You're a fantastic teacher! Thank you! I have read this proof over-and-over in multiple calculus textbooks (Thomas, Stewart, Larson, Hughes-Hallett ...) without a clue as to what's happening, and finally understand it after your video. Outstanding job.
I love how vertical math can illustrate equailty/parity - it is easy to understand things go down stay the same. For that very reason alone I have noticed that when you write the < 2 *(E/2) I would prefer it next to the term above it. Like the Text books illustrates - I find that the inequality is easier to understand when you don't ('page skip') in this proof. If at the end it goes < terms E = E I find the solution more satisfying. Thanks for demonstrating proper use of Negatives in Absolute Value Functions
My teacher was makes no sense and doesn't explain and I've watched multiple youtube videos to try to understand one little step in the proof and you just helped so much.... and you're hot so it's a win-win!
i am literally a student studying astrophysics at The University of Chicago, and let me tell you. this cleared up what I did not understand for three weeks in my calculus class
Put off doing this because WebWork didn't have these kinds of problems and our professor made them optional. Forgot he said this was fair game for the quiz this week week and my knowledge of limit proofs were super fuzzy but this 100% helped. Thanks!
Thanks, the algebra is rather straight forwards, however the instructor failed to show why delta and epsilon predicate will be a proof of the limit. This will required perhaps some graphics . Thanks
Using similar straight forward methodology could u do few harder exercises like rational functions, squares, cubes, trig. square roots, polynomial, trinomials, M & N? Thanks
@@athenkosifeni910 I think it's like when there is |-1 * x|, which would equal |-x| but the absolute value will make any |-x| = x. That's why he was ok with turning the -2 inside |-2 * (x-3)| to |2 * (x -3)|, because anything negative inside the absolute value would turn positive anyway. I hope this helps.
Also due to how absolute values work, if it did turn to -2|x-3| and you divided both sides by -2, the inequality sign would have to flip, so having the 2 be positive allows |x-3| to still be less than epsilon
This was the only video I could find that helped me understand epsilon-delta limits. Thank you!
Literally a f****** g****** godsend thank you sir!
same for me
I've been reading for two hours and I didn't understand anything, but now, 😁
Same here. Thank you sir!
I have to admit I zoned out in class and had no idea how to do this, thank you this video was a life saver
You're a fantastic teacher! Thank you! I have read this proof over-and-over in multiple calculus textbooks (Thomas, Stewart, Larson, Hughes-Hallett ...) without a clue as to what's happening, and finally understand it after your video. Outstanding job.
Thank you for this video. the book didnt explain why the proof worked in a way i could understand. your explanation helped it click. Thank you!
Hey! You were my professor when I took Algebra! Now I'm watching you for Calculus!
Woah... at where?
Woah... at where?
Woah... at where?
@@princeagamah7496 woah.... at where?
@@asphyszn Woah… at where?
Legend out there with a calculus exam in the morning
I am that legend.
This guy saved my life. Calculus would have killed me if not for these videos.
simple epsilon/delta=f'(a)
5:46 Me until the end of Examination
lmao relatable
😂
Best explanation of epsilon-delta that I have seen. Thank you.
Thank you so much for providing a very concise explanation on how to solve these. Text book was so confusing.
I love how vertical math can illustrate equailty/parity - it is easy to understand things go down stay the same. For that very reason alone I have noticed that when you write the < 2 *(E/2) I would prefer it next to the term above it. Like the Text books illustrates - I find that the inequality is easier to understand when you don't ('page skip') in this proof. If at the end it goes < terms E = E I find the solution more satisfying. Thanks for demonstrating proper use of Negatives in Absolute Value Functions
You are fantastic teacher in the world❤
My teacher was makes no sense and doesn't explain and I've watched multiple youtube videos to try to understand one little step in the proof and you just helped so much.... and you're hot so it's a win-win!
This has puzzled me and everyone in my class for months. But this video made it easy. Wth the calculus book suck sometimes.
the books assume you’re an expert in algebra and will understand everything first try. even the professors dont follow the books
There are some good videos that explain epsilon-delta visually, but this one excels at just doing the problem and making it understandable.
