Seems like a pretty easy build. Do you have a video of the build. Does it deform a lot a 90 degrees. Your definitely pushing that bar pretty easy. Nice.
@164ChopShop I want to build this. Is it fair to say that cog system is like a come along? It would probably be easy to put a motor on it going by how easy you bent it. Love the way you go about your builds.
Anyone out there that can figure this math??? Here's the dimensions of Cog wheel, sprockets and everything... The lever is 22 inches with the cog springy thing being 1 inch from lever pivot point. The wheel with the cogs is 14 inches, the first sprocket underneath is 3 inches and the final drive sprocket is 11 inches. Would love to know what kind of power is being put to the die. Lets say i am putting 100lbs of force with the lever. I'm super curious!! Thanks for watching!!!
100LBS * 21" * (14/2)*(11/3)=53900IN-LBS or 4491FT-LBS of torque at the output shaft that holds the die. If the die has a 3.5" radius then 53900IN-LBS/3.5" = 15,400 LBS
Seems like a pretty easy build. Do you have a video of the build. Does it deform a lot a 90 degrees. Your definitely pushing that bar pretty easy. Nice.
No video of the build. doesn’t deform much at all. Really smooth bends all the way to 180.
@164ChopShop I want to build this. Is it fair to say that cog system is like a come along? It would probably be easy to put a motor on it going by how easy you bent it. Love the way you go about your builds.
@@jtcustoms1182 yep. could totally do that. Thanks man
Keep in mind that the lever and cog is where the most power is produced.
@@164ChopShop thanks appreciate the reply back.
Anyone out there that can figure this math??? Here's the dimensions of Cog wheel, sprockets and everything... The lever is 22 inches with the cog springy thing being 1 inch from lever pivot point. The wheel with the cogs is 14 inches, the first sprocket underneath is 3 inches and the final drive sprocket is 11 inches. Would love to know what kind of power is being put to the die. Lets say i am putting 100lbs of force with the lever. I'm super curious!! Thanks for watching!!!
100LBS * 21" * (14/2)*(11/3)=53900IN-LBS or 4491FT-LBS of torque at the output shaft that holds the die. If the die has a 3.5" radius then 53900IN-LBS/3.5" = 15,400 LBS
@@rogerthorpe6546 Now that's interesting!!! Thanks for that Roger!!
@rogerthorpe6546 I was interested in that, too. Now my head hurts. I suck at math if you didn't know. Thanks for that info. I have to try making this.