Sir Q.3 mein y ki range [0,3] hi hogi..cause question mein given hai Y=√(9-x²) ....iska matlab y is equal to some positive quantity matlab y greater than 0
@@sakshigupta8324 chatgpt reply -The function you provided is a semicircle equation centered at the origin with a radius of 3. The range of this function represents the set of all possible y-values it can take. To determine the range, we need to find the minimum and maximum values of y for the given function. Since the function represents a semicircle, the y-values will range from the lowest point on the semicircle to the highest point. The lowest point occurs at the bottom of the semicircle, where x = 0. Plugging x = 0 into the equation, we get: y = √(9 - 0^2) = √9 = 3. So, the lowest y-value is 3. The highest point on the semicircle occurs at the top, where the x-coordinate is either 3 or -3. Plugging these values into the equation, we get: For x = 3: y = √(9 - 3^2) = √(9 - 9) = √0 = 0. For x = -3: y = √(9 - (-3)^2) = √(9 - 9) = √0 = 0. Therefore, the highest y-value is 0. Hence, the range of the function y = √(9 - x^2) is [0, 3]. aur waise bhi y=+√9-x2 hai toh y ki negative value consider nahi karenge
Domain = R/{5} (B) option And Range = R/{0} It takes 2 seconds to solve this question thank you so much sir for providing top notch content in free of cost 🙏🏻🙏🏻
in Q no.2 based ondomain and range there is a error in the solution for finding range, when you were applying quadratic formula , instead of 2 we have to write 2y in the denominater and the final answer of range is [ -1/2 to 1/2] -{0}.
Answer of last question should be option b as all real numbers can be placed except 5 because at 5 whole expression will tend to infinity as denominator would turn 0 but any other real value except 5 wouldn't do so Hence option b
Sir , pls make a video on metric space i.e. connected metric space , continuity in metric space and compact metric space. I'm not understanding the topics of metric space .kindly make a video on above topic . Pls sir 🙏
Sir... I am very impressed with you. And clear my concepts deeply... I Wana join your online session for prepration of higher competitive exams.. please sir 🙏 guide me how I join you.
sir an you please make some more video related to Nepal's University related topic...as I can understand the topic more by watching your video......rather than in college
@@pixie_dust2089 it is given that y = root(9-x^2), and we know that a real number under root can never be negative so we get from here that y>=0. and hence discard -ve values
Proposnal and predicate logic and trees graphs and combination bhi sir jaldi se cover kar di jiye uske bhi video share kariye sir external exam hai 26 ko 🙏
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answer will be (B) {R}/5
college me 1 lakh fees dene ke bad bhi aisa content nahi milta
Bhai barbaad ho gya hai paisa to college mai bher ker
Sahi kaha
Yes 😢😢
BSC mein 1 lakh how?
@@OmPrakashMaharana326 hlo bhai aap kaha se padhte ho
Backbenchers k masiha ho aap..
Boht ashirwad milega apko exam k ek din pehle padhne walo se..
correct ans of last ques is option (b) i.e, domain = R/{5} and range is equal to R/{0}
Ye options me divide sign kyu lgaya hai.. sir ne to esa kuchh nhi btaya
iska mtlbr ( R -5) hota hai
@@Payal_Ojha
none of these , please check Y should be
No bro domain is = R - {5}
@@Payal_Ojha real no. Maise 5 ke alawa uska meaning hai
Sir Q.3 mein y ki range [0,3] hi hogi..cause question mein given hai Y=√(9-x²) ....iska matlab y is equal to some positive quantity matlab y greater than 0
X=-3 rakhne par bhi y non negative hi hoga
@@RaghavAnand-ik8qe bhai wo domain nhi range k bare me bol rhe h
[-3,3] hoga
@@Anujmuzixyes❤❤
At 20:07 I think answer is correct because hame underroot se kabhi bhi negative value nahi milegi aur y kabhi negative nahi hoga so answer is [0,3]
Kyu for x=0 you will get +-3 na ! Then ??
@@sakshigupta8324 chatgpt reply -The function you provided is a semicircle equation centered at the origin with a radius of 3. The range of this function represents the set of all possible y-values it can take.
To determine the range, we need to find the minimum and maximum values of y for the given function.
Since the function represents a semicircle, the y-values will range from the lowest point on the semicircle to the highest point. The lowest point occurs at the bottom of the semicircle, where x = 0. Plugging x = 0 into the equation, we get:
y = √(9 - 0^2) = √9 = 3.
So, the lowest y-value is 3.
The highest point on the semicircle occurs at the top, where the x-coordinate is either 3 or -3. Plugging these values into the equation, we get:
For x = 3:
y = √(9 - 3^2) = √(9 - 9) = √0 = 0.
For x = -3:
y = √(9 - (-3)^2) = √(9 - 9) = √0 = 0.
Therefore, the highest y-value is 0.
Hence, the range of the function y = √(9 - x^2) is [0, 3]. aur waise bhi y=+√9-x2 hai toh y ki negative value consider nahi karenge
@@7paradoxgamer okok now clearr ! Thanks 😉👍
Sir you teach very well but your old video are very helpful for me ❤
Domain = R/{5} (B) option
And Range = R/{0}
It takes 2 seconds to solve this question thank you so much sir for providing top notch content in free of cost 🙏🏻🙏🏻
buddi bohot tez h tumhari
@@ayushsinghal3195I solve the question orally 😂😂
Range kese nikalenge...??
@@swatinema6342 its very easy find the value of x in equation and then check for real number
sir b hI
in Q no.2 based ondomain and range there is a error in the solution for finding range, when you were applying quadratic formula , instead of 2 we have to write 2y in the denominater and the final answer of range is [ -1/2 to 1/2] -{0}.
