for people who have SAT on 5th, almost 90% of what u saw here could be done on desmos, for eg question 5 took me 30 seconds max, take supposed values of c (i took took 4) and then 2c will be 8, add these values to table in desmos and equate table to exponential equation given in the question, it will give you b which is 6, learn to play smart boys, keep ur heads up
this video covered all the topics i was struggling on! i havent been able to find other videos covering all these topics so this is a godsend haha esp bc im taking the oct5 sat tysm so youre the best
i took the october sat and this is lowk rlly good; not spot on, but most of the problem he solved were on the sat. I would argue that even though some of his predictions were not relevant to the october sat, it is imperative to know them for practice and future sat
dude this helped me so much, I just took the dsat rn. I was able to finish module two with 2 minutes left, and it was all thanks to this video. You’re a godsend bro 🙏🙏🙏
You can solve Question 5 (4:35) in less than a minute with Desmos. Enter a table with the two points exactly as given. Next, enter a slider for c and set it equal to 1 (any value will do). Then type the regression y1 ~ a^x1 - b. After that, you just replace b with each answer choice until r^2=1 (that means it's a perfect regression). This will only happen when b=6. You can also tell from the graph that b=6 because it's the only value for which the graph goes through the two points.
@@payalthakur7051 1. Graph the circle 2. Type a=-16. 3. Type (a,b). 4. Create a slider for b and change its interval from 0 to 30 (checks the whole circle). Now just change the a value in Step 2 until the point passes through the circle. It is a=-14
For Question 9 (9:51) you can literally solve in two steps with desmos. Step 1: Create a table and enter two points from the original f(x) equation. Obvious ones that you should be able to do in your head are (0,1) and (4, 1.84). Step 2: Enter the regression y1 ~ (1 + p/100)^x1. Your answer is given under REGRESSION PARAMETERS. p = 16.4674. So the answer is (A) 16. This took 15 seconds. Not showing kids how to use this amazing tool that the college board actually allows you to use during the test is borderline criminal.
@@shigeo9718the exponent becomes zero if you plug in x as zero, and anything to the power of zero is one. as for the other point mentioned since it’s x/4 if x=4 it’ll be 4/4 which equals one and anything to the power of 1 equals itself (in this case 1.84), therefore creating the pairs (0,1) and (4,1.84)
since im a little slow and dont understand this, the way i did it using desmos was: 1- put one equation as one line 2- put the other equation as another line 3- put “p” as a slider (so u can input values for p) if u dont know what the slider is, it should say “add slider: p” 4- input all answers A, B, C, D and see which p value makes the 2nd line look most similar to the first line 5- and voila! the closest line should be p=16!
@@JZTESTPrep very similar of the second one, exact same of 3, exact same of 6 too bad I didn't watch your 6th one I couldnt do it, also a similar 9 I think. I could only do 2 and 3 but thanks to you I did them so xD
You can solve question 10 in under a minute on Desmos, plug in the full equation, set a slider for p, and change the value for p multiple times until you find that the sum of the solutions is 6.67.
Bro thank you so much for this! It has helped me a lot!!! :) Could you in the future do videos on these specific problems. They were from the practice tests, and the answer explanations are confusing. Practice Test 3: #22 (1st mod) #8, #16 (2nd module hard) Practice Test 4: #15, #22 (2nd module hard) Practice Test 5: #22 (2nd module hard) Practice Test 6: #22 (2nd module hard)
Yo sup dawg this videos great, just wondering, you got any tips for writing the sats for international students? If I'm getting 790s in the practice ones will I get around the same on the real one?
Wow 790 on English is great. Seems like you got the English section down already. I would say practice test are pretty accurate so you should be good to go on test day.
Cool beans, thanks for the reply! Although I meant 790 for the math section 😅 I think I may have spoken too soon tho, took about a 3 week break from sat studying and my score dropped down to a 710😭😭 lmaooo it's the second module dude. I feel like I run out of time every single time lmao. Got any tips?
