My professor prooved the same thing to us. He skiped all the (un)necessary comments what's coming from where so I was so lost looking back at my notes. Your videos are for sure saving me :D
First I need to tell you that you have great videos with excellent explanations. These definitely make math learning interesting, enjoyable and easy to understand. The point of this comment is to let you know about a very important notation matter. When we right limit at the beginning without a parenthesis, the limit only belongs to the first term. So, the correct way to write it is to use a parenthesis around all three terms as lim{ x → 1} (x²+5x+6) = 12. Keep doing what you are doing. Thank you.
This is the best I have ever heard this concept explained. I was struggling with understanding how the proof worked for the past 2 days, and I finally understand now. Thank you!
Hey, first of all, i really like your videos. You are doing a great job! I am a fan of generalizing the epsilon-delta-criterium and give a specific formula for delta. What I found out was that, if you choose for a general x_0 (which is in this case 1 of course) the formula delta (epsilon) = - abs(x_o) - 5/2 + sqrt( epsilon + (abs(x_0) + 5/2)^2), you get a guaranteed delta for any epsilon > 0 that you choose. Thank you for your great videos again. They are very inspiring!
You are really doing an excellent explanation and thus make our life easier in understanding maths even though it is not my proffesion. Awesome! Thank you!
Can someone please explain when 9:04 he writes x+6 as 8 in the inequality. Because he showed that x+6 is less than 8, but when he inserts 8 in the epsilon inequality, he technically increased the left hand side of the inequality without increasing the right hand side (epsilon). Which makes me a little suspect on whether the inequality will hold true. I am no professor and I respect everything he does, but I get delta=epsilon/6. Please feel free to enlighten me. Cheers from Denmark
but you can't do the step at 13:20, bc you assume that delta is less than one which inplies epsilon less than 8, which doesn't therefore show FOR ALL epsilon bigger than 0.
Hello Sir, there is a mistake in this proof. You cannot replace |x+6| with 8 and be sure that 8|x-1|< E. We can take 6 instead of 8 but in that case in the last step you wont be able to replace |x+6| with 6, hence we get stuck. Could you please check for this.
this is the serious issue what am i going to tell you.... if 6 < x+6 < 8 and at the same time |x+6|.|x-1| 6 and now replace x+6 with 6 then it will be not contradict because the product of |x+6|.|x-1|
When you want to show that the left hand side is less than the right hand side, you should always increase the left hand side. So 8 and not 6 was the correct choice.
It depends on what your teacher wants. Some just want you to show there is a delta. But some want you to show that that value you found truly works. So ask the professor what they want.
This is it. Two hours of working on the same delta-epsilon problem, and this is the video that made it click for me. Thank you.
My first time to appreciate someone on TH-cam
Thanks
9:18 I did the same expression and the meme appeared! Truly magnificient! YOU GOT ME! LOVE FROM INDIA
My professor prooved the same thing to us. He skiped all the (un)necessary comments what's coming from where so I was so lost looking back at my notes. Your videos are for sure saving me :D
The explanation is all wrong.
Sir, could you recommend a better video? @@tomtomspa
@@tomtomspait’s not
You're really making our life much simpler and thanks a lot. You simplified the proofs very well.
Each video I saw about the limit using Epsilon-Delta concepts is a delight. Your explanations are clear and your proof is perfect !
Mathematics becomes easier for me because of how you explained it in such simple ways....Thank you very much
It was wrongly explained!
@@yohannesyebabe7923 I cannot believe how someone so poorly knowledgeable on limits get to wrongly explain them on yb
You are One of the Great Teachers i have ever seen Thank a lot!!!!
I actually appreciate you for the good work ,,,God bless you
A very very brilliant lecture from a genius . Thank you sir for your contribution.
First I need to tell you that you have great videos with excellent explanations. These definitely make math learning interesting, enjoyable and easy to understand. The point of this comment is to let you know about a very important notation matter. When we right limit at the beginning without a parenthesis, the limit only belongs to the first term. So, the correct way to write it is to use a parenthesis around all three terms as lim{ x → 1} (x²+5x+6) = 12. Keep doing what you are doing. Thank you.
