Doppler effect: reflection off a moving object | Physics | Khan Academy
ฝัง
- เผยแพร่เมื่อ 31 ธ.ค. 2024
- Does the doppler effect still apply when sound is being reflected off a moving object? Created by David SantoPietro.
Watch the next lesson: www.khanacadem...
Missed the previous lesson? www.khanacadem...
Physics on Khan Academy: Physics is the study of the basic principles that govern the physical world around us. We'll start by looking at motion itself. Then, we'll learn about forces, momentum, energy, and other concepts in lots of different physical situations. To get the most out of physics, you'll need a solid understanding of algebra and a basic understanding of trigonometry.
About Khan Academy: Khan Academy offers practice exercises, instructional videos, and a personalized learning dashboard that empower learners to study at their own pace in and outside of the classroom. We tackle math, science, computer programming, history, art history, economics, and more. Our math missions guide learners from kindergarten to calculus using state-of-the-art, adaptive technology that identifies strengths and learning gaps. We've also partnered with institutions like NASA, The Museum of Modern Art, The California Academy of Sciences, and MIT to offer specialized content.
For free. For everyone. Forever. #YouCanLearnAnything
Subscribe to Khan Academy’s Physics channel: / channel
Subscribe to Khan Academy: www.youtube.co...
You know you are a nerd when you start calculating the change in frequency of your scream when a door is coming towards you at 30kmph.
Thank you! I got the "feel" of the concept here. Now I can solve my problem easily.
Your example was really amusing)) Hahaha)))
I really really love your explanations
Ty
nicely explained! good work man :-)
Awesome example
You’re great. Thank you
Thanks, i finally understood it. In fact the explanation is clear. Neighbors making noise at 11:22 p.m. and 4:32 a.m. are not.
love you Mr Khan
Liked this shit. Awesome.
Thanks so much.
could you please explain how you calculated the (Vs/(Vs+-Vd))? why is it the reciprocal?
Dassa F in 2nd case the door is acting as a source and man is acting as an observer.therefore Vo=0 is taken because man is at rest
u are the best
just want to acknowledge the scenario......
Why do you have to multiply by a factor
I used to work in cardiology as an ECG Technician. We had a person who did Echocardiograms. She was a Cardiac Technician. That's what I was trying to be before I decided that PRE-hospital Care was where I belong. Where most doctors aren't. Cardiologists are a different type of doctor. Dr. Cook was right when he said they talk to you any way they please and you have to get used to it. I was able to do that in Prehospital but not In-hospital care. I understand EMP's.
i would strongly recommend the author of this video to revise their Doppler shift notes - the calculations parts
this dude is hilarious
The video lecture is unclear. I solved this problem detailly.
Review for solving: photos.app.goo.gl/GtOkNQvFlyQgVpJ93
Soultion: photos.app.goo.gl/UxqAopG6UN53juzg2
btw... isn't that the equation for the period... I think you forgot to take an inverse of it. or the other video from khan academy was wrong....now I'm confused
me too.....damn this man confused the hell out of me
and im here laughing at a youtube vid years ago lmao its too funny
The best
David you got the formula for frequency and period mixed up
Nope. It's correct
but what if all this i happening in a train or on a windy day?
terrible