Half Wave Rectifiers
ฝัง
- เผยแพร่เมื่อ 24 พ.ค. 2018
- This electronics video provides a basic introduction into half wave rectifiers which convert an AC sine wave signal into a half wave pulsating DC signal using a transformer, a diode, & a load resistor.
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I'm watching this during my finals week. I wish i had watched these early on in the semester. Such a better understanding vs in class.
noob
@@gokulsehgal9372 How so? I think finding a good resource and making a decision to use it over a bad resource is a very non-noob thing to do...
How did your finals go?
@@PunmasterSTP no
@@gokulsehgal9372 No what?
After your wonderful description of the circuit, I wasn't quite sure what the rest of the video would have in store. But thanks so much for going through the derivations behind converting from rms to peak and finding the average power. You always go above and beyond in your videos!
thank you so much mr tutor
you've been a help in every subject for so many years
We’ve literally went through this today in class. My professor gave us half wave, full wave, and bridge all in one. I was lost these videos are helping me pass 😭
Watching this 30 minutes before my paper😂😂
I swear I'm doing the same and it's exactly 30 min to my exam 😂😂😂
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@@Seig_TCG btw I got 16/20 in the exam, thanks to the video :)
Oh my gosh, the same goes.....
Congratulations, I guess@@Galaktica74
Thanks for explaining the Cal part. It shined some light on the whole Vavg part.
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Hey organic chemistry can u plz make a full video on all parts of half and full wave rectifier like about piv , ripplr factor,form factor etc. Plz
Physics exam in 3 hrs. This channel iss reallly nicee forr revising stuff.
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I'm learning so much with this playlist. So to reverse the polarity of a circuit means to change the direction of current flow?
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If there is a reverse-biased diode and current is flowing anti-clockwise then the peak voltage would be across resistor or diode?
I mean in forward-biased we used peak voltage across the resistor for finding average peak but in case of reverse-biased, the current would first pass through the resistor and then diode so would we calculate final peak voltage across diode or resistor for average peak?
Thank you!
Man, God bless you❤❤
Thanks!
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The calculus solution was interesting.
Where are you???
i think you use the rms formula of full wave, rms=vm/2 is for half wave and rms=vm/2 for half wave
God...this was very understandable
It would be a neat addition if you quickly explained why the transformer yields a counter-rotational current in relation to the input by for instance drawing a quick transformer with a core and two coils and by lenz law making a quick yet deep demonstration for why. Not trying to be a besserwisser, because theres only one here who knows best - you. Still amazziiiing videos.
thanks
In my EE class I was taught to convert the peak pulsating DC voltage to an RMS value by multiplying by .707, then multiplying by .45 for half wave and .9 for full wave. Any reason this could be?
it's the same thing. .45 comes from sqrt(2)/pi. .707 is 1/sqrt(2). that is some dumb math since you're cancelling out the root, dividing by pi is the same.
1/√2 = 0,707. in your case you divide the peak / ,0707 or you can aslo multiplie the peak at √2
This is such a great explanation.The conventional book used in my curriculum(Indian) is pathetic!!Anyone else here agreeing with me?
in finals week on my first semester, can't say I don't agree lol
Sehr gut
can you made some videos on FET MOSFET DIA TRIAC IGPT
Question? - I have circuit diagram from 2005-2008. It has DC to AC Inverter of 120v AC output hooked with diode on each secondary line , that is reversed polarity .( Both different) one way , then other way. My test meter reads both on AC and DC . How do I get proper reading across load resistor on multi meter? This is not supposed to be clipping circuit of very low voltage. Circuit load on paper was inductor coil, diodes and and resistor.
Hello!
You are the best ❤ but please I need you to solve series exercise on both half wave and full wave rectifier.
Please I should have exams next week.
@innovator from Sierra Leone
This vid is better than my lecturer
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Sir at: 7:17 are you sure that the Vs peak = Vsrms x 0.707 is correct ? Because the form is:
Vrms = Vpeak x 0.707
In class, I got the formula Vrms = Vpeak / sqrt2 since his calculation checks out from what I got
Except the diode is drawn backward...When I was in Electronic Technology, many moons ago...there were two ways to look at a circuit - Conventional, where a circuit was traced positive to negative and how schematics are drawn - and/or Electron Flow, where the electrons actually flow from neg. to pos.
Conventional direction of tracing a circuit was with the arrow... however, electron flow was actually against the arrow.
So, when you are referencing actual current flow in a circuit, it should be against the arrow. That way, everyone is on the same page, resulting in less chance of confusion.
But if you are using the conventional method, it should be noted... still, at least the blue arrow should be pointing the other way @ 1:30.
Omg thankss I was so confused on that
I dont know where you are in the world but where I am (nyc) electricians aren't taught electron flow, only engineers know about that. most electricians automatically assume that were talking conventional flow.
the rms value of HWR is Vrms = Vm/ 2
So, what's the resistor do?
How about a halfwave rectifier with capacitor filter?
Thank you Jesus Christ My lord and Savior ❤️💯
I see a problem. You integrated from 0 to pi, so the second half in a full wave is already deleted. It should still be 2x Vpeak.
A thousand likes!
Why does the graph of the V changes ?
Ain't the graph changes due to the diode which makes the circuit if it's opened then closed so the current is affected?
So why the V isn't a normal Ac graph
Pls how are you able to know everything??
Where is the full video
Why we use a resistor in series of the out put?? What will happen if I don't add that resistor and simply use the out put.
Its a resistive load(A load(electrical) is anything that consumes electrical power). A light bulb is an example and a heater. www.theelectricalguy.in/tutorials/types-of-electrical-load-resistive-inductive-capacitive-load/
The primary side current of the transformer can not be sinosuidal.
Watch before a long quiz😅😂
Hello Der
Wow calculus
What about the drawing.. I will write the peak value?
Why did you multiply Vs RMS and the square-root of 2.
it's the formula of rms ,i not quite sure how its work,but wiki rms will give you the answer
What's the use of the Resistor there???? Can someone explain please
Its a resistive load(A load(electrical) is anything that consumes electrical power). A light bulb is an example and a heater. www.theelectricalguy.in/tutorials/types-of-electrical-load-resistive-inductive-capacitive-load/
To drop voltage
why do you multiply by square root 2
because it is the same as u divide the rms voltage on 0,707 . 1/√2 = 0.707 also
Conventional flow is fucking me over here
thank u organic chem tutor lets make out
im not an electrician, but why do we need the transformer?
10:08 woahh i didnt come for this make it stop
Where did he get 18.15V? Was it supposed to be 18.85V?
18.85 is peak at secondary, you lose 0.7V over the diode and the reading at A and B is that peak.
Why you are multiplying by √2, if it is half wave it should multiply by 2 to get the Vm. You can multiply it by √2 if it is full wave.
@sudhanshu prakash i dont actually get it, if it its vm/2 after the diode then the Voutput should be vm/2
“Transforma”🤣🤣
5 minutes to exams
Wrong my god the positive side blocks current you said it takes it
외국사람들은 전자하는 사람이 많구나
한국 사람들은 전자 다 포기 했는데
푸대접 당한다.
Very long story.i fell asleep.
Why bother with Puny single diode rectifiers when you can use a FOOOOOL BRIIDJ RECTIFIAAAAH
Too many adds distracts the viewer :(
This is not perfect explanation of rectifire.
Thank you sir