Unfortunately that's the least serious error of the video.
I spent an hour working on one of these proofs and this video was the one that showed me how to replace the factored part (|x + 6|). Thank you so much
This is the best I have ever heard this concept explained. I was struggling with understanding how the proof worked for the past 2 days, and I finally understand now. Thank you!
SO AM I FROM University of Namibia 👌👌👌👌👌👌
I love the way you are so enthusiastic about teaching!! thank you so much for the video :)
Hey, first of all, i really like your videos. You are doing a great job!
I am a fan of generalizing the epsilon-delta-criterium and give a specific formula for delta. What I found out was that, if you choose for a general x_0 (which is in this case 1 of course) the formula delta (epsilon) = - abs(x_o) - 5/2 + sqrt( epsilon + (abs(x_0) + 5/2)^2), you get a guaranteed delta for any epsilon > 0 that you choose.
Thank you for your great videos again. They are very inspiring!
You are the best math teacher that exists!
Plus the way u smile doing some cracks, while solving, its just fantastic, u wont be left with any qsn
I didnt understand anything before watching this video. but you made it way easier to understand. thank you brother
Wooow Man u the best, i actually had a crisis in understanding this, but i just grasped it easily, The best of the Bestest
Bro you are amazing , i mean you have the talent to be a teacher bc you try to understand the students❤❤
Thank you
Thank you so much for the explanation. Watched bunch of other videos and yours was the simplest to understand
You are good lecturer may the Lord Jesus bless you in all your endeavors 🙏
Your handwriting is dope sir and I love the way you have explained.
Thank you!
OMG !! You are an amazing teacher. Thank you so much 🙏
I’ve been trying to understand this for a lot and is the first time I feel like I get it.
You my friend are an excellent tutor. Great job on Precise Definition of a Limit !!! Keep up the good work....sorry... Great Work.
You are really doing an excellent explanation and thus make our life easier in understanding maths even though it is not my proffesion. Awesome! Thank you!
best video on the subject so far.
thank you very much i was really confused on this delta and epsilon proofs you just made my day,thank you sir
Even i can miss up a class,, its okay with this handful of skills, i really appreciate you.
It's Amazing. I watched many videos but after watching this video I understood the math well.
Your enthusiam for maths makes me like it
Your videos are better enough. Thank a lot sir
You are amazing bro! You teach math as if math is your friend and you are introducing me to him 🤣
I understood this today 😢
You are a great teacher 👏
you are a genius ,thanks for your support
Like how you explain it my brother.much appreciated.
Bro keep uploading...Love from Bangladesh 🇧🇩
You are a Geneous sir...Excellent in making mathematics simple ..very good in explaining
I want to be a genius. It's just hard 😪 🤣
Damn , that's some quality teaching .
Very helpful master ❤❤❤ from India.
A big thank you! I love how you teach, makes me enjoy more solving hahaha.
J has to pass my Calculus I course knowing that i will fail in every question of this type. Great explanation!!! Thank you
The proof has fundamental error!
The correct proof is as follows
Let f(x)=x^2+5x+6
We want to show lim x->1 {(f(x))}=12
For all e>0 whenever |f(x)-12|
Thanks a lot buddy! ✌🏻💚
This comment deserves a lot more likes.
Why would you need this type of math
@@brendawilliams8062 It is the rigorous mathematical analysis called the epsolon delta techniques.
@@yohannesyebabe7923 thx. , but what can you do with it
@@brendawilliams8062 To prove mathematical theorem.
Never Stop Teaching!
I didn't get why did you replace the x+6 with 8 and not 7 or 6 or 6.5 where did the 8 come from
your videos are very interesting keep going on !
You're so talented
Can someone please explain when 9:04 he writes x+6 as 8 in the inequality. Because he showed that x+6 is less than 8, but when he inserts 8 in the epsilon inequality, he technically increased the left hand side of the inequality without increasing the right hand side (epsilon). Which makes me a little suspect on whether the inequality will hold true. I am no professor and I respect everything he does, but I get delta=epsilon/6.
