Finding Remainder | Binomial Theorem | Crack In Seconds | Unacademy JEE | JEE Maths | Nishant Sir
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- เผยแพร่เมื่อ 13 ต.ค. 2024
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Unacademy JEE | JEE Mains | JEE Advanced | JEE 2020 | JEE 2021 | JEE Mains 2021 | JEE Advanced 2021 | JEE 2022 | Class 12 Maths | Class 11 | JEE Maths | Binomial Theorem | Finding Reaminder | Finding Remainder Using Binomial Theorem | Binomial Theorem | Binomial Theorem Tricks | Binomial Theorem IIT JEE | Binomial Theorem Ticks
In this session, Nishant Sir will be helping you find the remainder of a number using the Binomial Theorem.
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now the year is 2022 and jee have literally asked a direct question on remainder..thanks sir
Yeah
Same mere shift me tha and i left it 😒😒😒
same in my shift too
Mere sift me bhi tha
3 direct questions
Nishant sir's tricks are amazing! His vision of tackling jee problems are A++✌️✌️
They are. But sir doesn't tell us the logic behind them so that we can know it's limitations too.
@@Raj-qy7pl Abhi logic ki jarurat nai,waqt kam hai,BTECH me padh lena
@@Raj-qy7pl i have given the logic see😂
@@nishasharma7459 🤨 -> 🤔 -> 😒 -> 😏
16:12 m 9 se remainder -1 kyo aayega +4 ni aayega please jisko bhi aata ho reply
youtube recommending this to me one day before my jee... looks like a sign!
Hey,how was your jee btw
Jee main 2022 , 26th June 1st shift. Thank you so much sir. Got this correct in just few sec. 🙏😌
4
26 S2 aya 2nd paper ?
@Divy Pathak I am regretting doing it hours before exam because it didn't came in my second shift
Who is Here After Jee Brief Series 😅
Wonderful trick..As you said the normal method used to be long and time taking and in some questions there is no guarantee we get the right answer.. this shortcut is wonderful sir.. thank you sir for this trick... Want more tricks for matrices and integration sir.. will be very helpful sir.
o
Shortcut nhi h bhai .... Bas direct kar rhe h sir normal wale me jaoge to waha bhi kuch integer banta hi tha
.... To wahi likh nhi rhe h direct kar rhe h binomial theorm se bhi jaoge to wha bhi ( 1+x) ke form me hi late the ... But ha time Kam lgg rha ❤
22:52 , the nearest multiple is 32 , therefore difference must be (27-32 = -5)
Yields the same answer anyway.
If it's -5 then the answer should be 11 and not 5
@@shailybansal9661 I made this comment 3 years ago, don't have any idea what this is about 😂 nor am gonna see this, my JEE journey was over long ago lol
Sir format theorm , prime numbers methods and Many other methods for calculate remainder easily sir please meke video for all complete methods
its fermat
It's ferment
*Osm Mathematics tricks Really Loved*
osm bhai osm
Thanks sir because of you i got +4 marks in jee July 27 shift 1 2022
How.much percentile bro😅
Lecture starts at : 01:30
And end at : 25:00
Thank you Miss Ritu ..
I was searching for this 🙂
but dont miss one more shortcut @ 27:24
@@dimplegupta7184 Thank you so much dimple ♡♡♡
@@dimplegupta7184 thank you so much
Thank You Very Much Sir FOR THIS GREAT EXPLANATION.....
*THANKS* *A* *LOT*
Sir the trick was awesome !! They can't be better at this point :)
Thanks sir for explaining this types of problems.
😭😭 thank you so much sir i cannot explain in words how much this video helped me.........thanks a million
Thankyou sir for this amayyyzing lecture!!!!! Loved it❣❣🔥🔥🔥🔥🙏🏻🙏🏻🙏🏻🙏🏻
Superb lecture sir it is very helpful
Hats off to whole jee live daily team
Thank you sir
I thought this is toughest question if 2 to 3 numbers with different powers get multiply and then divide by any other number but after seeing your video if become very easy
Sir make the shortcuts of whole jee syllabus pls my request
I agree bro
Agreed 😆
I always wanted a trick for this . thank you very much❤️❤️❤️❤️
Arey bhai sahab,,,maja aagya,,,kasam se dil jeet liya sir ne,,,😍😍😍,,,kattayi jeher,,,
ohh bhai maro mujhe maro ...SIR AWESOME😱 DIMAAG PHAT GAYA😂(MIND BLOWING)❤️
Bhai aapke pas math nhi hogi 11 12 me esliye itna surprised ho
@@Jesus_forever3123 actually baki alag methods se kaafi asaan hai yeh
Legends know this is derived from congruent modulus remainder finding technique😎
Congreunce modulo hota hai
Legends don't care form where it is derived ...only need marks
@@aspirant392 je baat ! 🍻
@@aspirant392 😂
Ah Olympiadic boyh
You rocked it sir
Mind boggling Trick ❤️♥️❤️♥️
Very Helpful Trick. For every Competitive Or for easyness.
