also find product moment of inertia and bending stress , and also find moment of inertia of Z, etc section. Thank you for clearing such type of my concept...
Bro I must say you are an amazing teacher!!! I really like your explanation ❤❤ Hat's off to your teaching 🎉 Thank you, You're a life saver, tomorrow is my civil exam 😅
Sir ek question tha agir sir ybar aise hi I section mein bhi upar ya niche Banta ho axis of symmetry se to bhi sir hum parallel axis waala ye theorem lagayenge 2nd section of area ke liye bhi alag?Matlab A2h2squared?
Iyy 2 solve karte waqt aapne jo neeche ka rectangle tha uski length 100 le li jabkibuski length 80 thi , waha h ki value 15 aayegi (40-25) ,baki sab ok hai
Sir please help Does we are applying parallel axis therom on IYY please reply🙏🙏 And on which diagram we have to apply parallel axis therom or it depends up on question ❓
Time 4 minute........2 diagram me x 2 and y2 ka distance wrong likha haii sir.......about xx and about yy axix.......x 2 =20/2 =10 and y2 =20 +60÷2 =50....ye chahiya tha
I will make separate video on Ixy. If you are pursuing engineering then i think you might not come across such problems in exam in which you have to calculate Ixy
In several videos you have done several mistakes and correction done....if possible repost with zero defect, I like but when mistakes it bring me back in rethinking
Brother moment of inertia for rectangle ka formula hai "(bd^3)/12" Now if you put the dimension of each term knowing that "12" is a constant number so it will not have any dimension. So remaining terms are b and d^3 For b the dimension is mm For d^3 the dimension will be (mm)^3 So combining bd^3 will be mm.(mm)^3 So it will become mm^4 Hope you got it If still have any doubt, feel free to ask.
Bhai app kya solution late ho kese lai khuch samj nhi aya kese nikala 😒 thoda to samjhao yrr time waste feeling a rhi he☹️✌️i am not satisfied your explanation
This is the thing that pisses me off, people like you putting tutoring videos like this in English , writing the question in English and making the title English. It's great that you are putting out these videos but if they are going to be in another language put a disclaimer in the title or at least put the title into your language instead of baiting people for clicks.
Don't forget to follow me on my personal instagram for more updates: instagram.com/kunal_badgujar_07
This lecture is far better than my college teacher teaching
Same ❤️
also find product moment of inertia and bending stress , and also find moment of inertia of Z, etc section. Thank you for clearing such type of my concept...
Will upload in the upcoming lectures
Finally I understand after spending lots of time on other lecture and theory
Superbb sir jese college me sir ne bataya tha usi tarah se aapne
Excellent sir
Thanks for the appreciation
@@CivilStuff most wlcm sir
Bro I must say you are an amazing teacher!!! I really like your explanation ❤❤ Hat's off to your teaching 🎉 Thank you, You're a life saver, tomorrow is my civil exam 😅
Thanks for the appreciation brother
Thank you so much sir 💎🙏🙂
very much thank you bro you explained it very nicely
Thanks for the appreciation
Without your help I could not have understood that 😊😃😊
To find h1 simply do ybar minus y1 and to find h2 do ybar minus y2
Correct
Thank you bro
That is correct method actually, but many of them don't follow
Iyy = 1.63x10⁶ mm⁴
You have inserted 516.67x10⁶ instead 516.67x10³
Thanks.
Yes bro
Calculation mistake ho gaya tha
Thanks for the feedback
@@CivilStuff😅😮😅😅ook
If only i could understand india
Thanks alot 🎉Nimeelewa
❤️❤️❤️👍👍👍👍 fantastic
Iyy should be 1.626 * 10^6 mm^2 addation is wrong
Answer is 1.44 × 10⁶
1.627×10^6
517.78×10⁶
Yes it is this answer
1.62×10^6 mm^4
Great
Thanks
Ans. Iyy = 1.627 x 10*6 hoga
Osum
🙂 Nice video
Thanks
@@CivilStuff sir all Diploma civil 2nd chapter teach msbt
Means?
Thank u Excellent 🎉
Sir ek question tha agir sir ybar aise hi I section mein bhi upar ya niche Banta ho axis of symmetry se to bhi sir hum parallel axis waala ye theorem lagayenge 2nd section of area ke liye bhi alag?Matlab A2h2squared?
I am not getting your question
Thanks for your information
Welcome
Iyy 2 solve karte waqt aapne jo neeche ka rectangle tha uski length 100 le li jabkibuski length 80 thi , waha h ki value 15 aayegi (40-25) ,baki sab ok hai
Ha brother. Mistake ho gyi thi.. Thank you foe the correction
Bhai 40-25 nahi 30-25 hoga na reply kar bhai 16 ko paper hai
Hello sir please post videos for barch students too you are really great teacher ❤
Sorry Brother but i have done B.Tech in Civil Engineering
Iyy answer is wrong we get 1.62x10^6mm4
Thanks you so much sir ji❤️❤️❤️🔥
Welcome
Cool language
This is the same question with same dimensions, which our college sir thaught
I used the tectboom of Engineering Mechanics by Sanju Unadkat
@@CivilStuff oh that's why. By the way thanks a lot sir
Thanks a lot bhai❤️
Welcome
Thanks Sir
Thanks
Welcome
Thanks 😊 sir ❤️ 🙇🙇🙇
Thank you so much bhaii
Welcome
Nice
Thanks bro
Thank You Sir
Welcome
Thank you sir 🙏🙏🙏
Thank you
Thankyou Sir 🥰🥰
Bro we write as IYY = db³/12 + A¹( Y bar - y)²
Pls upload videos of toss
Yes definitely brother
Thank you so much
Answer is 471.66*10^4
Yes
Brother aap kon si book se question padhate hai please bataiye
Strength of Mechanics by R S Khurmi
last IYY was wrong its 1626670 is correct
Iyy=1.626×10^6mm4
thank you sir for nice video
when you're taking area of 60×20 how come you're c.g is 25.