Please feel free to enlighten me. Cheers from Denmark
By far best explained thankyou
Glad it helped
Thank you very much sir
❤ From india 🇮🇳
I like his content for sure
dude you're a genius! :) tysmmm
THANK YOU SO SO SO MUCH YOU HELP ME A LOT A REALLY LOVE YOUR EXPLANATION
Great video! Thanks. It would be nice to add some graphics to bring this concept to clarity.
He does it again! Bam! QED! 😃
Bravissimo.
Con te e con Robert Ghrist la matematica è un incanto.
Grazie 😊😊
why x-6 cannot be replaced with 7? it is smaller than 8 how we replaced that?
I finally understand this brother thanks a lot
wow superb sir ❤
holy shit you saved my life here
really exciting
thank you so much sir, it really helps me a lot. And now, maybe I can answer our exam tomorrow hhahhaha
Good luck
God bless your soul. Thank you
Amen
Best love from India❤
Respect from Cameroon +237, 3:19 🎉🎉🎉
Why do we replace x+6 with 8? How does it still hold the inequality I x+6I I x-1I < ε?
but you can't do the step at 13:20, bc you assume that delta is less than one which inplies epsilon less than 8, which doesn't therefore show FOR ALL epsilon bigger than 0.
Can you please try this problem
Use Epsolon delta Def to show that
Lim x-->-1.(2x+3)/(x+2)=1
Love that t-shirt!
Very good sir love from antartica
Thank you so much for the very clarification🎉❤
Thanks man, I finally got it
Glad it helped
Hello Sir, there is a mistake in this proof. You cannot replace |x+6| with 8 and be sure that 8|x-1|< E. We can take 6 instead of 8 but in that case in the last step you wont be able to replace |x+6| with 6, hence we get stuck. Could you please check for this.
That's exactly what I also figured out...👍
We may take delta=min{1, epsilon/8}
Truly amazing
Man u save my life
this is the serious issue what am i going to tell you....
if 6 < x+6 < 8 and at the same time |x+6|.|x-1| 6
and now replace x+6 with 6 then it will be not contradict because
the product of |x+6|.|x-1|
i dont know you are looking for this or not.....
i hv figured out the mistake..
you should not start with lx^2 +5x-6l
Yes you are right. I spotted that straight away.
When you want to show that the left hand side is less than the right hand side, you should always increase the left hand side. So 8 and not 6 was the correct choice.
So helpful sir amazing ❤
Do you have calculus 1 playlist?
holy crap u saved me brotha
Great teacher! Thanks...
AWESOME SIR YOU ARE JUST A GREAT MAN THNX A LOT SIR
Ohh you are so so good❤
What if I have the same equation and the denominator is same to one of the denominator
wow u r great man
in the second part can we not substitute delta = epsilon/8 into |(x-1)|< delta for the proof to be satisfied.
It depends on what your teacher wants. Some just want you to show there is a delta. But some want you to show that that value you found truly works. So ask the professor what they want.
@@PrimeNewtons thanks professor.
8:58
We substituted 8 because we
|x-1
What if you are asked to proof lim
X--2 2x² +3 =11 .
How can I go about it?
Why did we add 7 to 1 and -1?
Nice explanation
8:40 no i dont get that. Why does that work? Why does replacing |x+6| by 8 as a result of that inequality work?
It doesn't have to be 8. You could use another constant. Just keep track.
@@PrimeNewtons I get that part. I'm just wondering how replacing it by 8 keeps the inequality the same!
nvm im so stupid.
If ab
Yes
Correct!
That is easy and clear , do you do one to one tour ?
Yes. Please send me an email
what a nice video to watch
well taught sir
Do we need to delta=min(1,epsilon/8).Because we do not know what the epsilon is.Maybe 1 is less than the epsilon?
Yes
Sir which camera are you using
Thanks so much 🙏
Love❤ from India
U're genius
I love it 🎉
when you found that 6 < x+6 < 8, why cant you replace x+8 with 6