@@sujitrishikumar8621 ~[~(P d Q)] d (P c Q). (P d Q) d ( P c Q) (P c Q) d (P d Q) (P d P d Q) c ( Q d P d Q). ( Using distributive law) (P d Q) c ( P d Q)
two request : improve the presentstion skill on board ( sb kachra likhte ho pata nhi kis cheez ki jldi h ) : please focus on quality jyada jyada videos banakr paisa kamana or conecpts clear nhi krna is not a good teaching
It's 2.14 am and in mrng I have my exam and his videos saved me. Thankyou soo much sir you are a true teacher... Not even our univ. Taught as a single concept of this chapter.
@@EverythingShorts6969 no it's not right czz you have to solve it in a way you get conjunction inside the values and disjunction outside the bracket or between the values
Last questions of this session is = ~(p v q) --> (p ^ q) Solution is :- Step 1 : Use demorgans law (~p^~q) --> (p^q) Step 2: use Conditional or implies Formula ~(~p ^ ~q) v (p^q) Answer= (p^q) v (p^q) Thanks ❤
To obtain the Disjunctive Normal Form (DNF) of the expression (p ∨ q) ∨ (p ∧ q), we can follow these steps:- Step 1: Distribute the outermost disjunction over the conjunction: (p ∨ q) ∨ (p ∧ q) = ((p ∨ q) ∨ p) ∧ ((p ∨ q) ∨ q) Step 2: Apply the distributive property to each disjunction: = ((p ∨ p) ∨ q) ∧ ((p ∨ q) ∨ q) = (p ∨ q) ∧ (p ∨ q) Step 3: Simplify the expression: = p ∨ q Therefore, the Disjunctive Normal Form (DNF) of the expression (p ∨ q) ∨ (p ∧ q) is p ∨ q.
in question no 1(solution second line): pV(pV(qV(~qV~r))) can be written as pV(pV((qV~q)V~r))[associativity] which gives pV(pV~r) which gives pV~r[associativity]
Sir aap bahut achchhe se padhate hai Mujhe aapke video se bahut help milti hai free me education mil ja rha hai ye bahut badi bat hai Thank you so much sir 😊😊😊😊😊
HomeWork question obtain Disjunction Normal Form ~(pvq) -> (p^q) by double negation law ; (pvq) V (p^q) (p^q) V (pvq) by commutative law pv(pvq) ^ qv(pvq) distributive law pvp v pvq ^ pvq v qvq pvq ^ pvq pvq (idemptotent law X ^X = X)
Homework question: ~(pvq) -> (p^q) is equl to: (pvq) v (p^q) => (pv(p^q) v (qv(p^q) => (p^(pvq) v (q^(pvq) => (p^p) v(p^q) v (q^p) v (q^q) . ( I used distribution law)
@@kapilkarki2591 it'll change.. because if it's 1, next step 1 or (p^q) will be 1..(tautology) If it's 0, next step 0 or (p^q) will be p^q There's a mistake actually
Bhai aap iit jam ki taiyari kar rahe ho kya agar aap kar rahe ho to bhai mujhe aap se ek help chahiye kya aap apna contect number de sakte ho bhai please🙏
solution is (p and q ) and we can also write it as (p and q) or (q and p) by using commutive law we can replace as (p and q) and then we use idempotent law
Sir ji the playlist is amazing but i have a request kindly provide answers of the h.w questions so that we can cross verify our answer . Once again Thank you for wonderful playlist
1. Use De Morgan's Law: ~(p v q) is equivalent to ¬p ∧ ¬q. 2. Substitute the equivalence into the implication: ¬p ∧ ¬q -> (p ^ q). 3. Apply the implication rule: ¬p ∧ ¬q -> (p ^ q) is equivalent to (¬p ∧ ¬q) ∨ (p ^ q). 4. Therefore, the DNF of ~(p v q) -> (p ^ q) is (¬p ∧ ¬q) ∨ (p ^ q).