Y1=100/2+20=70
Tq bro
Welcome
Sir how to do if only about x-axis
Bro db³ likh k values bd³ ki kyun dal rahe ho Iyy2 mai
Sir please help
Does we are applying parallel axis therom on IYY please reply🙏🙏
And on which diagram we have to apply parallel axis therom or it depends up on question ❓
But how to find Ixy please tell me
What is Ixy brother
Diploma ka math ➗ and mechanic ka all chapter video chya 🙏🙏 and pdf bi chya ❤️❤️ from odisha
Sorry sir i'm not understand what u are speaking. Can u please speak in English
Time 4 minute........2 diagram me x 2 and y2 ka distance wrong likha haii sir.......about xx and about yy axix.......x 2 =20/2 =10 and y2 =20 +60÷2 =50....ye chahiya tha
Axis change ho gaye haii gurujii
How to calculate (I)xy
I will make separate video on Ixy.
If you are pursuing engineering then i think you might not come across such problems in exam in which you have to calculate Ixy
❤❤❤
In several videos you have done several mistakes and correction done....if possible repost with zero defect, I like but when mistakes it bring me back in rethinking
Okk brother
You can ask your doubt or share the mistakes i made in the comments, so it will also help others.
And thanks for the feedback.
Hou to calculate this problem in calculator
Yo need casio fx991ms for this
Sir calulater kase use karte hai mn me yahi nhi samjh me ata hai
Konsa padrt apko nhi smj aa raha brother
@@CivilStuffsir mai mm4 kase ata hai mujhko nhi samajh me ata 1 bar 1 qoution ko le aou calculater saman use karke dikhaye
Brother moment of inertia for rectangle ka formula hai "(bd^3)/12"
Now if you put the dimension of each term knowing that "12" is a constant number so it will not have any dimension.
So remaining terms are b and d^3
For b the dimension is mm
For d^3 the dimension will be (mm)^3
So combining bd^3 will be mm.(mm)^3
So it will become mm^4
Hope you got it
If still have any doubt, feel free to ask.
@@CivilStuffok sir
Value m bhuth difference aara
Mail your Calculation on civilstuff07@gmail.com
I will let you know
Iyy2 in h2 distrence is incorrect
भाई थोडा और मोटा पेन use kiya karo
Okk brother, next video se jarur istemal karunga... Thank you for the suggestion
Total Iyy Ki value Meri different Aa rhi h. Check it plz if possible
Brother Calculation to correct hai mera
Ap ek kam kijiya civilstuff07@gmail.com
Iss mail id ke upar apna solution send kijiye
@@CivilStuff bhai IYY wala last addition wrong hain aapka
Ha brother.. But mene video me hi edit karke correct Iyy ki value add kardi hai.. Aap check kr sakte hai
🙏🙏🙏🙏
MOI about y is wrong ans😂
Moment of inertia q nikalte koi batayega
Brother major and minor axis of bending determine karne ke liye Calculate karte hai.
Iyy1 ka answer galat hai 0.516×10^6 j
Sir App to apne hi padh rahe ho thoda slow padhayi
Next videos se slow try karunga brother
h2 me doubt hai
Yea sure
Kya doubt hai brother
U did wrong addition at last
Which one sir
Sir last one Iyy calculation is wrong.. check again sir
Please send me your calculation on civilstuff07@gmail.com
I will check it and will let you know
And thanks for the feedback
In English please
I'll try to upload my upcoming videos in English
Mera to sir Iyy=1626666.66 aa rha hai
Send your calculations on civilstuff07@gmail.com
clear nhi samajh me aa rha hai sir
Which part you did not understand?
Sir samajh nhi aara hai
Konsa part nahi samaj aaya sir
Sir moment about point ixx and iyy
Sir y2 ka value wrong hai
Iyy addition is not correct
Please send your calculations on our Instagram account or mail me on civilstuff07@gmail.com
Not understand sir
Which part you did not understand
Iyy galat solve kiya hai, video dekhne k baad comment section bhi dekha kijiye .
Could ypu please share your calculation on civilstuff07@gmail.com
Bhai app kya solution late ho kese lai khuch samj nhi aya kese nikala 😒 thoda to samjhao yrr time waste feeling a rhi he☹️✌️i am not satisfied your explanation
Konsa solution ki baat kr rahe ho sir aap
Wrong answer sir
What is wrong sir?
are bhai detail me bata na value hi direct bolra kya sikhara bhai tu
Apko konsa part me problem hai bro..me apko clear kar dunga
This is the thing that pisses me off, people like you putting tutoring videos like this in English , writing the question in English and making the title English. It's great that you are putting out these videos but if they are going to be in another language put a disclaimer in the title or at least put the title into your language instead of baiting people for clicks.
All the engineering books are written in english... So all the topic names are in English... Thats why i have to put the title descriptions in english
Iyy=1.62×10^6 mm^4
Thank you so much sir
Welcome sir
thanks bro
thanks bro
Thank you brother
Welcome
Thanks you sir ❤️
Welcome
Thank you so much sir
Welcome