Capillary action dissected

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  • เผยแพร่เมื่อ 20 มิ.ย. 2024
  • Capillary rise in small tubes is a familiar phenomenon that most of us have seen. But why is it that water rises higher in thin tubes than in thick tubes? This animation will focus on the forces at work in capillary action and derive an equation from first principles known as Jurin’s Law. Enjoy!
    For further reading:
    en.wikipedia.org/wiki/Capilla...
    hyperleap.com/topic/Jurin's_law
    chem.libretexts.org/Bookshelv...
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ความคิดเห็น • 33

  • @fatimakhan-ei5fy
    @fatimakhan-ei5fy 2 ปีที่แล้ว +5

    woah that was very helpul, beautifuly elucidated all the concepts involving in this topic.

  • @shandusa
    @shandusa 2 ปีที่แล้ว +10

    There will a day when capillary action will power the world.

    • @h7opolo
      @h7opolo 23 วันที่ผ่านมา

      yessir.

  • @AdamaRamaWADE
    @AdamaRamaWADE 7 หลายเดือนก่อน +1

    This was such a detailed and comprehensive explanation, just what I needed! Thanks!

  • @leroyjenkinz3296
    @leroyjenkinz3296 3 หลายเดือนก่อน

    Thank you I really appreciate your video, My Current project has me running past them And I Realize, I really have no idea what they are what they do.But now you help solve that in every way possible.Thank you very much appreciate it.

  • @fatimakhan-ei5fy
    @fatimakhan-ei5fy 2 ปีที่แล้ว

    thanks for putting it up here

  • @corrrnn
    @corrrnn 2 ปีที่แล้ว

    Very helpful Mr, Thankyou ! :))

  • @ahmadsaqibqaeym1684
    @ahmadsaqibqaeym1684 ปีที่แล้ว +1

    Hello sir, I am studying bioengineering. This video was very useful to learn capillarity topics in my Fluid mechanics class.
    I really appreciate it. Thanks a lot.

    • @ScienceSketch
      @ScienceSketch  ปีที่แล้ว

      Thank you very much. Glad it was helpful!

  • @azrayks24tip
    @azrayks24tip 10 หลายเดือนก่อน

    what happens when the temperature increases? is there a decrease on capillary rise?

  • @nurrizzatimohammadzambree9553
    @nurrizzatimohammadzambree9553 ปีที่แล้ว +1

    sir, regarding the upward force section, i still don't get it why we're multiplying the circle circumferences with the constant of upward force, would u mind explain it more...

    • @ScienceSketch
      @ScienceSketch  ปีที่แล้ว +1

      Hi Xoxo, thanks for your message. The upward force is proportional to the liquid that is in contact with the surface area of the tube. The surface area of the tube increases as the circle circumference increases. At this point in the calculation we don't know exactly what the relationship is.....we just know that as one increases, the other has to increase also. Please let me know if I can explain in other ways.

  • @123hekke
    @123hekke 2 ปีที่แล้ว

    This was a great video. Thank you

    • @ScienceSketch
      @ScienceSketch  2 ปีที่แล้ว +1

      Glad you enjoyed it! Thanks for watching.

  • @XORCyst
    @XORCyst 27 วันที่ผ่านมา

    I came here because I was watching the anime “Dr. Stone” during a totally unrelated scene and I’m glad I did

  • @user-nh7gk1bw7d
    @user-nh7gk1bw7d 4 หลายเดือนก่อน

    Could melted aluminum also use the equation? for example, melted aluminum adhere to non-melted aluminum?

  • @hsb14214
    @hsb14214 2 หลายเดือนก่อน

    Very good video

  • @arashmokhtarbaf5826
    @arashmokhtarbaf5826 ปีที่แล้ว

    Very good thank U

  • @mddelman
    @mddelman 4 หลายเดือนก่อน

    Very informative video, thanks. Do you have time to answer a question for me? I have a small vessel filled with water. A thin tube (1.5mm inner diameter) hangs an arbitrary distance below the surface and the top is attached to a valve that allows me to release ink into the water. When the valve is open, ink flows freely. When I close the valve, a vacuum is created at the top of the tube, so the flow of ink stops. However, through what I assume is capillary action, water from the vessel is pulled into the tube, apparently displacing ink, which then leaks into the vessel. This continues until all of the ink in the tube has leaked out. My question is, is there any way to prevent this leakage from happening? I cannot change the viscosity of either the ink or the water. The tube could be modified if that would help, but not to the extent of using a much larger diameter tube.
    I hope you find this question interesting and I'd be most appreciative if you can answer it. Thanks very much!

    • @ScienceSketch
      @ScienceSketch  4 หลายเดือนก่อน +1

      Hi Michael, that's a really interesting observation. The water and the ink are still in contact even though the valve at the top is closed. There is no flow through the tube. Nevertheless, there could be diffusion of the ink molecules into the water vessel and diffusion of the water into the tube holding the ink. Let's do a thought experiment...if you place a capillary tube in a beaker of water, you will get a rise of water up into the capillary tube until it reaches equilibrium. At that point, there is not net flow (i.e. the level of the water does not change). But you would expect that, due to random molecular motion, there would be exchange of the water molecules from the capillary tube into the beaker and vice-versa? I think the same thing is happening with your ink in the tube. Now, how to prevent it? I have no idea. Molecules diffuse!

    • @mddelman
      @mddelman 4 หลายเดือนก่อน

      @@ScienceSketch Thanks very much for your thoughtful reply. This sounds correct. I'm not sure why I thought capillary action would occur in a tube that's already full.

  • @raghav5651
    @raghav5651 4 หลายเดือนก่อน

    thank you thank you thank you so so so muchhhh

  • @thestrongman11
    @thestrongman11 2 ปีที่แล้ว +2

    thanks for the video, I guess if the diameter in the tube is less than 0.1mm, there wouldn´t be limit for the height.

    • @v1Broadcaster
      @v1Broadcaster 11 หลายเดือนก่อน

      ah yes, vertical contact angle and infinite surface tension

  • @shubhsoni2893
    @shubhsoni2893 4 หลายเดือนก่อน

    1:02 a small mistake to point out- g is not the gravitational constant rather G is, g is the acceleration due to gravity with the value 9.8ms^-2 and G has the value 6.67*10^-11
    otherwise a good explanation

  • @akinnubisamuel968
    @akinnubisamuel968 ปีที่แล้ว

    What would happen if we performed this experiment in space?

    • @QwertyUiop-zr6pw
      @QwertyUiop-zr6pw ปีที่แล้ว

      the water would probably continue to go up, as there’s no gravity pulling it back down

    • @ahmadsaqibqaeym1684
      @ahmadsaqibqaeym1684 ปีที่แล้ว

      @@QwertyUiop-zr6pw Yes this is exactly what happens. but the moment the water left the tube it will remain still if there isn't any external force.

  • @arnokosterman231
    @arnokosterman231 ปีที่แล้ว

    Ferry wheak ❤

    • @arnokosterman231
      @arnokosterman231 ปีที่แล้ว

      th-cam.com/video/zMgpvLbqp8w/w-d-xo.html
      Where I use the word surpherts thention olso includes atmospheric pressure jad it is not pressure as it are thentional diverentional displasmends towart the aditional lobido of the behavieures of the air particles and therevcohesun magnetude of the space inbetween within and around oll participating party's 💜
      Resistance and not pressure 🙏💜🙏

  • @veracity1175
    @veracity1175 7 หลายเดือนก่อน

    Yoooooo ms tennial

  • @timoplaysclash
    @timoplaysclash 8 หลายเดือนก่อน

    i have to use this in 8th grade 😭