If you go to my TikTok, the video where I explain how I got an 800 has a list of the most important formulas not given. Just remember for the discriminant >0 means 2 real solutions, =0 means 1 real solution, and
Ok I notice you explain things in a way that assumes all watchers understand basic math concepts, in the future if you're ever up to it please make an in depth video for some of us
Yeah this video is for those who are mostly just struggling with the hardest question types and trying to get those last 40-50 extra points. If you don’t understand most of the basic math concepts on the SAT watching this video to study is not best way to improve your math score
If you’re looking to learn these basic math concepts I would use khan academy since it goes over pretty much all the concepts u need for the SAT. Once you’ve done that take blood test and see what types of questions ur getting wrong, only then I would I use videos like this to supplement my practice
c/a is the formula for the product of solutions. We are told that the product of solutions is kab. So we set that equal to c/a. So c=ab because it is the value of c and a=57 because it is the coefficient of a
Great question. We are given the equation a^x - b which passes through the points (c,9) and (2c,219). Since we plugged in a value of 1 for C (which is also the x-coordinate) we can plug that into the equation we were given. So we set that equation equal to our y-coordinates for both points. Then we solve for B through substitution.
Hello. I have a question. Why in question 20 AC is equal to BC. It's first time I am hearing that if they are making right angle then they are equal. Thank you
Sorry, that was my mistake. I meant to say it's because they're both radii of the circle, so AC equals BC. And because it's a right angle, we can use the Pythagorean theorem to find the length of AB.
Good questions. It is the formula for the x-coordinate of the vertex. Since we know that the x-coord is -1 at the vertex we just set -b/2a equal to -1. However what I realize now is that you don't need to do all that since you can just plug in the vertex point into the equation to find b
@@JZTESTPrepI understand how the formula for the x coordinate for the vertex point get you b. I’m now curious how you could plug in the vertex point (into the equation?) to get b since that sounds simpler. Can you explain that pls
Yeah, so our vertex is at point (-1,-8) so we could just plug that into the equation y=2x^2 + bx + c because we found the value of C already which is -6. So our equation would become -8=2(1) +b(-1) -6 and we get that b=4.
This video compiles commonly tested questions. Many people saw multiple questions in this video on August SAT. Since college board reuses the same question types you will definitely see a couple questions like the ones in this video.
The formula for the product of solutions is c/a in a quadratic equation (ax^2 + bx +c) where C is the last value of the equation and A is the coefficient of the first value of the equation.
I’m a sophomore bout to be a junior this year and I’m most lost in half of this but I have questions on how u got 49 in the first question ( I’m on question one rn) I’ll prob leave more questions I have
Good question. So when you subtract 3,136 both sides are negative. But to get both sides to be positive you can’t just ignore the - sign. You have to multiply both sides by negative 1 and when you multiply this inequality you have to flip the the direction from < to >.
If you were to leave it with negatives on both sides it would still make sense but you would have to recognize a larger negative number is actually less than a smaller negative number
If 3,136 - 64k is less than 0 then we know that 64k has to be a greater value than 3,136 since if 64k was less, those two combined would not be less than 0.
I am so sorry if this sounds rude but the writing for Question 5 is a little illegible so I am a bit unsure of what some of those numbers/variables are because I can’t quite decipher them. Can someone please rewrite it for me?
Myb ig I’ll start from (b+9)^2 - b = 219. Then I foiled it out to get b^2 + 18b + 81 - b - 219 = 0. Then I simplified to b^2 +17b - 138 = 0. Then I factored and got (b+23)(b-6) and we get our answer as b=6
Real quick , for the first question, why did the answer end up being 50? I get how we got to 49 but I dont understand why it would round up to 50 since 49 is an integer aswell isnt it?
