Nice puzzle; and great solution! The only hint I needed was seeing Heron's formula in the title board. Even more fun if the semicircle is laid on the side of length 14, so the blue area is exactly 36 pi. 😉
So the circle arc was drawn such that the center is inside the length 15 triangle side. Well that makes the construction right. I wasn't sure if the centre of circle was supposed to be on the line or somewhere else where perpendiculars to the other triangle sides and circle are tangent
@@CristhianMathematician nice problem. Maybe postponing the area calculation until after the radius were drawn and opposite vertex and circle centre marked would make more sense for younger viewers At a point in my life I just taught to myself if I wanted to measure a circular hole and didn't have enough measuring tape to get the diameter how would I get the radius of a circumscribed circle from 3 sides measurement. Turns out herons formula is useful after all or alternatively using generalised theorem of Pythagoras and trig identities plus law of sines does the trick
27÷15×1=1.8)(15-1.8=13.2÷2=6.6)(13×13-6.6×6.6=165.76 squroth=12.87×15=193.1217÷2=96.56full area trengle)(12.87÷2.41421356=5.3329×5.3329×3.14159268÷2=48.5499
Nice puzzle; and great solution! The only hint I needed was seeing Heron's formula in the title board.
Even more fun if the semicircle is laid on the side of length 14, so the blue area is exactly 36 pi.
😉
if not explicit that blue area is exactly a semicircle (circle/2), can not be solved.
Nice❤
Thanks 🔥
So the circle arc was drawn such that the center is inside the length 15 triangle side.
Well that makes the construction right. I wasn't sure if the centre of circle was supposed to be on the line or somewhere else where perpendiculars to the other triangle sides and circle are tangent
Exactly the diameter of the semicircle is drawn on the side of the triangle. What did you think of the exercise?
@@CristhianMathematician nice problem. Maybe postponing the area calculation until after the radius were drawn and opposite vertex and circle centre marked would make more sense for younger viewers
At a point in my life I just taught to myself if I wanted to measure a circular hole and didn't have enough measuring tape to get the diameter how would I get the radius of a circumscribed circle from 3 sides measurement. Turns out herons formula is useful after all or alternatively using generalised theorem of Pythagoras and trig identities plus law of sines does the trick
Je connais aussi le théorème de kashi et le produit vectoriel
😂😂😂😂😂😂😂😂😂
27÷15×1=1.8)(15-1.8=13.2÷2=6.6)(13×13-6.6×6.6=165.76 squroth=12.87×15=193.1217÷2=96.56full area trengle)(12.87÷2.41421356=5.3329×5.3329×3.14159268÷2=48.5499
Fascinating, how did you like the exercise?