correct ans= p v q solution ~(p v q)-> (p ^ q) => (p v q) v (p ^ q) => (p v (p^q)) v (q v (p^q)) => on further solving you will get (p v q) v (p v q)=(p v q)
there is a small mistake in the question at 10:00 this question will give a tautology as the answer. But if we rewrite it as : P v (~P --> (q ^ ( q --> ~r ) ) ) ; then the ans will be : P v q v ~r
The last answer : ~( ~p ^ ~q ) v ( p ^ q ) the first part has been derived by reversing the de morgan's law. initially the answer was : ( p v q ) v ( p ^ q ) but it wasn't Disjunction between conjunction, so modified it.
those who stuck at p or q or p and q just use distributive then we get p or q or p and p or q or q then p or p=p and q or q -q and p or q and p or q use idempotent then p or q
➡ Incase you missed previous Videos of Discrete Mathematics =
Playlist of Discrete Mathematics - th-cam.com/play/PLU6SqdYcYsfJ27O0dvuMwafS3X8CecqUg.html
~(~P c ~Q) d ( P c Q )
c ---> conjunction
d ----> disjunction
Am i right sir?
Sir distributive law to padhaya nahi
@@sujitrishikumar8621 ~[~(P d Q)] d (P c Q).
(P d Q) d ( P c Q)
(P c Q) d (P d Q)
(P d P d Q) c ( Q d P d Q). ( Using distributive law)
(P d Q) c ( P d Q)
@@sujitrishikumar8621 cut the negation and you will get your answer
two request : improve the presentstion skill on board ( sb kachra likhte ho pata nhi kis cheez ki jldi h )
: please focus on quality jyada jyada videos banakr paisa kamana or conecpts clear nhi krna is not a good teaching
It's 2.14 am and in mrng I have my exam and his videos saved me. Thankyou soo much sir you are a true teacher... Not even our univ. Taught as a single concept of this chapter.
@One Handed Pro Gaming lmao
Me to
And you are not a true student 😂😂
Me bhi 12:26 am ko dekh rha..... Kl exam hai.....
~(p v q) --> (p ^ q)
~(~(p v q)) v (p ^ q)
(p v q) v (p ^ q)
p v q (Since union of a union to its intersection will give union itself)
Nice this a right answer
Nice this is right answer
that's right bro
@@EverythingShorts6969 no it's not right czz you have to solve it in a way you get conjunction inside the values and disjunction outside the bracket or between the values
answer is (p and q) or (p and q)
The answer to the last
question is (pvq)v(p^q). thank you so much for teaching sir.😊
(-p^-q)v(p^q).... is the correct ansr
@@jimmytyson6582 it's incorrect (pvq)v(p^q) is correct
@@jjjyotijain explain
@@jjjyotijain it is wrong
@@jjjyotijain DNF form mai hi nhi tumhara answer
Sir, at 9:00
p \/ (~p -> (q \/(q->r))) is not equal to p v q v ~r
Please check once and the answer will be a tautology
yes, even i am getting the same :)
same bro
yeh same
Same
Last questions of this session is = ~(p v q) --> (p ^ q)
Solution is :-
Step 1 : Use demorgans law
(~p^~q) --> (p^q)
Step 2: use Conditional or implies Formula
~(~p ^ ~q) v (p^q)
Answer= (p^q) v (p^q)
Thanks ❤
Are kaam pad leee sala BC
Further after applying the distributive law you'll get (p v q)
Your answer is wrong
P v Q v (p^Q) is the correct answer
@@suffer_of_life It is correct.