@@JZTESTPrep ohhhhhh right the least possible value that's greater than 49. Thanks. One more question though for number 20. How did you get-15, and 7 I was a bit lost there.. thanks again 🙏
Yeah no problem. So from the equation we get the center point as (-4,19) and our radius is 11 and we’re asked to find A which is an x-coordinate. So if our radius is 11 then the point A needs to be within the range of x = -15 and x = 7. Lmk if that makes sense
@@JZTESTPrep oh ok so if we add or subtract 11 by the x axis it will give us our possible values for A in the X axis. I was adding and subtracring by 19 aswell so I got confused. Thanks man🙏
@@8wtqd8ye like the last 5-6 questions were this difficulty. But I missed one of the super easy questions cus I forgot what complementary angles were😭 and I had one question I had no idea about in module 1. So I got only 2 wrong in math
Bro, you're awesome! I mean it bro .... I scored perfect 800 on Math during practice test on blue book, I didn't see such good questions that helps us to catch up!
You can either do it 2 ways, Desmos, or by hand, he chose to do by hand, but let’s face it, you will use desmos whenever you can to save energy, For desmos, set 1 side of the equation to y = x(kx - 56) and a second part as y = -16. From there, create a slider just before the parabola touches the line, that is the fastest way to do the problem 2nd he just used the descrimmant formula to determine the value, it’s a lot more work you can you easily google that up
@@yesyes.66 I mean for number 10, it might be a bit difficult to use desmos, when I meant desmos, I meant generally but it is possible. If you want to do it in desmos, you just plug in the equations separately. y=3x+p, y=2x^{2}-16x+6p, and y=5x^2-45 you will notice an slider will appear. You can immediatly deleate the y=5x^2-45 since it does not have any p variable, thus there is no slider, the sum is always 0. You also notice that when you just slide the p slider arbitrarly (I just slid it to 0, 1, and 2) you notice that the sum is always 8 (thats why the sum of solutions formula -b/a does not reqiure the c value, since this is a parabola). So since you know that the sum is = 20/3, (20/3)-8 = 1.333. So now all you gotta do is slide p value until the y=3x+p intersects at 1.333 point, that should be easy as this is a whole number) however if you want to be more precise, or even faster this way, you can hand solve it since the intersection is at the x-intercept, (1.333,0), by plugging that into y=3x+p, which gives you 4, but you can also just slide it to 4 on desmos if you dont want to "waste your braincells on easier demos question" lol
Bro I’m going into 7th grade( I know I’m young idc) and my school offers the sat to 7th graders. I’m taking algebra 1 in school and the friends I have who took it in 7th grade scored around a 1000 composite idk what they got in math. Are there any tips or ways I could study to get a better score, I have a lot of time on my hands and if anyone else took the sat at a young age I would appreciate any specific tips, thanks .
It’s definitely helpful to start early, but I wouldn’t recommend dedicating all your free time to the SAT since you are only in 7th grade. If you’re currently scoring in the 1000 range, your priority should be mastering the core concepts tested. For that, I’d suggest using Khan Academy, as it provides lessons on everything you need for both math and reading. If you’re looking to improve your grammar, Erica Meltzer’s book is a great resource, or you could check out free grammar rule lists online. For reading, make it a habit to read both in and out of school to improve your ability to summarize and comprehend texts. Once you feel comfortable with the basics, start taking practice tests every few weeks using College Board’s Bluebook platform. After that, focus on drilling questions from the SAT question bank, especially in areas where you’re consistently missing points. Review videos or explanations for those specific sections (College Board will show you which ones). Improving your score really comes down to consistent practice. As you work through problems, you’ll start to notice patterns in how the SAT asks questions, which will help you develop the skills you need for a good score. I know it sounds like simple advice but it’s really all it takes to improve on the SAT.
