Hi, so I built a similar circuit on a breadboard. Carefully measured all voltages, resistances and currents. Base current measured was 12uA. Applied all measurements to the formula. Resulting calculated base current is 12.1uA. Have to love it when the math lines up with the real world!
@@ayrtoncassar7300 That is quite kind of you to say, and usually my puns are pretty terrible. Incidentally, in case you'd be interested... th-cam.com/video/KHDBT4IWldg/w-d-xo.html
I just wanted to say thank you so much for these videos I know personally they are helping me immensely and I just want to thank you for sharing it with everyone out there and for all of your time to explain and to break it down and it's just it's a blessing I appreciate it
This is a great piece showing Thevenin's equivalent and the biasing of a transistor. I am taking Cleveland Institute of Electronics Advanced Engineering Course and will add this to the transistor books. I will teach this is Asia. I was a staff engineer/scientist at IBM with patents and recognize the great work that you have shown here. Great job.
All your videos about electrical and electronics are the best videos for learning the basics... Its not an animation its just a study in a retro style.. watching your videos and use my own note book like old school learning. Thank you so much Sir.
Thank you!!! In every tutorial finally give an explain application of that circuits, that is very useful for students and circuit builders, most of college or institutes not teaching and not telling wherever we can practically use, so i am asking... thank you once again.... for you great tutor
Personal notes: in voltage divider bias circuit Ve = Ie*Re Ie = Ic if Rth < (1+B)Re if it is not, use Ie = Ib + Ic also learned where Vb, Vc, Ve are positioned
I've been trying to solve this without find the Thevenin equivalent as was done in the video. Using KVL in the "finding the I_B" stage, I initially used: V_CC = I_1R_1 + V_BE + I_ER_E and from that have gotten as far as: I_B = (V_CC(R_2/(R_1 + R_2)) - V_BE) / ((β + 1) R_E) It's basically the same as the one that was used in the video, however I am missing a term in the denominator which is the equivalent parallel resistance between R_1 and R_2. Can someone try to point out how I could fit that in this equation? I feel like I should have included it in the initial KVL equation I used, but I don't know where (and how) it should go. EDIT: After searching a bit, I realize that the equation should've been: V_CC = I_1R_1 + I_BR_B + V_BE + I_ER_E R_B is the parallel resistance I'm missing. However, I'm still struggling to intuitively think of the *existence* of R_B along that path.
I'm not sure that the Base Voltage of 3.7 V is correct here, because it lacks the voltage input from the V-source/voltage divider. It seems that the BASE VOLTAGE is the Thevenin Equivalent voltage of 4.9V. It can't be both, and 4.9V satisfies the KVL loop for the Base-Emitter loop and represents the first entry into the big equation for Base current. The Thevenin equivalent voltage is the voltage produced by the source voltage and the voltage divider. The 3.7V value did not affect the other calculations, so I think this is a minor error. Any other input on this welcome.
Going the route of solving for VB with thevenin, then solving for VE using difference between base and emitter voltage, then using the drop over the emitter resistor to solve for emitter current, then finally solving for IB and IC using beta relations will get you a vastly different answer. Why is that?
wow, is the formula for Ib given on exams or must you derive it? I doubt I could remember it. Also I'm glad he did another example with thevenin voltages and thevenin resistors. I was not sure how to apply them to a real example. So overall awesome lecture!!!!
Firstly thank you for the great tutorial secondly if we calculated the half of Ic saturation it won't equal Ic of this circuit so does that mean it ain't a midpoint biased circuit or is it that my calculations are wrong or is there some other thing i don't know ?
Think about what happens at the nodes where two transistors are in parallel. How are the currents and voltages related? Try to use Ohm's law and Kirchhoff's current law to find the total current across both resistors, and then the equivalent resistance would be R_equivalent = V/I_total.
It seems that we assume B=200 holds for the circuits. Does anyone know why we can confidently use B=200? Or in other words, how do i know that the circuit is running in the active zone before i start solving it?
The beta is determined by the specific transistor that you use, you will have to research the part number to find it on the data sheet or calculate the value yourself.
@@brandonfd789 Thanks, Brandon! I understand that is the value specified in the data sheet. My question is more about how to determine that the transistor is working in the linear active region, so the B is perfectly 200? Why is the transistor NOT in the saturation region? Or cutoff region ?
What if we are not given the values of R1,R2,..and we have the values of B=100,VBE=0.7v,VC=8v,VE=2v and Ic=1mA...then you are asked to determine the values of R1 R2 R3 R4...how can we tackle the Question
Hello, thank you for all the videos. Can you do a video on neighbouring group participation (NGP) in organic chemistry or send me a link if you have, can't find it thank you!!!!!
