To determine the normality of a ferrous ammonium sulfate (FAS) solution, you need to know the following: 👉The molar mass of ferrous ammonium sulfate [Fe(NH4)2(SO4)2·6H2O] is approximately 392.14 g/mol. 👉The equivalent weight of FAS depends on the reaction it is involved in. In redox reactions where iron (Fe²⁺) is oxidized to Fe³⁺, FAS has an equivalent weight equal to its molar mass because 1 mole of Fe²⁺ loses 1 mole of electrons. ✅Steps to Calculate Normality: 1. Weigh the FAS: Accurately weigh a certain mass of ferrous ammonium sulfate. 2. Dissolve in Water: Dissolve the weighed FAS in distilled water and make up to a known volume (typically in liters or milliliters). 3. Determine Equivalent Weight: For ferrous ammonium sulfate in redox reactions, the equivalent weight is 392.14 g/equivalent. 4. Formula for Normality: Normality (N)= Mass of FAS (g) \Equivalent weight (g/equivalent) x Volume of solution (L) ✅Example Calculation: 👉Suppose you dissolve 19.6 g of FAS in 1 liter of solution. 👉The equivalent weight of FAS is 392.14 g/equivalent. Now, apply the formula: N = 19.6 / {392.14 x 1} = 0.05 N So, the normality of the solution is 0.05 N. ✅Key Points: 👉Use the molar mass of FAS (392.14 g/mol) for determining the equivalent weight. 👉The volume of the solution should be in liters to get the normality in equivalents per liter (N). 👉The normality is a measure of the concentration of reactive equivalents in a solution.
Solid and moisture ko kese calculation kare
FAS ki normality kese likhalte hai
Video banaiye
To determine the normality of a ferrous ammonium sulfate (FAS) solution, you need to know the following:
👉The molar mass of ferrous ammonium sulfate [Fe(NH4)2(SO4)2·6H2O] is approximately 392.14 g/mol.
👉The equivalent weight of FAS depends on the reaction it is involved in. In redox reactions where iron (Fe²⁺) is oxidized to Fe³⁺, FAS has an equivalent weight equal to its molar mass because 1 mole of Fe²⁺ loses 1 mole of electrons.
✅Steps to Calculate Normality:
1. Weigh the FAS: Accurately weigh a certain mass of ferrous ammonium sulfate.
2. Dissolve in Water: Dissolve the weighed FAS in distilled water and make up to a known volume (typically in liters or milliliters).
3. Determine Equivalent Weight: For ferrous ammonium sulfate in redox reactions, the equivalent weight is 392.14 g/equivalent.
4. Formula for Normality:
Normality (N)= Mass of FAS (g) \Equivalent weight (g/equivalent) x Volume of solution (L)
✅Example Calculation:
👉Suppose you dissolve 19.6 g of FAS in 1 liter of solution.
👉The equivalent weight of FAS is 392.14 g/equivalent.
Now, apply the formula:
N = 19.6 / {392.14 x 1} = 0.05 N
So, the normality of the solution is 0.05 N.
✅Key Points:
👉Use the molar mass of FAS (392.14 g/mol) for determining the equivalent weight.
👉The volume of the solution should be in liters to get the normality in equivalents per liter (N).
👉The normality is a measure of the concentration of reactive equivalents in a solution.
Sir aap kaha se he
Gorakhpur
Sir etp bacteria develop krne ke liye best solution bataiye
th-cam.com/video/fdSVrDNES64/w-d-xo.html