![[MV] A leap of faith...ความเชื่อใจครั้งสุดท้าย (From "Petrichor the series")](http://i.ytimg.com/vi/U1piZH2CNXA/mqdefault.jpg)
![Digital SAT Math - 7 HARD Problems for the NOV 2024 DSAT [Problem Sette #10]](/img/n.gif)
Thank you, this has literally saved me with 24 hours to test day
Omg me too, praying for oct. 5th sat next morning
@@adrianamanzolillo it's already Saturday morning for me 😭3 hours till test time
@@morna224 it’s 1am for me and I’m trying lock in 😭😭
@@morna224 how was it
@@DarlineKrystel it was HARD. I got a 1410 even though I expected above 1450
dude spammed the link on reddit, but the video is actually good ngl
just posted on the thread and it immediately was in the comments
one of the best SAT videos on internet ngl; just straight to the point
for people who have SAT on 5th, almost 90% of what u saw here could be done on desmos, for eg question 5 took me 30 seconds max, take supposed values of c (i took took 4) and then 2c will be 8, add these values to table in desmos and equate table to exponential equation given in the question, it will give you b which is 6, learn to play smart boys, keep ur heads up
How did u get there supposed value of c to be 4?
Also doesn’t Desmond only let you input x and y as variables?
@@spencerjames6898u can take any value, take c as 64,100,69 anything, it will work
@@spencerjames6898replace c with x g
@@spencerjames6898 click the + and make a table
this video covered all the topics i was struggling on! i havent been able to find other videos covering all these topics so this is a godsend haha esp bc im taking the oct5 sat tysm so youre the best
i took the october sat and this is lowk rlly good; not spot on, but most of the problem he solved were on the sat. I would argue that even though some of his predictions were not relevant to the october sat, it is imperative to know them for practice and future sat
excuse my grammar, i really dont care about it when im writing a comment
Can you make a video on how to use desmos for each of these questions ?
dude this helped me so much, I just took the dsat rn. I was able to finish module two with 2 minutes left, and it was all thanks to this video. You’re a godsend bro 🙏🙏🙏
Glad I could help
what score did u get
@@mov2600 1490, I thought I could do better but that wasn’t the case apparently 💀, but I did get an 800 math
Watching this on my way to the exam 💯
😂
You can solve Question 5 (4:35) in less than a minute with Desmos. Enter a table with the two points exactly as given. Next, enter a slider for c and set it equal to 1 (any value will do). Then type the regression y1 ~ a^x1 - b. After that, you just replace b with each answer choice until r^2=1 (that means it's a perfect regression). This will only happen when b=6. You can also tell from the graph that b=6 because it's the only value for which the graph goes through the two points.
plz tell me how to do question 6 in less than a minute with the help of desmos
You can plug the equation into desmos and just see which answer choices are inside the circle.
@@payalthakur7051 1. Graph the circle 2. Type a=-16. 3. Type (a,b). 4. Create a slider for b and change its interval from 0 to 30 (checks the whole circle). Now just change the a value in Step 2 until the point passes through the circle. It is a=-14
how come you set C to 1 or any value?
@@ethancho8561 because no matter how much we multiply x by to shift the graph, the formula would be the same for b and a values
i wish i had idk option in dsat 4:56 XD . great video btw , you saved my sat tomorrow
I just gave the exam and u came in clutch for 2 or 3 qstns today
Glad I could help. Do you remember which ones you saw?
please tell me my test is in 1 hour 😢
Yo bro this is a really good review these questions are definitely important ones. Good stuff
For Question 9 (9:51) you can literally solve in two steps with desmos. Step 1: Create a table and enter two points from the original f(x) equation. Obvious ones that you should be able to do in your head are (0,1) and (4, 1.84). Step 2: Enter the regression y1 ~ (1 + p/100)^x1. Your answer is given under REGRESSION PARAMETERS. p = 16.4674. So the answer is (A) 16. This took 15 seconds. Not showing kids how to use this amazing tool that the college board actually allows you to use during the test is borderline criminal.
