A motorcycle has to move with a constant speed on an overbridge which is in the form of a circular
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- เผยแพร่เมื่อ 14 ต.ค. 2024
- A motorcycle has to move with a constant speed on an
overbridge which is in the form of a circular arc of radius
R and has a total length L. Suppose the motorcycle
starts from the highest point. (a) What can its maximum
velocity be for which the contact with the road is not
broken at the highest point ? (b) If the motorcycle goes
at speed 1/√2 times the maximum found in part (a),
where will it lose the contact with the road ? (c) What
maximum uniform speed can it maintain on the bridge
if it does not lose contact anywhere on the bridge ?
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Sir, why we took Normal is equal to or greater than zero
Sir please answer 🙏
If n is less than zero then contact with the road is lost. So n always should be greater than or equal to zero.
@@anushkaburnwal763 sis why 0 at 0 n is break n
Bhaiya I have a doubt why you take cos theta minimum in its (c) part
N ≥ 0 kyu hua samajh hi nahi aaya
Pls try to explain this part nicely ☹️😔
Why theta(not) is not 90 ? Why don't you consider if completely circle if chapter is of circular motion .
Already discussed in the video
Your second equation is wrong because it's ucm
Yes you are right!!
I am sry it's correct
Its Ok!!
@@PhysicsWithShubham I have one doubt since the body is maintaining uniform speed then how come it be an accelerated motion I mean no tangential acceleration should act, it's given in question
@@khushisinha3705 tangential component mgsin0 will be balanced by friction if it is moving with the constant speed
@@PhysicsWithShubham then the equation should be mgsin0= force of friction
@@khushisinha3705 Yes