I really appreciate the hardwork of the whole team thanks a lot Homework answer Q5 = a is 5 d=1.75 a n is 20.75 After solving 20.75=5+n-1×d n=10 Q2 S7 is 49 S17 is 289 given Sn=n/2×2a +n-1×d for both 7 and 17 a+3d=7 -(i) a+8d=17-(ii) By elimination method d=2, a=1 Sum of n = nsquare
Alternatively we can derive the formula to find the sum of first 100 natural numbers as below. Sn=1+2+3+...+100. 1+. 2+. 3+....50 100+99+98 +51 ---------------------------------- 101+101+....+. 101 50×101=50×(100+1)=5050. In general S=n(n+1)/2 where n is number of terms.
Good afternoon ma'am, It was a wonderful session 🎉 H. W. QUESTION : (Q-5) By using the formula a+(n-1)d Value of n = 10 (Q-8) In this question we have to form two equations : 2a +6d = 14 ______(1) 2a + 16d = 34 _____(2) By using Elimination method, d=2 From equation (1) a=1 Using the formula Sn = n/2 (2a+(n-1)d), We get, Sn = n².
Homework Question :- Imp Ques 5 :- By going through the statement we got to know that a=5 d=1.75 an = 20.75 And we have to find n So by putting all the given values of in the formula 'an=a+(n-1)d' We got n=10 Imp Ques 8 :- By reading the statement we got to know that S7=49 n=7 By putting these values formula 'Sn=n/2[2a(n-1)d]' We got S7 = a+3d-------- (i) And We were also known that S17=289 n=17 By putting these values in the formula 'Sn = n/2[2a(n-1)d]' We got S17=a+8d ‐------- (ii) By subtracting equation ii and i We got value of a = 1 and d=2 So, the sum of n terms would be Sn=n/2[2a(n-1)d] By plugging in all the values We got {Sn=n²} Thank you so much ma'am for this wonderful session and want more such sessions. It was much helpful.😊😊😊
Homework:--------- By going through the statement we got to know that a=5 d=1.75 an = 20.75 And we have to find n So by putting all the given values of in the formula 'an=a+(n-1)d' We got n=10 Imp Ques 8 :- By reading the statement we got to know that S7=49 n=7 By putting these values formula 'Sn=n/2[2a(n-1)d]' We got S7 = a+3d-------- (i) And We were also known that S17=289 n=17 By putting these values in the formula 'Sn = n/2[2a(n-1)d]' We got S17=a+8d (ii) By subtracting equation ii and i We got value of a = 1 and d=2 So, the sum of n terms would be Sn=n/2[2a(n-1)d] By plugging in all the values We got (Sn=n²} ❤❤Thanks mam❤❤❤
Mam aap bohot accha padhati hoo I understand everything but you're not taking all the chapters... why...triangles and trigonometry??? Please aap lelo...
Mam At Byjus The Learning App, I am not able to change my grade from 9th to 10th😐 I registered on it in 9th standard and it's still showing me class 9th content but I am in 10th Please tell what to do and how🙏🙏
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Why this channel is underrated. Your teaching style is awesome ma'am
Mam Playlist of math sessions 2024 25 in a proper way please ❤❤
Bhot aachi teacher hai bhot aache sei padha tii hai...😊😊
I really appreciate the hardwork of the whole team thanks a lot
Homework answer
Q5 = a is 5
d=1.75
a n is 20.75
After solving 20.75=5+n-1×d
n=10
Q2 S7 is 49
S17 is 289 given
Sn=n/2×2a +n-1×d for both 7 and 17
a+3d=7 -(i)
a+8d=17-(ii)
By elimination method
d=2, a=1
Sum of n = nsquare
H.W answers
5ans: n=15
8ans: a=1 ; d=2 ; Sn=n^2[n square]
Thanks a lot mam for the amazing learning within an hour..☺👍
Thankyou ma'am for this wonderful session:)
Maam this is my humble request that pls make another video on ex 5.2
Because questions after 6 are little bit tricky 😢😢😢😢😢😢
Alternatively we can derive the formula to find the sum of first 100 natural numbers as below.
