i am literally a student studying astrophysics at The University of Chicago, and let me tell you. this cleared up what I did not understand for three weeks in my calculus class
You're a fantastic teacher! Thank you! I have read this proof over-and-over in multiple calculus textbooks (Thomas, Stewart, Larson, Hughes-Hallett ...) without a clue as to what's happening, and finally understand it after your video. Outstanding job.
Put off doing this because WebWork didn't have these kinds of problems and our professor made them optional. Forgot he said this was fair game for the quiz this week week and my knowledge of limit proofs were super fuzzy but this 100% helped. Thanks!
Using similar straight forward methodology could u do few harder exercises like rational functions, squares, cubes, trig. square roots, polynomial, trinomials, M & N? Thanks
Thanks, the algebra is rather straight forwards, however the instructor failed to show why delta and epsilon predicate will be a proof of the limit. This will required perhaps some graphics . Thanks
My teacher was makes no sense and doesn't explain and I've watched multiple youtube videos to try to understand one little step in the proof and you just helped so much.... and you're hot so it's a win-win!
@@athenkosifeni910 I think it's like when there is |-1 * x|, which would equal |-x| but the absolute value will make any |-x| = x. That's why he was ok with turning the -2 inside |-2 * (x-3)| to |2 * (x -3)|, because anything negative inside the absolute value would turn positive anyway. I hope this helps.
Also due to how absolute values work, if it did turn to -2|x-3| and you divided both sides by -2, the inequality sign would have to flip, so having the 2 be positive allows |x-3| to still be less than epsilon
This was the only video I could find that helped me understand epsilon-delta limits. Thank you!
Literally a f****** g****** godsend thank you sir!
same for me
I've been reading for two hours and I didn't understand anything, but now, 😁
Same here. Thank you sir!
Legend out there with a calculus exam in the morning
I am that legend.
Thank you for this video. the book didnt explain why the proof worked in a way i could understand. your explanation helped it click. Thank you!
Thank you so much for providing a very concise explanation on how to solve these. Text book was so confusing.
5:46 Me until the end of Examination
lmao relatable
😂
I have to admit I zoned out in class and had no idea how to do this, thank you this video was a life saver
i am literally a student studying astrophysics at The University of Chicago, and let me tell you. this cleared up what I did not understand for three weeks in my calculus class
Hey! You were my professor when I took Algebra! Now I'm watching you for Calculus!
Woah... at where?
Woah... at where?
Woah... at where?
@@princeagamah7496 woah.... at where?
@@asphyszn Woah… at where?
You're a fantastic teacher! Thank you! I have read this proof over-and-over in multiple calculus textbooks (Thomas, Stewart, Larson, Hughes-Hallett ...) without a clue as to what's happening, and finally understand it after your video. Outstanding job.
Put off doing this because WebWork didn't have these kinds of problems and our professor made them optional. Forgot he said this was fair game for the quiz this week week and my knowledge of limit proofs were super fuzzy but this 100% helped. Thanks!
There are some good videos that explain epsilon-delta visually, but this one excels at just doing the problem and making it understandable.
I think I finally understand how to prove thanks to you... Am so thankful to you..
This guy saved my life. Calculus would have killed me if not for these videos.
simple epsilon/delta=f'(a)
Thank you so much we for making me understand everything even if they can bring a test tomorrow I will get 100%
you need to clarify the content
Best explanation of epsilon-delta that I have seen. Thank you.
You are fantastic teacher in the world❤
This is one of a rare kind videos on YT
i'm just a little confused on the last part of the proof...I'll try again
Thank you for going over the proof in detail
Thank you for your help! Would you proof this question by using epsilon and delta definition. Limit x approaches 1 ( 5x^5+4x^3+x^2+x+1=12
simple epsilon/delta=f'(a)
epsilon=40delta
bruh thats it im working construction
Thank you so much. This was helpful
Samet acay sadakatini takdir ediyor.
Thanks so much! This was such a brilliant and easy to understand explanation.
If(x) - 5l
You have the capacity to create awareness .You are real supporter ❤❤ thank you a lot.
Thank you very much and we hop more video for this object..st sequence convergenc.....
Thank you!
before 3years....and very useful until the math die🙃
What if the x tends to infinity ?
Very intuitive, thank you
please Mr do another when given cube roots and difference of two squares
Using similar straight forward methodology could u do few harder exercises like rational functions, squares, cubes, trig. square roots, polynomial, trinomials, M & N? Thanks
Thank you very much
Thank you sir ❤️
Thanks, the algebra is rather straight forwards, however the instructor failed to show why delta and epsilon predicate will be a proof of the limit. This will required perhaps some graphics . Thanks
This has puzzled me and everyone in my class for months. But this video made it easy. Wth the calculus book suck sometimes.
the books assume you’re an expert in algebra and will understand everything first try. even the professors dont follow the books
OMG, thank you for making this. You explained it so clearly ❤❤
My teacher was makes no sense and doesn't explain and I've watched multiple youtube videos to try to understand one little step in the proof and you just helped so much.... and you're hot so it's a win-win!
Do you need to show the "scratch work" on the exams, or is showing the proof enough?
Cause then the delta would kinda magically appear.
In the "proof phase" with "assume" you really should've put |x-3| < delta = epsilon/2.
thanks for clear explanation
perfect video, it saves my life
You look like doctor strange
Thank you so much, God bless you and your work!
great,thank you sir
this was kind of an asmr lol, great video
cool!, thanks you very much for explanation
thank you😍
this video helped me alot! thank you
Thank you so much! Your videos are extremely helpful!
Great video! Helped clarify the subject.
All you guys from UvA... I know your pain...
Two kinds of δ: δ and Ꮄ
Kifflom
Love from india
osu mania reference
i started stressing out when he told me to remember epsilon over 2
I fucking love you sooooooo much you are my fking savior
clear explanation....do a video on proving a unique fixed point please
what is 2 times epsilon over 2 less than?
i’m so cooked
very farrious
Thank you for this video!
thank you
So clutch
oh my lord this man is a god amongst man
Beautifully shown!
Shermuta
Thanks Prof 😌
Great video, this really clicked for me. I appreciate it.
شكرا لك يا بروفسور❤❤❤
This video is an absolute godsend. Thank you!
Good explanation!
عراقي،🇮🇶🇮🇶
Ευχαριστώ πολύ!!!
Clear, I like it❤
❤❤❤
🐻
needa nobel peace prize
Excellent!
Thank you
Very helpfull
Winderful
you made it easy
Thank you for making this video
Thank you from Brazil :)
neat. thanks Daniel!
I love your explanation on changing the sign👍
Great video 👍
simply exquisite
THANK YOU!!
Great video
Thx this helped me a lot, greetings from Puerto Rico.
Can you tell me that what should be delta value when in definition of limit when x tends to 2.
💫💥
The way you teach makes it easy ❤
simple epsilon/delta=f'(a)
A guide for repetition, not understanding
But why we changed that -2 to be +2 .... coz it cant go back to be that +6 when changed.. I didn't hear the reason...
But I get all the other steps🙏🙏
My question is why we choosing to carry on with the positive absolute value instead of the negative one we started with @ 03:45
@@athenkosifeni910 I think it's like when there is |-1 * x|, which would equal |-x| but the absolute value will make any |-x| = x. That's why he was ok with turning the -2 inside |-2 * (x-3)| to |2 * (x -3)|, because anything negative inside the absolute value would turn positive anyway. I hope this helps.
Also due to how absolute values work, if it did turn to -2|x-3| and you divided both sides by -2, the inequality sign would have to flip, so having the 2 be positive allows |x-3| to still be less than epsilon