Love you sir for this! This is evergreen, thanks a lot !
Please Teach us Feynmans Trick of integeration plz!!!!!!!!!
How to find the remainder of 3*7^22+2*10^22-44 when divided by 18 through this trick?
ans is 15
i also have a doubt whay if the nagativee remainder when subtracted with divisor also comes negative tthen?
ye trick UPSC CSAT me use krunga!!🤩🤩
Sir iss question ko kaise karenge ,??
The remainder when 19^200+23^200 is divided by 49, is _____ .
Maine
19^100 ×19^100 likh kar single single of 7×7 se divide karke solve karne ka try kiya. But kuch galat hora.
HATTS OFF SIR !!!!! EKDAM AAG LAGA DIYA AAPNE🔥🔥🔥🔥🔥
It's basically congruent modulo
Why i found it so late . This trick is awesome . We really need these type of shortcuts 💚💚
Greatly explained with plenty of examples and cases. Thank you ❤
Jee main april 2023 13 shift 1 direct question sir thanks a lot 🙏
Yes sirrr
sir here 1 thing is misssing
basically if we divide 2023 by 35 its reminder is 28 but if we write 35 as 7 *5 then seven will cut by 2023 and the value will become as 289/5. so reminder cones 4 so basically in yours method we dont have to split denominator till the end
Vohi toh.
Same with the example of 27^40 divided by 12 😂😂. Iss trick ke according 3 aajayega answer which is wrong
Came from Bounce back series
Sir 2^99 ÷ 33 ka reminder 16 aayega
14:50 pr can anybody check 😐
Mistake 16÷33 ka reminder -17 aayega not -16
14:34 16 ko 33 se divide karne par 16 kaise aayega
You heard wrong
when the dividend is smaller than divisor the dividend itself becomes the remainder
Wow sir aap genius ho ❤
Sir infinity kind of you abhi aap papper solve kara rahe the aapne bataya ayaha aa gaya me aur ab to halua ho gaya question ❤️
same bhai
Not same
Ultimate remainder finding in history of you tube
It was a great trick I am your plus student but just came here to see your great teaching 🤩🤩🤩🤩
OSM METHOD SIR. DIL GARDEN GARDEN HO GYA
Thanks a lot for this one sir.
Hoping more of crack in seconds
Thank you sir ❤❤❤ loved the trick so much
I am Surprised i am able to solve the problems after this mind blowing
Truly amazing the only waited lecture which I want.
Same here
16:18 doubt ?? 3 ko 5 se divide pe 3 kaise aaya remainder????
Haan yaar
Aur yske pichhale waale me bhi yahi Kiye hain...
Jab 16 ko 33 se divide Kiya..
🙄🤔🤔
3 ko 5 se divide karenge to negative concept ke hisaab se -2 aayega lekin sir ne pehle trivk bataya tha ki add the divisor into negative remainder and it'll be your positive real remainder
So 3 divided by 5 is equal to -2 then add +5 and -2 you will get +3 and that is remainder
sir awesome logic
thnku so so much
waiting for more such videos
specially on pnc and ap
a day before jee exam . trick may help me a lot.
Vai kal to 23 tarikh hain 😂
Chamka...🙇🌟🌟✨
Sir plzz make a playlist of crack in seconds....🙏🙏🙏
Awesome trick , Awesome method,
Awesome teacher.
Sir can you tell how to find remainder of 2023²⁰²³/35 by this method? JEE ka hi pyq hai
Bhai aage bdhte Jana hai 1 nhi BN Raha to 2 ya 3 ka hi vo power leke use solve kro , wahi to sikha rehe sir ki sirf remainders ke form me kake solve kr rehe . Dividend ka jo power hai use jo remainder aaraha smallest uske upar power laga k aage bdho
Very helpful for jee 2023 aspirants
One of the easiest trick you have provided gratitude and appreciation to you from deep of my heart....