How did you find the points
@@shigeo9718the exponent becomes zero if you plug in x as zero, and anything to the power of zero is one. as for the other point mentioned since it’s x/4 if x=4 it’ll be 4/4 which equals one and anything to the power of 1 equals itself (in this case 1.84), therefore creating the pairs (0,1) and (4,1.84)
please tell me whats a regressoin, easy explanatino?
since im a little slow and dont understand this, the way i did it using desmos was:
1- put one equation as one line
2- put the other equation as another line
3- put “p” as a slider (so u can input values for p)
if u dont know what the slider is, it should say “add slider: p”
4- input all answers A, B, C, D and see which p value makes the 2nd line look most similar to the first line
5- and voila! the closest line should be p=16!
if this helps anyone looking for a desmos solution 😢
subscribed! Bro, you deserve a many likes, subscribers.... Thank you so much!
question 6 can be done on desmos after you sub c as 1 yeah
thanks for the vid, really helpful for test tomorrow
today before the sat for the first time! Goodluck me…
Dude these are so good plz post more I’m taking October
I am glad to know it from u 'cause it was what i needed, i really appreciate it👍🏻
Yo I just took the sat, I got 3 questions thanks to you i didnt even watch the full video
W, which ones?
@@JZTESTPrep very similar of the second one, exact same of 3, exact same of 6 too bad I didn't watch your 6th one I couldnt do it, also a similar 9 I think. I could only do 2 and 3 but thanks to you I did them so xD
You can solve question 10 in under a minute on Desmos, plug in the full equation, set a slider for p, and change the value for p multiple times until you find that the sum of the solutions is 6.67.
question how do u easily find the sum of the solutions? i have to manually add up each solution value and see if its correct
@@yesyes.66literally just -b/a and the product is c/a
Your explanation is really helpful man! Keep it going please!
this vid was really helpful! is there another google classroom, it says it's full
Yes new code is: mvi6sng
Bro I literally saw like 5 of these questions. Thank u bro 🙏
Which ones?
Bro thank you so much for this! It has helped me a lot!!! :)
Could you in the future do videos on these specific problems. They were from the practice tests, and the answer explanations are confusing.
Practice Test 3: #22 (1st mod) #8, #16 (2nd module hard)
Practice Test 4: #15, #22 (2nd module hard)
Practice Test 5: #22 (2nd module hard)
Practice Test 6: #22 (2nd module hard)
For sure I'll look into those questions when I make my next video
Dude this was all the stuff that screwed me on the practice God bless
Helpful one! Although a few questions could have been done better using Desmos regression, eg Q-9.
Can u pls tell me if there's still paper sat or not ?
@@Meow123-i7b no it's all digital
@@lol-bm3bi okay.. Thanks for replying
THANK YOU
Thank youu, i have a question what editing software did you use to make this video?😭🙏🏻
capcut
thank youuuu, that's gold
Hey, nice video BUT. What formula is that on 9:27 ? -b/2a
It is the formula for the x-coordinate of the vertex
this might be a dumb question, but for the first problem, why does k equal 50 and not 49?
Great question. A lot of ppl forget that question says that K is an integer constant. So since it is 49
@@JZTESTPrep This made absolutely no sense but I don't think it is your fault, the understanding of math may not be the best..
What part of it are you having trouble understanding?
K = 49 will give you one solution.
K = 50 yields no real solution.
@@meep9963so an integer is a whole number so we need to find the smallest whole number that is >49 which is 50
9/10 cooking 😤
For question 4 , i had 5103 which is right but looking at your solution , why did you assume c is 100 . Nice tutorials though
THANK YOU SO FUCKING MUCH YOU HIT ALL THE QUESTIONS I WAS STRUGGLING WITH
Thanks, it helped me a lot. Kisses from Brazil
Is it possible to do question 4 on demos?
I will take the SAT exam and this will be the first time I take this exam. Can anyone here help me?
thanks for ur video, appreciated it
For question 8 can’t we also just plug in (-1,-8) into the equation since we already know c to solve for b?
Yes, I actually like that method better since you won’t need to remember the formula
For Q6 couldn't you just type in the formula and make each option x = ; so that which ever line cross it would be it?
