Topic 5.8 (Reaction Mechanism and Rate Law) If you are given a proposed mechanism in which the first step is the slow, rate-determining step, then you can determine the order with respect to each reactant by looking at the number of particles of each reactant in the slow, rate-determining step. This will help you to write the rate law for the overall reaction. Topic 5.9 (Pre-Equilibrium Approximation) It can get a little complicated to determine the rate law if you are given a proposed mechanism in which step 1 is a fast equilibrium step, followed by step 2 in which Step 2 is the slow, rate-determining step.
Good question. The answer is that step 1 could have been classified as either endothermic or exothermic. There was no information given in the question about the energy details of step 1. Therefore I just made a choice to draw step 1 as exothermic. Click on the link below, to see a picture of two different proposed energy diagrams that would both be acceptable (i.e., step 1 = exothermic or step 1 = endothermic). As long as step 1 has a higher activation energy than step 2 and the potential energy of the product (NO₂F) is lower than the potential energy of the reactants (NO₂ and F₂), each of the energy diagrams would be correct, because they address each of these these chemical concepts. bit.ly/42ePdc3
I'm studying for my unit 5 test and ts (this) is extremely helpful!
Your videos are super helpful thank you!!
Faragoat 🐐
Are there any exceptions to these rate law rules? I feel like there are lots of exceptions in Chemistry
Topic 5.8 (Reaction Mechanism and Rate Law)
If you are given a proposed mechanism in which the first step is the slow, rate-determining step, then you can determine the order with respect to each reactant by looking at the number of particles of each reactant in the slow, rate-determining step. This will help you to write the rate law for the overall reaction.
Topic 5.9 (Pre-Equilibrium Approximation)
It can get a little complicated to determine the rate law if you are given a proposed mechanism in which step 1 is a fast equilibrium step, followed by step 2 in which Step 2 is the slow, rate-determining step.
For Q16c on the diagram, how do you know to draw the end of step 1 as exothermic or endothermic given the information?
Good question. The answer is that step 1 could have been classified as either endothermic or exothermic. There was no information given in the question about the energy details of step 1. Therefore I just made a choice to draw step 1 as exothermic.
Click on the link below, to see a picture of two different proposed energy diagrams that would both be acceptable (i.e., step 1 = exothermic or step 1 = endothermic).
As long as step 1 has a higher activation energy than step 2 and the potential energy of the product (NO₂F) is lower than the potential energy of the reactants (NO₂ and F₂), each of the energy diagrams would be correct, because they address each of these these chemical concepts.
bit.ly/42ePdc3