In my book it had |f(x)| |(g(x) - M| + |M| |f(x)-L| and then it magically become... greater than or equal to |f(x)| |g(x) - M| + ( 1 + |M|) |f(x) - L| Thank you for clearing up my confusion at 3:20 because I forgot that, in your example, L2 can be zero and so that is why we add by 1
Great proof!
In my book it had |f(x)| |(g(x) - M| + |M| |f(x)-L| and then it magically become...
greater than or equal to |f(x)| |g(x) - M| + ( 1 + |M|) |f(x) - L|
Thank you for clearing up my confusion at 3:20 because I forgot that, in your example, L2 can be zero and so that is why we add by 1
thanks a lot!!
i understand, thanks.
thank youuuu