9:58 sir (true or q), true k equilant hoga na.. and then true or -r... Ese krke total true me convert ho jayega
@@pesaccounts9 galat hai bhai true hoga
tum jiyaan ho@@anshulraina1819
To obtain the Disjunctive Normal Form (DNF) of the expression (p ∨ q) ∨ (p ∧ q), we can follow these steps:-
Step 1: Distribute the outermost disjunction over the conjunction:
(p ∨ q) ∨ (p ∧ q)
= ((p ∨ q) ∨ p) ∧ ((p ∨ q) ∨ q)
Step 2: Apply the distributive property to each disjunction:
= ((p ∨ p) ∨ q) ∧ ((p ∨ q) ∨ q)
= (p ∨ q) ∧ (p ∨ q)
Step 3: Simplify the expression:
= p ∨ q
Therefore, the Disjunctive Normal Form (DNF) of the expression (p ∨ q) ∨ (p ∧ q) is p ∨ q.
(p v q) v (p v q)
step 3rd how you solved bro
@@bhupinderkumar1286 by property bro,ye ek property h -> (P^P=P)
Bro nice
@@puneetanah ok I got it bro
Answer = (p v q)
Thank you so much sir for providing very good content for college students
Mera solution to (P or Q) or (P and Q) aa rha h???
iske aage kese krna h???
@@mayankarora9546
~(P v q) ----> (p ^ q)
= ~.~ (p v q) v (p ^ q)
= p v q v p ^ q
= (p v q)
@@mayankarora9546
~~(pvq) v(p^q)
Then
[ P v(p^q) ] v [ q v(p^q) ]
Then using absorption law
[ P ] V [ q]
P v q
@@mayankarora9546 Bro iskay agay distributive law lgao ok
@@mayankarora9546 Agr nhi smjh ara you may contact me on my email I'll send you solved question so that you understand better
in question no 1(solution second line):
pV(pV(qV(~qV~r))) can be written as pV(pV((qV~q)V~r))[associativity]
which gives pV(pV~r)
which gives pV~r[associativity]
Actually it's value is just true (T). Because P v ~P is not 1 but True
Answer - (p v q)
Thank you so much sir 👌👌🙏🙏🔥🤗
Same answer
Bro _ kiu lagie hai ?
Thank you sir for helping us in prep. 3 days before exams
Ans: P v (p ^q) v q v (p ^q) for last DNF prblm
we can ignore one (p ^q) than answer becomes p v (p ^q) v q.
(pvq)v(p^q)
Aise nehi chor sakte kya?
@@parthapratimkalita983 nhi conjunction ( ^ ) k middle me disjunction hona chahie so the answer should be p v(p^q)v q Aisa hona chahie
Sir, I would like to thank you.. because of you I passed my university exam...
Bhai partyyy
To bhai phonepe kar do mujhe kuch
@@ashmitsinha3698 🤣🤣🤣
@@chhatrikumar1677 🤣
at 10:17min..... shouldn't the whole term be True as per dominant rule?
Sir aap bahut achchhe se padhate hai
Mujhe aapke video se bahut help milti hai free me education mil ja rha hai ye bahut badi bat hai
Thank you so much sir 😊😊😊😊😊
DNF= (p^q) or (p^q)
How
Use de -morgan law
HomeWork question
obtain Disjunction Normal Form ~(pvq) -> (p^q)
by double negation law ;
(pvq) V (p^q)
(p^q) V (pvq) by commutative law
pv(pvq) ^ qv(pvq) distributive law
pvp v pvq ^ pvq v qvq
pvq ^ pvq
pvq (idemptotent law X ^X = X)
bro is this DNF or CNF
@@krishnamurari5464CNF but the question was to obtain DNF so the answer is wrong
Namaskar Sir, i am from Bangladesh. i watch your classes.
you are so good sir...your classes very helpful for me. Thanks sir💗
Normal form q-dnf n(pvq)->(pdq))
Ans- apply distributive low
(Npdq)v(qdnp)
D-disjunc. N-negation
It took some time to process your solution, but it helped me thanks :)
where you have write disjunc there will be conjuction
Answer - (pvq)
Thank you so much sir 🙏🙏🙏🙏
P v q nahi aayega ???
