can u please upload more video ( m1,m2) and all remaining part of mechanics on your channel , & thank u , its very easy and clearly to understand all things,
23:25 It's weird how you consistently (erroneously) rewrite the Ad^2 as (Ad)^2 . I realize you don't calculate it that way, but weird how every time that ^2 ends up outside the parenthesis on the next line. Good video and informative though.
Q ki figure 1 & 3 aap dhyan se dekhiye wo equidistant hai about both X and Y axis Jab ki figure 2 shifted hai Y axis ke about Hence we cannot apply concept of symmetry for figure 2
15+180= 195 I think Back bearing is measured in opposite direction like if there is line AB Then to satisfy your condition 15° is the back bearing of line BA not AB
@@CivilStuff In that question I think 15 also right because they not clarify the wcb or rb system For reduced bearing system rb=wcb Is it right or wrong sir?? I answered 15
Thank u bro aap ese hi hmara support kro bhut problem aa rhi thi muje esme or haa kya aap column and struts ke bhi solutions kr ke video bna do plz 6367475871 plz help me
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Thank you so much sir isase mera aadha concept clear Ho Gaya
Aaaadha??
Baki kya samjh nahi aaya batao, i will try to help you out
Thank you so much sir ....aisob topic e onk beshi somossa cilo .....
alhamdulilah akhn onkta clear hoici
Bhaiya you cleareed all my concepts .
Thank youu soo muchh❤
Thanks for the appreciation
Nice explanation 😊😊
Continue to help students
Bhai bahut badhiya
Thank you sir
can u please upload more video ( m1,m2) and all remaining part of mechanics on your channel , & thank u , its very easy and clearly to understand all things,
I can't say about m1 m2 but I will upload the video of the mechanic soon
Plese can you say SFD and bmd brother 👐
Yes brother
Avoid background music
Ok sir
Thank you so much sir 🙏🏻❤
Most welcome
Thankyou sir
Thanks dear
Thanks sir
Welcome
Appreciate your content and teaching way. But aap aur videos kb se daaloge.
Jaise ki survey and mechanics ki 1 year pehle ki h last video. 🙏
Yes brother
I wiill start uploading the videos as soon as possible
17.8 kasa aya TYy k phle case mm
Simple stress and strain padao bhai kha ho aap
sir please do videos on centroid
Ok
Bhai kidhar ho simple stress and strain padhaoo plz
Ok brother
@@CivilStuff thanks bro the way you teach ⚡ is crazy totally understanding 🤍
Thanks for the appreciation
nice
Bro make isolated triangle
Moment of inertia de video
Ok brother
Sir plz 🙏 sfd and bmd following draw ko kaise samse basic se plz batado😓😓
Brother....actually there are some problems right now..i will definitely upload if but i need some time
Bahi 3 hour lagya samj ne me😅😅😅
Y1 kaha se nikala h top ya bottom
Agar bottom toh fir Y1 wrong h
Bottom se
Y1 galat
Kaise brother?
Why u r not uploading videos?
I am little busy right now
But soon i am going to start uploading videos again
23:25 It's weird how you consistently (erroneously) rewrite the Ad^2 as (Ad)^2 . I realize you don't calculate it that way, but weird how every time that ^2 ends up outside the parenthesis on the next line. Good video and informative though.
Sir sometimes while recording the videos i had made many mistakes.
But the calculations are done correctly.
Thanks for the appreciation.
Sir figure 2 mein symmetry ka vmcincept kio nahi kiya
Q ki figure 1 & 3 aap dhyan se dekhiye wo equidistant hai about both X and Y axis
Jab ki figure 2 shifted hai Y axis ke about
Hence we cannot apply concept of symmetry for figure 2
@@CivilStuff Sir por agr with respect to x dekhungi toh symmetry ka concept use kor sakti hu Naa fig 2 mein
I am not getting what you you are saying
@@CivilStuff Figure 2 kaise shifted hain y axis ka about boh smjha dijia plz sir
Figure 2 is not present on the global YY axis
Hence it is shifted
So we cannot use summetry concept there
👍
Sir isme Ixx2 me (h) ki kimat kyo nahi bheji???🙄
Kyuki channel section centroidal X-axis ke about Symmetrical hota hai.
Iski wajah se h ki value 0 ayegi
I think h1 is 7.2 plz once again bro
Please send your calculation on civilstuff07@gmail.com
please give your tutorial in English
Ok
If back bearing is 15 the fore bearing kitna hoga???
Ans bataiye na..xm me tha
15+180= 195
I think Back bearing is measured in opposite direction like if there is line AB
Then to satisfy your condition 15° is the back bearing of line BA not AB
@@CivilStuff In that question I think 15 also right because they not clarify the wcb or rb system
For reduced bearing system rb=wcb
Is it right or wrong sir??
I answered 15
It is true only when bearing is in 1st quadrant
In 1st quadrant rb=wcb
ah^2 is right
(ah)^2 is wrong
Sorry for the inconvenience
Bro you done a mistake its A•d2 not ( a• d)2
Yes bro you are right
@@CivilStuff but nice explanation
Bro can you plz teach simple stress and strain also
Yes why not
@@CivilStuff thanks 🙏
9:13 ?
Kuch me mtlb h
Calculations saary ghalat hai
Sorry sir
Aap ko pdana nhi aata
Q sir
Thank u bro aap ese hi hmara support kro bhut problem aa rhi thi muje esme or haa kya aap column and struts ke bhi solutions kr ke video bna do plz 6367475871 plz help me
Which type of column and strut
@@CivilStuff civil sec. Yr ki book me hai ye chapter SOM me
Brother aap muje mail kro.. Possible hua to me apko answer sendkr dunga