Sn=1+2+3+...+100.
1+. 2+. 3+....50
100+99+98 +51
----------------------------------
101+101+....+. 101
50×101=50×(100+1)=5050.
In general S=n(n+1)/2 where n is number of terms.
Good afternoon ma'am, It was a wonderful session 🎉
H. W. QUESTION :
(Q-5)
By using the formula a+(n-1)d
Value of n = 10
(Q-8)
In this question we have to form two equations :
2a +6d = 14 ______(1)
2a + 16d = 34 _____(2)
By using Elimination method,
d=2
From equation (1)
a=1
Using the formula Sn = n/2 (2a+(n-1)d),
We get,
Sn = n².
Homework answer:
1) a=5
d=1.75
an=20.75
n=?
An=a+(n-1)d
n=10
2)
S7=49
S17=289
7=a+3d ------>1
17=a+8d ------>2
d=2
Substituting
a+3(2)=7
a=1
Therefore sn=n²
Homework Question :-
Imp Ques 5 :-
By going through the statement we got to know that
a=5
d=1.75
an = 20.75
And we have to find n
So by putting all the given values of in the formula 'an=a+(n-1)d'
We got n=10
Imp Ques 8 :-
By reading the statement we got to know that
S7=49
n=7
By putting these values formula 'Sn=n/2[2a(n-1)d]'
We got S7 = a+3d-------- (i)
And
We were also known that
S17=289
n=17
By putting these values in the formula 'Sn = n/2[2a(n-1)d]'
We got S17=a+8d ‐------- (ii)
By subtracting equation ii and i
We got value of a = 1 and d=2
So, the sum of n terms would be
Sn=n/2[2a(n-1)d]
By plugging in all the values
We got {Sn=n²}
Thank you so much ma'am for this wonderful session and want more such sessions.
It was much helpful.😊😊😊
Im fine mam
Ans 5.n-16,d-8/3
8. S51-5610
5) n=16, d=8/3
8) S51=5610
Thanks for wonderful session
Mam i download with lot of effort it is very bad😮
But i download in laptop
Phone ma nahi hua
Homework:---------
By going through the statement we got to know that a=5 d=1.75 an = 20.75 And we have to find n So by putting all the given values of in the formula 'an=a+(n-1)d' We got n=10
Imp Ques 8 :-
By reading the statement we got to know that
S7=49 n=7 By putting these values formula 'Sn=n/2[2a(n-1)d]' We got S7 = a+3d-------- (i) And We were also known that S17=289 n=17 By putting these values in the formula 'Sn = n/2[2a(n-1)d]' We got S17=a+8d (ii) By subtracting equation ii and i We got value of a = 1 and d=2 So, the sum of n terms would be Sn=n/2[2a(n-1)d] By plugging in all the values We got (Sn=n²}
❤❤Thanks mam❤❤❤
homework answe:
5ans: n=15
8ans: a=1 ; d=2 ; Sn=n^2[n square]
Homework Questions
1) n=2
2)a=1
Mam I request you to make a video on the triangle chapter mam🙏🙏🙏🥺🥺
Jab jab kab tab hoi Lekin padhaiya byzus ke sang hoi
please bring ncert solution session
Mam aap bohot accha padhati hoo I understand everything but you're not taking all the chapters... why...triangles and trigonometry???
Please aap lelo...
Mam At Byjus The Learning App, I am not able to change my grade from 9th to 10th😐
I registered on it in 9th standard and it's still showing me class 9th content but I am in 10th
Please tell what to do and how🙏🙏
Mam please provide your full class 10 Play list
Ma'am please 🥺🙏🙏🙏🙏
Why there is no new class
Why younot posting new chapters we are waiting and lot pending is going on ur channel
No reply 😮😮
Hello ma'am 👋🥺🙏🙏🙏🙏💋
Ma'am ncert questions 😢🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺🥺
Hlo mam
Hii ma'am ncert solutions 😢🥺🥺🥺🥺🥺🥺