@@Shethcodes nhi thik hai uska answer
@@bhavishratan5568 kese ???
Yes it's correct
Agar isko distributive law laga ne se
(PvQ)v(P^Q)
= (PvQvP)^(PvQvP) by idempotent law
(PvQ) ^ (PvQ) again by idempotent law
We will get
PvQ .
Homework question: ~(pvq) -> (p^q)
is equl to: (pvq) v (p^q)
=> (pv(p^q) v (qv(p^q)
=> (p^(pvq) v (q^(pvq)
=> (p^p) v(p^q) v (q^p) v (q^q) . ( I used distribution law)
Nice bro thanx👍🏻
bro please tell me how you did third step ?
wrong answer
its wrong ... negation ki precedence sbse zyada hoti hai
Wrong , union uske intersection ka union hi hota he , matlab answer p v q hoga
15:26 sir p ^ ~p should be zero, i think.. because truth table is:
p ~p p^~p
1 0 0
0 1 0
Please clear my doubt 🙂
Yes bro
Yes but it also doesn't change the ans
@@kapilkarki2591 it'll change.. because if it's 1, next step 1 or (p^q) will be 1..(tautology)
If it's 0, next step 0 or (p^q) will be p^q
There's a mistake actually
@@kapilkukkar4776 aaah
broo, I have same doubt.
Answer - (P or Q) or (P and Q)
Ye aage or hoga
Chutiyaa kiti abhas karto 😂
Bhai kaise kiya, mera to nahi aa rahi hai🤔🤔
Wrong hai ~ use bhi hatao
Wrong haii
Watching before 1 hour of exam
(p^q)v(p^q)
Sir,am also a lecturer bt am very thankful to you that ur lecturer s help s me a lot when I hv any doubts.....
Thank You Sir. It helped a lot.🙏🙇
Last ans:- (p^q)v(q^p) 16:36
one answer seems wrong at 10:18 min where you have done q v ~q =1 but then entire expression should become equal to 1 and final answer should be 1
Same doubt
this techer doesnt know what he is teaching@@rahulg1560
Thank you sir making this simple❤
sir at 10:03 you said q and negation of q is equal to 1 whether there is conjunction or disjunction between them please correct it
same problem broo
sir this series is really very helpful for revision of such boring chapter so easily
thankyou for the efforts and keep going ❤❤
You are great sir ji
Bhai aap iit jam ki taiyari kar rahe ho kya agar aap kar rahe ho to bhai mujhe aap se ek help chahiye kya aap apna contect number de sakte ho bhai please🙏
ans = PvQ
Wrong
Sir you are the best 💚💚💚💚💚
pharu sir . apke padhane ka tareeka gajab ka hai
Your teaching accent is great and thanks for questions after concepts
(p^q)√(p^q)
thank u sir playlist is awosome,,, ^we lob u
thnku so much sir i have doubt when to use distributive law and also how to know which law will be used when
solution is (p and q )
and we can also write it as (p and q) or (q and p) by using commutive law we can replace as (p and q) and then we use idempotent law
bhai dnf bola hai , cnf nahi
ye cnf hai bhai
dnf ka answer (PvQ) hai
@@trushilpatel5781 yes
normal form me implies & double implies remove karna hota h ?
Sir ji the playlist is amazing but i have a request kindly provide answers of the h.w questions so that we can cross verify our answer . Once again Thank you for wonderful playlist
at 15:14 the value of p and negation p is fi, but their is no change in answer
1. Use De Morgan's Law: ~(p v q) is equivalent to ¬p ∧ ¬q.
2. Substitute the equivalence into the implication: ¬p ∧ ¬q -> (p ^ q).
3. Apply the implication rule: ¬p ∧ ¬q -> (p ^ q) is equivalent to (¬p ∧ ¬q) ∨ (p ^ q).
4. Therefore, the DNF of ~(p v q) -> (p ^ q) is (¬p ∧ ¬q) ∨ (p ^ q).
sir ,
at 9 : 59 we know that (p v T) T
but you used ( P v T ) P
Exactly
Associative law, but sir applied distributive law ? what is the answer, it is tautology or sir is correct ?
