Constant Acceleration 6 • SUVAT Simultaneous Equations • Mech1 Ex9D • 🚀

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  • เผยแพร่เมื่อ 5 พ.ย. 2024

ความคิดเห็น • 31

  • @missunicorn7681
    @missunicorn7681 3 ปีที่แล้ว +29

    thank you so much, I am so glad i found ur channel. you are teaching me things even my teacher has not taught me. it's nice to see a teacher that is dedicated to not only your students but any student that watches your videos, I hope all your days are forever filled with happiness :)))))

    • @BicenMaths
      @BicenMaths  3 ปีที่แล้ว +12

      What a lovely, kind comment - thank you so much for writing it! Wishing you all the best for your studies - and let me know if I can help in any way!

    • @missunicorn7681
      @missunicorn7681 3 ปีที่แล้ว +2

      @@BicenMaths :)) of course!

  • @sameerdewan9218
    @sameerdewan9218 ปีที่แล้ว +5

    could you tell us where you got the worksheet from pls? i would like to practice these questions more
    😊

    • @BicenMaths
      @BicenMaths  ปีที่แล้ว +6

      The questions are taken from Exercise 9D of the Applied Year 1 Edexcel textbook, and also from Mixed Exercise 9.

  • @HistorAIy
    @HistorAIy ปีที่แล้ว +1

    For the last question part a why can’t you do QR and PR and equate the final velocity? I tried it and it didn’t get the same answer

    • @BicenMaths
      @BicenMaths  ปีที่แล้ว

      Did you add the distances together to get distance PR? You should be able to use your method, it will work if you have all the correct values!

  • @hashimabbas6731
    @hashimabbas6731 6 หลายเดือนก่อน +2

    goat 🐐

  • @TheRealD3Y
    @TheRealD3Y 2 ปีที่แล้ว +4

    at 2:40, doesnt one second later mean another second added. so if p was moving 9s, then q would have been moving 10s as its one second later? thanks for everything and i hope you can clear this up and help me understand this.

    • @BicenMaths
      @BicenMaths  2 ปีที่แล้ว +4

      It means that Q has been in motion for one second less, hence my notation. The time for Q is measuring how long it has been moving for!

    • @BicenMaths
      @BicenMaths  2 ปีที่แล้ว +2

      Yes!

  • @gunjitaswami7743
    @gunjitaswami7743 2 ปีที่แล้ว +3

    for 3:02 isnt q 1 second later than p? so, shouldnt it be t plus 1???

    • @BicenMaths
      @BicenMaths  2 ปีที่แล้ว +4

      No because that would mean it had been travelling 1 second longer than P, but it left 1 second after so it’s time is 1 less than p!

  • @bryceanderson7468
    @bryceanderson7468 5 หลายเดือนก่อน +1

    Don’t you have to convert km and hours into si units for the last question, or is it okay to leave it how it is? Thankyou

    • @BicenMaths
      @BicenMaths  5 หลายเดือนก่อน +1

      You do usually - but as we didn't need it in the standard units at the end, this was OK to leave.

    • @bryceanderson7468
      @bryceanderson7468 5 หลายเดือนก่อน +1

      @BicenMaths OK, thank you very much!

  • @SeyamMuhaimin
    @SeyamMuhaimin ปีที่แล้ว +1

    Hi sir, my end of year 12 exams are coming up and I wanted to ask if you know any websites/places where there are questions for each topic(not a lot) that cover the whole topic and then there is a video or answers showing how to solve it if I got stuck. This is because I don’t have much time and would like to go over everything I learnt within a few questions. Thanks.

    • @BicenMaths
      @BicenMaths  ปีที่แล้ว +1

      Hmm not that I know of, although I have all my exam questions arranged in topics in my Google Drive - you can find it in the About section on my channel.

    • @chaska8144
      @chaska8144 9 หลายเดือนก่อน +3

      physicsandmathstutor, savemyexams, isaacphysics, revisely

  • @ibrahimsahak1696
    @ibrahimsahak1696 4 ปีที่แล้ว +8

    Helpful

  • @samuelbrodie1060
    @samuelbrodie1060 ปีที่แล้ว

    Hi, At 5:20 can you please explain how you knew that the displacement for each particle is the same? Are you saying that the displacements from point A is the same? Also, could you make both t values equal to each other? Thank you so much!

    • @BicenMaths
      @BicenMaths  ปีที่แล้ว

      So they have the same displacement as they have both started and ended at the same point, and you could also have equated the t values too!

  • @sss-sl3nu
    @sss-sl3nu 6 หลายเดือนก่อน

    can you give me a scenario where you add 1 to T instead of subtracting.

    • @BicenMaths
      @BicenMaths  6 หลายเดือนก่อน +1

      If we let T by the time for particle A to travel, and then B was travelling but started 1 second before A, then the time for B would be T+1 as it would be travelling for the same amount of time as A plus 1 extra second!

    • @sss-sl3nu
      @sss-sl3nu 6 หลายเดือนก่อน

      @@BicenMaths thank you

  • @BBK583
    @BBK583 7 หลายเดือนก่อน

    At 1:20 how is “u” = 3 and not “v”. If it’s been travelling for 1 second, thats not its initial velocity is itv

    • @BicenMaths
      @BicenMaths  7 หลายเดือนก่อน

      We’re about to consider its journey after this point, so 3 is its initial velocity for the journey that we are considering.

  • @mako.chiwariro9978
    @mako.chiwariro9978 ปีที่แล้ว

    Hi sir at
    16:01 how di you get the values for U and A please !

    • @BicenMaths
      @BicenMaths  ปีที่แล้ว

      Good question! My calculator has the simultaneous equation solver function, so I imagined that u and a were the x and y variables, and treated it as a pair of simultaneous equations!

  • @BBK583
    @BBK583 7 หลายเดือนก่อน

    Don’t understand why you chose PQ and PR for the last question, how do you make that decision?

    • @BicenMaths
      @BicenMaths  7 หลายเดือนก่อน

      We need to have some shared values in order to do simultaneous equations, and by having P with both of them, we have the shared initial velocity. We also have shared acceleration too.