to 3: 9 - x^2 - 3 - x 6 - x^2 - x Integral: 6*x - x^3/3 - x^2/2 At 2: 12 - 8/3 - 2 = 10 - 8/3 = 22/3 At 0: 0 - 0 - 0 = 0 So the difference, and the solution, is 22/3.
Masterpiece. No confusion, no unnecessary working, short, sweet and to the point. Others should take a page out of your book ❤
Thank you very much, I'm glad you liked it, the idea is for people to see that mathematics is not complicated. Greetings
Not sure this is an extreme challenge, but it was presented very well.
It's relative, thanks and regards
Thank you! I have not learnt calculus yet, but you make it very easy to understand. Do you think you could do an integration challenge, or do you only make videos about finding the area?
Hello, I think I could make a section of video tutorials on Differential and Integral Calculus
Sorry, I meant to say derivatives, but i wouldn't mind more area challenges like the last two videos. Those have been really helpful. Thanks
Please, put parentheses in the integral.
Thank you
Use area of parabola as 2/3 base * height . And no integration. 10th class question.
How is this hard? The curves intersect at x=2:
9-x^2 = 3+x
(3-x)*(3+x) = 3+x
3-x = 1
x=2
So just subtract and integrate from 0 to 3:
9 - x^2 - 3 - x
6 - x^2 - x
Integral: 6*x - x^3/3 - x^2/2
At 2: 12 - 8/3 - 2 = 10 - 8/3 = 22/3
At 0: 0 - 0 - 0 = 0
So the difference, and the solution, is 22/3.