Answer of the last question is P or q
Can you explain me bro ,, because my answer is coming wrong again and again 😐
gajab ser ke upar se gaya ekdum.
will you cover construction of parse trees?
sir at 10.23 you have made ~p v p =1 but the 1 has also made the other statement 1 but 1 was forgotten
10:01 q or negation q is true
16:30
(q^p) OR (p^q)
Sir you are God
Sir aapke videos bahut jyada helpful hain
This playlist is very helpful . Thank you very much sir.
A : (~p ^ q) or (q ^~p)
if we apply commutative law, won't this just become (~p ^ q) ? because with same statement OR just becomes idempotent law?
correct ans= p v q
solution
~(p v q)-> (p ^ q)
=> (p v q) v (p ^ q)
=> (p v (p^q)) v (q v (p^q))
=> on further solving you will get
(p v q) v (p v q)=(p v q)
very clear concept
Best CNF and dnf solutions video for me
great❤
there is a small mistake in the question at 10:00
this question will give a tautology as the answer. But if we rewrite it as : P v (~P --> (q ^ ( q --> ~r ) ) ) ;
then the ans will be : P v q v ~r
Congratulations sir 1M💫
Sir plz last problem ka and comment me dal diya kijiye check krne me easy rhta h
Is cnf and pcnf same ?
Am also trying to become teacher like you....
answer : p V q V (p and q)
is this answer correct
sir question one me hi doubt he aap distributive property kaise laga sakte ho kyunki same sign he to associative lagegi
exactly mra v ye doubt hai
thanx sir for this video
Sir cnf dnf truth table se nikal sakte hai ki nhi??
bohot bdiya lg rhi hai sir
Two distribute and one idempotent law use hoga
Super lecture....
Thank you so much sir. Series is best
sir but (Q ^ ~Q) will aways be 0
"and hoya or ho to humesha 1 hota h" isvwrong kyuki snd mein 0 hota h
Ans - P or Q or (P and Q)
Is it correct?
answer of last question is
~(pvq)->(p^q)
(pvq)v(p^q)
expand it
pvqv(p^q) it is the answer
Thanks sir
Last question answer is
(P or q) or (p and q)
Hello where are you from
( p v q ) is the answer 👍
by formula (p->q=(~pvq))
ans=~(~(pvq))v(p and q)
(pvq)v(p and q)
very halpful video for normal form
Construct the truth table for [(p→q)A-q]→-p. answer sir
Ans is. ~(~p and ~q )or(p and q)
Ek baar pura bnaa ke dikhaiye
Thank you so much sir 😊you are amazing 💓
The last answer : ~( ~p ^ ~q ) v ( p ^ q )
the first part has been derived by reversing the de morgan's law. initially the answer was : ( p v q ) v ( p ^ q )
but it wasn't Disjunction between conjunction, so modified it.
My exam start from 22 and I am here studying few topics to lessen my burden 10 days before exam.
answer is ~(~p^~q) or (p^q)
Yes sir this is equivalent
T. T
T. T
T. T
T. T
This is equivalent 🎉
Answer - P v q
sir i want principle conjunction normal form (PCNF) and principle disconjunction normal form(PDNF) topics
You are a superstar teacher.
Thanks.
good knowledge
Ans : (p or q)^(p or q) (p or q)
Thank you 😊 sir
(PUQ)U(p^q)
those who stuck at p or q or p and q just use distributive then we get p or q or p and p or q or q then p or p=p and q or q -q and p or q and p or q use idempotent then p or q
(pvq)v(p^q) (pvq)
how is qV~q equal to q isnt it equal to t
It equals to 1 but it equals to t ( btw same doubt)