Hey! How to solve question 5 in desmos?
can someone pls explain to me why a value is between ( -15 , 7 ) and why radius 11 affect a ? Question 6 btw
We agree that the x-coordinate of the center of the circle is -4. So if the radius is 11, then the point must be somewhere in between x=-15 or x=7
htanks the video is really good :)
The video is great. Keep it up.
Yo sup dawg this videos great, just wondering, you got any tips for writing the sats for international students? If I'm getting 790s in the practice ones will I get around the same on the real one?
Wow 790 on English is great. Seems like you got the English section down already. I would say practice test are pretty accurate so you should be good to go on test day.
Cool beans, thanks for the reply! Although I meant 790 for the math section 😅
I think I may have spoken too soon tho, took about a 3 week break from sat studying and my score dropped down to a 710😭😭 lmaooo it's the second module dude. I feel like I run out of time every single time lmao. Got any tips?
why in the first question the answer was 50 instead of 49?
A lot of ppl forget that question says that K is an integer constant. So since it is 49
for queston 5 do we just assume that the equation is equally to y?
I’m so screwed 😭
You’ll do great. You are already taking the initiative to study which puts you ahead of most people
@@JZTESTPrep just took the test. def time was an issue but a lot of the questions you mentioned were on the test! Thanks!
hii there’s a lot of formulas being used is there any resource i can use to memorize all the formulas needed for the sat for math?
If you go to my TikTok, the video where I explain how I got an 800 has a list of the most important formulas not given. Just remember for the discriminant >0 means 2 real solutions, =0 means 1 real solution, and
Bro is so clutch
(2.26) question 3, how is the product of the solutions c/a . where can i find this rule?
It’s formally called Vietas Formulas
what are this type of questions call advance math advance algebra.
Sir... these questions were on my august sat. Do they still apply? Are u making a new vid before October
The SAT always reuses the same question types. You should expect to see similar questions on the October test
If you want some more questions check out some of my recent TH-cam shorts. I go over some other “hard” questions that may show up
can anyone re explain me question 7? i quite did not understand it.
Ok I notice you explain things in a way that assumes all watchers understand basic math concepts, in the future if you're ever up to it please make an in depth video for some of us
Yeah this video is for those who are mostly just struggling with the hardest question types and trying to get those last 40-50 extra points. If you don’t understand most of the basic math concepts on the SAT watching this video to study is not best way to improve your math score
If you’re looking to learn these basic math concepts I would use khan academy since it goes over pretty much all the concepts u need for the SAT. Once you’ve done that take blood test and see what types of questions ur getting wrong, only then I would I use videos like this to supplement my practice
on question 19 where did you pull out the c/a and all the other variables?
c/a is the formula for the product of solutions. We are told that the product of solutions is kab. So we set that equal to c/a. So c=ab because it is the value of c and a=57 because it is the coefficient of a
@@JZTESTPrepwhat other formulas should I know
Is this for the December 1 SAT test please reply me😢😢😢
Sorry for the bad audio on question 1
It okay... we need more videos from you starting from now!
for number 2 isnt the same slope and y intercept mean there are infinite solutions? why would there be no solutions
Well we know they have different y-intercepts. So if they have the same slope and different y-int they will never intersect each other.
Hello quick question on number 19, where did the a-b=9 and a^2-b=219 come from?
Great question. We are given the equation a^x - b which passes through the points (c,9) and (2c,219). Since we plugged in a value of 1 for C (which is also the x-coordinate) we can plug that into the equation we were given. So we set that equation equal to our y-coordinates for both points. Then we solve for B through substitution.
69 subscriber? U deserve more man
Hello. I have a question. Why in question 20 AC is equal to BC. It's first time I am hearing that if they are making right angle then they are equal. Thank you
Sorry, that was my mistake. I meant to say it's because they're both radii of the circle, so AC equals BC. And because it's a right angle, we can use the Pythagorean theorem to find the length of AB.