Thankyou brother
@@animehunter2623Yes, I also noticed it.
Domain = R/{5}
Time taken 50s
noob
Answer of last question should be option b as all real numbers can be placed except 5 because at 5 whole expression will tend to infinity as denominator would turn 0 but any other real value except 5 wouldn't do so
Hence option b
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Sir your vibes , your excitement during solving problems give me interest to do Math❤
I think u deserve more subscriber ❤❤
Critical clear ho gya sir from.this video
Sir , pls make a video on metric space i.e. connected metric space , continuity in metric space and compact metric space.
I'm not understanding the topics of metric space .kindly make a video on above topic . Pls sir 🙏
Sir g very good yar bhut samag ati ha ap ki
Thank you sir 🙏
Thankuuu so much sir 💐💐
What will be the use of this logical maths in real life,?
thank you so much sir ji aapki video bhut helpfull h 💯💯💯
thank you so much sir ji
💯💯💯💯
Thank you for your time
SIR 2 waale ques. mein part a ki range [-1/2,1/2]-{0} hogi
You are really a great teacher❤ of Mathematics
Thank you so much sir you are amazing shaandaar teacher.
Love so much Sir
Ques.2 In f(x) = x/ x²+1 , range of the function will be [-½,½] - {0}
Sir, please ensure that this is correct. 18:21
Nice respect u sir 💕
thanku sir for sharing your lot of knowledge
Excellent sir
Sir... I am very impressed with you. And clear my concepts deeply... I Wana join your online session for prepration of higher competitive exams.. please sir 🙏 guide me how I join you.
Helpful!
nice way of teaching sir. apka tarika and attitude acha lga sir.
❤❤
Super sir 🔥
R/5
sir plz upload corn
Good evening sir
THANKYOU SIR
aur sir ques 3 mein part b ki range [0,3] hi hogi
Domain = R/{5} (B) option
And Range = R/{0}
Thank you sir....................
sir an you please make some more video related to Nepal's University related topic...as I can understand the topic more by watching your video......rather than in college
domain should be [negative infinity to 4 and 6 to positive infinity] because except 5 all values satisfy the equation for a real number
Thank you sir 😄😄
Thankyou so much sirrr....🤍
Happy Teachers Day Sir
Sir AAP itna achha kaise padhate hai ❤❤
Well explained sir
Sir your are the best teacher 💫👌
Option(B ) R {5} is correct answer
explain slowly deeply and in details
Last din padhke pass krwa diya sir
R-{5} ans b solving time 15 sec
best explainationsir
Very nice sir , please Sir all lectures upload discrite mathematics
Sir answer is (b)
Sirf 1 second me answer aagaya
Amazing teaching sir ty sir
Bhai explain kr skte ho kya bhai
Sir we need video on Bsc 4th semester under guwahati university...plzzz sir 🙏🏻
B is right answer sir
In the second last question range can't be [-3,3] because according to question y will always be positive.
no it would be -3 to 3 because y value can be -3 also and we get do not get the value less than zero
@@pixie_dust2089 it is given that y = root(9-x^2), and we know that a real number under root can never be negative so we get from here that y>=0. and hence discard -ve values
agr yha pr hum z+ and z- rkhay to kya eik element positive number ka aur dusra element negative number ka le gay ye explain kijye
Ans . B) R/{5}
Please sir dynamics ke bhi videoes upload kijiye
(C)R/{-5} is the right answer ❤
This is wrong right answer is R/{5}
Thankyou sir men
option (b) is the correct answer
Kammal ka teacher hai.
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suman sir app bohot achha padha to ho yar ...
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Yar???
Suman 😂😂😂
Kya hai ye?????
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Sir can you please provide your lecture notes pdf or ppt of all videos of discrete mathematics???
Sir las vale ka answer b , R/{5}
halaaa sir❤❤
Option B 20:05
I take 3 sec
Only 2 sec answer [R\5]
Funtion samajh Aa gya
I think last question m range [-3,3] honi chahiye
Homework ans will be B) R/{5}
B(R-{5})✅✅
Correct ans of last question is b sir ji 😄
Sir f: Z to Z is not one one function. for f(x)=x^2..i think 🤔
Sir inn ki pdf kahan milegi??
B will be the ans
answer is option c
SIR 10:10 Me apne joh range likhi h voh domain honi chahiye thi set ki. Pls check it sir.🙏
nahin bro . Domain toh set A ko kahenge = {1,2,3,4} , but range un sabhi domain ke images ko range kehte hain jo {x,y,p} hai.
Range is R -{0}
Answer B 5sec
R(5)
Last answer of function is R={-5,5}
last one.. range is [0,3]
as y can't be negative. watch root over.
Answer-R/{5}
20 sec.
sir, answer of question 2 is wrong i.e. 56. It should be 52 because blue and green balls are not 12 so we cannot blindly apply pegion hole principle.
i take 10 sec for last question corect option is B
Option c= R-{5}
B
Option C.( HW ans.)
ans is B
Sir, please explain the theory of relativity...
I looked out for it on yt, lekin agar aap explain karoge to jyada easy rahega..
@VigyanRecharge
Proposnal and predicate logic and trees graphs and combination bhi sir jaldi se cover kar di jiye uske bhi video share kariye sir external exam hai 26 ko 🙏
OPTION (B) 15SEC
Sir bsc वालो की किसी दिन online class लो।।आपसे कुछ बाते करनी है ।।sir please
The answer is option (b) and time taken to solve this question is 4-5 Seconds