last question , imp doubt. What if tail comes in 3rd throw and 4th throw(HHHT) . =TH+HT + HHT + HHHT+......+infinity. =(1/2)*(2/6) + (1/2)^2 * 2/6 +.......................... infinity =(2/6)*((1/2)/1-1/2)=2/6=1/3. where I m wrong ???????
Good evening sir my jee preparation is going well, following ur videos honestly ,sir I have a request can u make some videos on TH-cam based on examination tempramet ,last month tips regarding jee mains in January
The problem involving coin and dice, there is doubt why stop at 2 throws of coin when the sample space is {HH, HT,T1,T2,T3,T4,T5,T6}. If there is a third throw then the sample size becomes {HHH,HHT, T1,T2,T3,T4,T5,T6}. Here you see ony one T, no matter how many H before it. The sample size will always have 8 members. Like condition achived after 5 throws { HHHHH, HHHHT, T1, T2,T3,T4,T5,T6}. I wrote this down because it took me some time to comprehend this. The question being why stop at 2 throw, what if the outcome of second throw is also head ?
Sir plz complete caculus part first and plz record black room corse as early as possible plz its a humble request to u.i m dropper its my lst try plz record calculus and algebra till dec complete
I was really not able to understand conditional probability before this lecture. Thank you Sir.
last question , imp doubt. What if tail comes in 3rd throw and 4th throw(HHHT) .
=TH+HT + HHT + HHHT+......+infinity.
=(1/2)*(2/6) + (1/2)^2 * 2/6 +.......................... infinity
=(2/6)*((1/2)/1-1/2)=2/6=1/3.
where I m wrong ???????
Good evening sir my jee preparation is going well, following ur videos honestly ,sir I have a request can u make some videos on TH-cam based on examination tempramet ,last month tips regarding jee mains in January
U r the best maths teacher.Sir, there is some error page opening up whenever I click the link for the test series on your website. Please help me out
I can understand your explanations much better than my teachers at my coaching institutes.. : )
q
Sir how do u write on the board like that(reverse)
The problem involving coin and dice, there is doubt why stop at 2 throws of coin when the sample space is {HH, HT,T1,T2,T3,T4,T5,T6}. If there is a third throw then the sample size becomes {HHH,HHT, T1,T2,T3,T4,T5,T6}. Here you see ony one T, no matter how many H before it. The sample size will always have 8 members. Like condition achived after 5 throws { HHHHH, HHHHT, T1, T2,T3,T4,T5,T6}. I wrote this down because it took me some time to comprehend this. The question being why stop at 2 throw, what if the outcome of second throw is also head ?
Sir please upload new video as soon as possible.
Sir love your lectures i have one question how to you write is that a glass or something what is it
Sir how could I join yours test series for jee main jan 2019
sir 19.56 me demorgan law ka use hai na
Sir your explanation is just outstanding
Really after your lectures we don't need to memorize the theorems and are able to apply them
Really Sir you are sk good . I understand whole concept. And also question
U r lecture can make my score upto a very good rank in jee advanced
Very helpful lecture
Thank you for uploading a lecture
Sir why you are not talking about Venn diagram or tree diagram
Outstanding
I don't know how much should I thank u ❤
Excentre for jee advanced please!!
At 33:00 probability of HT will be 1/2 I think sir has done a mistake
Thank you sir
Sir plz complete caculus part first and plz record black room corse as early as possible plz its a humble request to u.i m dropper its my lst try plz record calculus and algebra till dec complete
Nice teaching sir
Sir can you please do a video with problem solving of composite functions and invertible functions.
Go to playlist of sir TH-cam Chanel and u will find it . Thank you
First view first like...😘😘😘
Thanks sir
Underestimated NCERT🙃