😟😟😟 hi man I don't understand this calculation you are making here you plug a number and then you are leave a question mark 20900+30000=50.900+BITA+1= FROM IB 9.954*10 MA so you block this number alone but never see the account creation😠😠😠😠you confuse more people
why dont you buy something like a 40 dollar mic, it will increase your production quality immensely since audio is the most important part of the videos. Not saying you sound bad, but even a razer headset has a better microphone. Thank you for your tutoring
Final Exams and Video Playlists: www.video-tutor.net/
Hi, so I built a similar circuit on a breadboard. Carefully measured all voltages, resistances and currents. Base current measured was 12uA. Applied all measurements to the formula. Resulting calculated base current is 12.1uA. Have to love it when the math lines up with the real world!
Perhaps I'm biased, but I think these videos are some of the best on TH-cam. Keep up the amazing work!
nice pun this should have way more likes
@@ayrtoncassar7300 That is quite kind of you to say, and usually my puns are pretty terrible. Incidentally, in case you'd be interested...
th-cam.com/video/KHDBT4IWldg/w-d-xo.html
Biased😂
@@ARTIFIUSYT I'm just glad anytime someone gets a charge from one of my puns.
😂
I just wanted to say thank you so much for these videos I know personally they are helping me immensely and I just want to thank you for sharing it with everyone out there and for all of your time to explain and to break it down and it's just it's a blessing I appreciate it
Just a comment to feed the YT algorithm.
Excellent review for those of us who used to work on this stuff.
Thank you so much.
PS: Would love it if you could organise your content in topic wise playlists. That'll amplify how useful they are :)
4:08
U literally the only tutoring TH-camr that i can understand
😆😆
Yeah, most of them have such strong paccents
I've gotta say you have carried me through school and now university so thankyou!!
This is a great piece showing Thevenin's equivalent and the biasing of a transistor. I am taking Cleveland Institute of Electronics Advanced Engineering Course and will add this to the transistor books. I will teach this is Asia. I was a staff engineer/scientist at IBM with patents and recognize the great work that you have shown here. Great job.
All your videos about electrical and electronics are the best videos for learning the basics... Its not an animation its just a study in a retro style.. watching your videos and use my own note book like old school learning. Thank you so much Sir.
Thank you!!! In every tutorial finally give an explain application of that circuits, that is very useful for students and circuit builders, most of college or institutes not teaching and not telling wherever we can practically use, so i am asking... thank you once again.... for you great tutor
Very good explanation. +1 after beta was always omitted when I did this 40 odd years ago at college due to it being negligable.
Well done!
IF ONLY I COULD TREAT THIS MAN AS A SIGN OF GRATITUDE. THANK YOU FOR YOUR VIDS MAN!
I just struggle with this question. And this is a huge help. I am going to download it so I can revise it whenever I want.
Hi there, it's perfect explanation how to calculate parameters in a transistor circuit. Thank you.
Your videos are invaluable. Thanks so much.
thank you i passed my Tutorials through this Video
You are amazing! I actually understand this now!
why Vb is not the voltage divider between r1 and r2 ?
Personal notes:
in voltage divider bias circuit Ve = Ie*Re
Ie = Ic if Rth < (1+B)Re if it is not, use Ie = Ib + Ic
also learned where Vb, Vc, Ve are positioned
The derivation to Ib is awsome
Amazing tutorial! Thank you!
I've been trying to solve this without find the Thevenin equivalent as was done in the video.
Using KVL in the "finding the I_B" stage, I initially used:
V_CC = I_1R_1 + V_BE + I_ER_E
and from that have gotten as far as:
I_B = (V_CC(R_2/(R_1 + R_2)) - V_BE) / ((β + 1) R_E)
It's basically the same as the one that was used in the video, however I am missing a term in the denominator which is the equivalent parallel resistance between R_1 and R_2.
Can someone try to point out how I could fit that in this equation? I feel like I should have included it in the initial KVL equation I used, but I don't know where (and how) it should go.
EDIT: After searching a bit, I realize that the equation should've been:
V_CC = I_1R_1 + I_BR_B + V_BE + I_ER_E
R_B is the parallel resistance I'm missing. However, I'm still struggling to intuitively think of the *existence* of R_B along that path.
I'm not sure that the Base Voltage of 3.7 V is correct here, because it lacks the voltage input from the V-source/voltage divider. It seems that the BASE VOLTAGE is the Thevenin Equivalent voltage of 4.9V. It can't be both, and 4.9V satisfies the KVL loop for the Base-Emitter loop and represents the first entry into the big equation for Base current. The Thevenin equivalent voltage is the voltage produced by the source voltage and the voltage divider. The 3.7V value did not affect the other calculations, so I think this is a minor error. Any other input on this welcome.
At 3:48 for the (B+1) should it not be 200+1 rather than (20+1)?
It is good man
Excellent toutor
can someone answer this. why isnt Vb = to Vcc ( R2/(R1+R2))?
it is
Going the route of solving for VB with thevenin, then solving for VE using difference between base and emitter voltage, then using the drop over the emitter resistor to solve for emitter current, then finally solving for IB and IC using beta relations will get you a vastly different answer. Why is that?