Sir please bring more tricks like this superb trick👍👍
Sir { 13^239 is divided by 16 than find the remainder } it's remainder should be 13 . Please check this one also . Sir you are great in teaching . It's a request to you please 1 time check these 2 Questions💖😇🤗
Na bhai, 5 hi aa raha h
Bro answer 5 hi ayega Teri koi mistake ho rahi hogu
@@DhruvPatel-qe2yw 13 is the ans
@@yashvardhansaini7178 5 kaha se aya bro
@@om3g456 bhai nearest no. Se divide krte h , bataya toh sir ne concept of negative reminder iss hisab se 32 nearest no. So 5 is the answer
Sir made a short trick video of binomial for which number comes at unit place and tense place... So on
Superb sir..
Incredible explanation sir ...listening to your class for first time...
Thank you soo much sir for this trick 🙏🏻🙏🏻
I was literally shocked when the ans came in seconds
Sir you are the best! Aap jaise padhate ho waise sab kuch samaj ata hai!
12,1,17,1 : answers
Sir your trick is superb and easy thank you sir.
I am studying in class 10th
Thank you sir for this short cut ☺️
Thank you sir this concept is very much useful
Watching after sir 45 days crash course.
no more revlevant anymore...... post jee 2022, remainder questions are not coming as simple back then so learn the og method now.... if you dont believe try this trick on 22/23 jee remainder ques...
I have not read this topic but still can understand everything great
Really nice 👌👍 trick
Legends know that answer sir had already taught this in unacademy Jee 1.0
in programming its a simple concept (a*b)%m=((a%m)*(b%m))%m where, a%m means remainder of a and b ; % is modulo operator and its also distributive in addition as well so (a+b)%m=(a%m+b%m)%m
(2023)^2023÷ 35 ka remainder kaise nikalenge isse???
ITS JUST AWESOME ....... IF WATCH IN 2X SPEED WHILE DOING PROBLEMS ITS LIT
❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️i can't express my happiness after learning this trick✨✨
Sir 16 divided by 33 jab 16 kese aayega -17 aayega na
Now this is became a "HOT SHOT" topic in jee mains
How to decide when to take + rem and when - rem
jo easy lage
thank u sir for clear expainations like this
What about (1576)^1989 divisible by 9?
1
1
@@apoorvasingh1981 how ??
Mostly question ask these types like 222^ 2223 then how will solve it
@@Chauhan089 pahele sabko alag all likh do aur phir karo
Thanks sir i hope u will bring more tricks like this 😍😍😍😍
2023 raise to the power 2023 divided by 35 find remainder?....How can we do this?.... Asked in this year's Mains
nahi hote kaafi questions is method se
@@jote0924 ho jaata hai bhai
By chance kuch questions na bane
@@ShivamsinghRajpoot-jc5pd agar divisor bada ho toh nahi lagta, 2023 ke 2-3 question mein 25 35 jaise divisor hain, usmein nahi lagta yeh
Applying congruences will be more simplier
Yaay!! Crack in Seconds is back...🤩🤩
basically congruence modulo arithmetic use ho rha hai
Literally 10 min. Ka advertising 🤯
Hats off unacademy. 😅
12 min ka
Then how to solve if divisor is greater than divident..If anyone know please give me reply.for example..9^16+6/8. & 4^1000/7.&16^3/70like this kind of problems.
Sir repeatedly asked questions in jee 2k22 . Kon kon 4 mark fixe karny aay ho 2k22 m.
thank you so much sir you made my day...
18:09 that's the question which i was looking for💀
Extremely thankful to you
I have mastered this topic using help of this video 🎉
bhai mera ek doubt please solve kar do. Hame hamesha +1 ya -1 remainder banana hai ya jitna close ayye in -ve or +ve.
Doesn't matter jo magnitude wise sabse paas me ho usse lete@@praduamnshukla5867
But sir is trick se big question like (2021)^3762÷17 ka answer kese aayega ?
Mera to nhi aa rha
Its applicable..4
@@Dororo_Haro how?
Unbelievable sir , no words 😮😮😮😮😊😊😊😊
Sirrrr gazab method u have telled us though i have just entered in 11 i found it one of most hard topics but u have provedcit one of the easiest thanks
Now the year is 2023 and jee direct asked remainder question ..... Thanks sir❤
Who is watching after giving June attempt 😂
Super sir very very useful to us