วีดีโอ

You should get more reach

Thank uhhhhhhhh so much ❤

Wow

Ua doing great . Keep going

how both blocks are moving with same acceleration 😢

hey! may i know if you ever studied in gagan bharti sr sec school in delhi??....i was just searching for some one

❤

Thanks Big brother .....

Samajh me nhi aaya

Why to take normal zero for not slipping ? There must be some contact for not sliping.

Sir why? There are more charges abelow the P-P' axis, than there are above it, so there will be a net force in perpendicular direction too?

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Underrated. Great explanation

Sir why was negative q charge distributed uniformly, won't it be effected by q1 charge?

The net force, including the force due to -ve charge inside, will be 0?

🙏🙏

How did you know that the force was exactly acting on that angle and not horizontal i thought it was acting horizontally and just did F=umg

Nice explanation

looking after 2 years and actually appreciate the style to teach

tqs alot bhaiya I just dint think n will be variable and got ans as 4mglu/9

tqs sir

Amazing 👏🏻👏🏻

Thank you sir

Love to see another day "aaj hame ek hcv ka question solve karna h"

Sir sin theta ku cos theta hona chahiye?

Top most point pr kinetic energy zero hogi na sir?

R-r kese nikala?

Sir work done by friction zero ku nhi h?

Sir answer 597.6j aa raha hai but HC verma mein 586 diya hai maine same process se kiya.

Can somebody please explain how is it Q1-Q2??

Change style of thumbnail to increase views ❤❤

Sir do kinetic energy is equal for equal moles of gas ?? In the same kind of questions?

Thank you so much bhaiya your videos are really helpful

😫bhaiya you're god.. waht a clarity you've on your concepts..

Sir your explanations are very helpful

Thanks sir

Thank you for the detailed explanation!

Mujhe physics theek karne se pehle English sahi karni padegi 🙃

Umbrella Or platform ko rotation opposite ku hoga?

Is he iitain

Awesome👏👏

for those who are facing problem apply wet from initaial compression of spring to natural length so that you will get horizontal v and solve it by projectile eq ...

yes sir by kinematics its easy just we have to make v f[x]] and integrate

Sir Option B is also correct alongwith option D if we consider the S1 at rest, S2 at any constant velocity such that both are parallel to the third particle moving with acceleration 4 m/s2. Option B uses the word 'may' also.

BRO U ABSOLUTELY SLAYYED THAT SOLUTION! ❤

Great

Thank u sir jo apne itne acha explanation kiya mera sara doubt khatam ho gya

exceptional. brilliant. This praise is coming from my heart.

u r telented boy .

Okay I didn't know ki if other end will connected to a light string it will act as free end 🙂 my teacher didn't tell me