I believe transistors are actually non-linear devices, so thevenin's theorem would not be applicable here.
This shit made no sense on my FE practice exam, thank you for the explanation.
Sir can you explain, when to use 0.6 or 0.7 when assuming value of Vbe. Thanks
It depends on the transistor that you used
wow, is the formula for Ib given on exams or must you derive it? I doubt I could remember it. Also I'm glad he did another example with thevenin voltages and thevenin resistors. I was not sure how to apply them to a real example. So overall awesome lecture!!!!
Thank you very much sir ❤
Your videos are the best. Can you please add signal voltage and current gain calculations?
Firstly thank you for the great tutorial
secondly if we calculated the half of Ic saturation it won't equal Ic of this circuit so does that mean it ain't a midpoint biased circuit or is it that my calculations are wrong or is there some other thing i don't know ?
Hello , how can i find my beta value in a BC547 Transistor?? i mean what is the value of beta if the transistor i used is BC547? Thankyou!!!
Can we able to drive a 7812 ic from a 200 volt DC supply using voltage divider rule?
Great. Explaination.
Life-saver equation!!!
Fantastic video
0:19 epic rap moment
How can you apply Voltage division rule if the exists a base current
Please reply 🙏
Something i never got. How do you derive the product over sum rule? Like, why can you only use 2 resistors for that?
Think about what happens at the nodes where two transistors are in parallel. How are the currents and voltages related? Try to use Ohm's law and Kirchhoff's current law to find the total current across both resistors, and then the equivalent resistance would be R_equivalent = V/I_total.
great video thanks a lot
I cannot thank you enough!!
Flashback to high school electronics , I took 3 years of electronics with certification.
If we have VCC on top and VEE bottom what will Vth be?
i dedicate my engineering degree to you Sir Organic Chemistry tutor
I'm looking for your video about FET
How do you find the collector current if you're not given the beta value?
Either find the beta of the transistor with a data sheet or calculate it, I cannot remember the specific formula for that.
How can I calc the resistor values??? Thx
is beta just the current through the IB resistor? 19 min
is Vth and Vb the same voltage? and if not, what is the difference?
Hello. are your playlist organized? like the first video is lesson 1 and the next video is lesson 2 like that
It seems that we assume B=200 holds for the circuits.
Does anyone know why we can confidently use B=200?
Or in other words, how do i know that the circuit is running in the active zone before i start solving it?
The beta is determined by the specific transistor that you use, you will have to research the part number to find it on the data sheet or calculate the value yourself.
@@brandonfd789 Thanks, Brandon!
I understand that is the value specified in the data sheet. My question is more about how to determine that the transistor is working in the linear active region, so the B is perfectly 200? Why is the transistor NOT in the saturation region? Or cutoff region ?
@@weisun5461 this question makes sense only for active mode transistor.
Big thanks great master! )
thank you sir
but how do i found the Ic(max) here? for example in circuit with 1 Rb, Ic(max) = Vcc / Rc. can anyone help?
😇😇😇👍👍👍🙏🙏🙏 The Best!!!!!!!!
Thanks...sir...🧡
Please what is Rb and how it's calculated
I need help. Can you solve when R1 is 180k, R2 is 60k, Rc is 14k and Re is 7k while HFE is 194
❤❤❤what will i do without you?
What if we are not given the values of R1,R2,..and we have the values of B=100,VBE=0.7v,VC=8v,VE=2v and Ic=1mA...then you are asked to determine the values of R1 R2 R3 R4...how can we tackle the Question
Does anyone know what to do if you don't have the value for R2?
Say I have a 10v source
R1 is 1k ohm
R2 is 100 ohms
RC is 10k ohm
RE is 100 ohms
IC is 10ma
Beta is 100
What’s the base voltage?
Good
Idol. Pa shout po sa next upload mo.
Hello, thank you for all the videos. Can you do a video on neighbouring group participation (NGP) in organic chemistry or send me a link if you have, can't find it thank you!!!!!
How to compute it?
How to compute what?
Helal olsun KRALLL KING
You beautiful human. :D
So, in the vase VE= 0, ib = 0 then ?
All peace from the Middle East
I got a minus value for Ib when i used the formula
My headdd🤯
why does my book have completely different equations
Pls what do you mean by thevenin resistor???
you skipped the thevenin equivalent circuit and the resulting KVL loop between the base and emitter...you simplified the calculation alot
🙏
❤
😟😟😟 hi man I don't understand this calculation you are making here you plug a number and then you are leave a question mark 20900+30000=50.900+BITA+1= FROM IB 9.954*10 MA so you block this number alone but never see the account creation😠😠😠😠you confuse more people
first!
You have complicated not simplified this one.
why dont you buy something like a 40 dollar mic, it will increase your production quality immensely since audio is the most important part of the videos. Not saying you sound bad, but even a razer headset has a better microphone. Thank you for your tutoring
He sounds great to me, perfectly clear and no distortion so I don't know what u are complaining about.