Thank you for going over the proof in detail
Well demonstrated, thank you for your work.
i am literally a student studying astrophysics at The University of Chicago, and let me tell you. this cleared up what I did not understand for three weeks in my calculus class
Put off doing this because WebWork didn't have these kinds of problems and our professor made them optional. Forgot he said this was fair game for the quiz this week week and my knowledge of limit proofs were super fuzzy but this 100% helped. Thanks!
Beautifully shown!
OMG, thank you for making this. You explained it so clearly ❤❤
I think I finally understand how to prove thanks to you... Am so thankful to you..
Thanks so much! This was such a brilliant and easy to understand explanation.
The way you teach makes it easy ❤
simple epsilon/delta=f'(a)
This video is an absolute godsend. Thank you!
This is one of a rare kind videos on YT
Thank you so much we for making me understand everything even if they can bring a test tomorrow I will get 100%
Thank you so much, God bless you and your work!
I love your explanation on changing the sign👍
clear explanation....do a video on proving a unique fixed point please
Very intuitive, thank you
Thank you so much! Your videos are extremely helpful!
Great video! Helped clarify the subject.
Great video, this really clicked for me. I appreciate it.
please Mr do another when given cube roots and difference of two squares
Thx this helped me a lot, greetings from Puerto Rico.
Can you tell me that what should be delta value when in definition of limit when x tends to 2.
Thanks, the algebra is rather straight forwards, however the instructor failed to show why delta and epsilon predicate will be a proof of the limit. This will required perhaps some graphics . Thanks
Good explanation!
If(x) - 5l
Thank you from Brazil :)
Using similar straight forward methodology could u do few harder exercises like rational functions, squares, cubes, trig. square roots, polynomial, trinomials, M & N? Thanks
شكرا لك يا بروفسور❤❤❤
oh my lord this man is a god amongst man
thanks for clear explanation
Thank you for this video!
Clear, I like it❤
Thank you so much. This was helpful
Great video 👍
this video helped me alot! thank you
this was kind of an asmr lol, great video
Thank you for your help! Would you proof this question by using epsilon and delta definition. Limit x approaches 1 ( 5x^5+4x^3+x^2+x+1=12
simple epsilon/delta=f'(a)
epsilon=40delta
Excellent!
perfect video, it saves my life
Great video
i'm just a little confused on the last part of the proof...I'll try again
simply exquisite
Thanks Prof 😌
Thank you for making this video
Thank you!
Thank you very much and we hop more video for this object..st sequence convergenc.....
cool!, thanks you very much for explanation
neat. thanks Daniel!
Do you need to show the "scratch work" on the exams, or is showing the proof enough?
Cause then the delta would kinda magically appear.
THANK YOU!!
Samet acay sadakatini takdir ediyor.
Thank you sir ❤️
i started stressing out when he told me to remember epsilon over 2
Ευχαριστώ πολύ!!!
You look like doctor strange
you need to clarify the content
Thank you very much
bruh thats it im working construction
What if the x tends to infinity ?
thank you😍
thank you
great，thank you sir
Very helpfull
So clutch
I fucking love you sooooooo much you are my fking savior
needa nobel peace prize
All you guys from UvA... I know your pain...
you made it easy
This is the method everyone teaches. I simply do not see how this is a formal proof of the original statement.
In the "proof phase" with "assume" you really should've put |x-3| < delta = epsilon/2.
What happened to 6?
what is 2 times epsilon over 2 less than?
osu mania reference
❤❤❤
💫💥
Two kinds of δ: δ and Ꮄ
Love from india
i’m so cooked
But why we changed that -2 to be +2 .... coz it cant go back to be that +6 when changed.. I didn't hear the reason...
But I get all the other steps🙏🙏
My question is why we choosing to carry on with the positive absolute value instead of the negative one we started with @ 03:45
@@athenkosifeni910 I think it's like when there is |-1 * x|, which would equal |-x| but the absolute value will make any |-x| = x. That's why he was ok with turning the -2 inside |-2 * (x-3)| to |2 * (x -3)|, because anything negative inside the absolute value would turn positive anyway. I hope this helps.
Also due to how absolute values work, if it did turn to -2|x-3| and you divided both sides by -2, the inequality sign would have to flip, so having the 2 be positive allows |x-3| to still be less than epsilon
before 3years....and very useful until the math die🙃
🐻
Kifflom
Winderful
Shermuta
very farrious