Lecture 32: Latches and Flip-Flops (Part II)

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  • เผยแพร่เมื่อ 5 พ.ย. 2024

ความคิดเห็น • 7

  • @ankitmishra2723
    @ankitmishra2723 4 ปีที่แล้ว +2

    Nice explanation

  • @AbhishekKumar-ft8uc
    @AbhishekKumar-ft8uc 6 หลายเดือนก่อน

    🥰 thanks sir.

  • @chetanbu7922
    @chetanbu7922 2 ปีที่แล้ว

    sir in K map how did you consider even invalid states to be in a group

  • @shubhambhardwaj2626
    @shubhambhardwaj2626 5 ปีที่แล้ว +2

    Sir, the D Flip Flop does not depend on Q(t) (Previous output)
    the characteristic equation is : Q(t+1)= D.
    It is a memory element I understand but how is it a sequential circuit ?

    • @yogeshsachdeva9566
      @yogeshsachdeva9566 5 ปีที่แล้ว

      When the clock level is 0 or 1 (apart from when it is at +ve edge) the output depends on the previous value, ie. Q(t) (no change)

    • @shubhambhardwaj2626
      @shubhambhardwaj2626 5 ปีที่แล้ว

      ​@@yogeshsachdeva9566 oh okay.
      At every positive clock edge D flip-flop sees what is the value of D, It does "store" (storing element)the value of D until the next positive edge but it does not fit in the definition of combinational circuits which is "it depends on prev and present inputs"
      To store a 0 or 1 you need to continuously provide a 0 or 1 at D ? then how is it depending on the previous output?

  • @NEXTALTERNATE
    @NEXTALTERNATE 8 หลายเดือนก่อน +2

    there is no content only copy past