Good video. Saw the link on reddit
hey what formula is the -b/2a in question 16, I don’t understand the implementation if that part in the answer !! Thank you
Good questions. It is the formula for the x-coordinate of the vertex. Since we know that the x-coord is -1 at the vertex we just set -b/2a equal to -1. However what I realize now is that you don't need to do all that since you can just plug in the vertex point into the equation to find b
@@JZTESTPrepI understand how the formula for the x coordinate for the vertex point get you b. I’m now curious how you could plug in the vertex point (into the equation?) to get b since that sounds simpler. Can you explain that pls
Yeah, so our vertex is at point (-1,-8) so we could just plug that into the equation y=2x^2 + bx + c because we found the value of C already which is -6. So our equation would become -8=2(1) +b(-1) -6 and we get that b=4.
@@JZTESTPrepI see ty !!
How do you know we are gonna see questions like this on October SAT?
This video compiles commonly tested questions. Many people saw multiple questions in this video on August SAT. Since college board reuses the same question types you will definitely see a couple questions like the ones in this video.
@@JZTESTPrep Maybe we will see these kinda questions as hard ones? Especially in Module 2? Or they are easy questions?
Hii, could you please explain the 3rd quation one more time? I don't understand why the product of the solutions is c/a
Viyet theorem
The formula for the product of solutions is c/a in a quadratic equation (ax^2 + bx +c) where C is the last value of the equation and A is the coefficient of the first value of the equation.
Why is the radius 11 in question 20?
We are given a circle formula. And r^2 is equal to 121 so r would be the square root of 121 which is 11
I’m a sophomore bout to be a junior this year and I’m most lost in half of this but I have questions on how u got 49 in the first question ( I’m on question one rn) I’ll prob leave more questions I have
Yeah feel free to ask. Just make sure your specific with what you don’t understand so I can provide a good explanation for you
Thank you so much
Is there a way to use desmos for question 5?
@@beeneeta186 is there a way to use desmos for question 1 and how?
Do a regression with the given equation using the 2 given points.
Yes - see my solution in the comments.
I am confused on how you got 11 for the radius on question 6.
Square root of 121 = 11 which is our radius
@@JZTESTPrep Can you please make this kind of video before December exam? This video is really helpful.
Hey, so in question 1, what if you subtracted 3,136 instead of adding 64k? I did it and ended up with the opposite sighn (k
Good question. So when you subtract 3,136 both sides are negative. But to get both sides to be positive you can’t just ignore the - sign. You have to multiply both sides by negative 1 and when you multiply this inequality you have to flip the the direction from < to >.
If you were to leave it with negatives on both sides it would still make sense but you would have to recognize a larger negative number is actually less than a smaller negative number
in question 9 why to equal -b/2a to -1? I didn't get where -1 came from.
-1 is the x-coordinate of the vertex. -b/2a is the formula for the x-coordinate of the vertex.
Question 4 with the percent is very confusing is there a way to do it easily with desmos?
Sorry, I'm not sure if you could solve this with desmos in an easier way. I feel like the method I used is already the easiest way to solve it.
for question one how do we know 3136 is less than 64k if we only know that when combined they are less than 0😭😭😭 y’all im done for
If 3,136 - 64k is less than 0 then we know that 64k has to be a greater value than 3,136 since if 64k was less, those two combined would not be less than 0.
I am so sorry if this sounds rude but the writing for Question 5 is a little illegible so I am a bit unsure of what some of those numbers/variables are because I can’t quite decipher them. Can someone please rewrite it for me?
Myb ig I’ll start from (b+9)^2 - b = 219. Then I foiled it out to get b^2 + 18b + 81 - b - 219 = 0. Then I simplified to b^2 +17b - 138 = 0. Then I factored and got (b+23)(b-6) and we get our answer as b=6
THANK U
I’m trying to join ur google classroom but the code does not work
Hmm that’s weird. Try pasting this: aln6wul both are L’s btw
What app are u using on video?
Freenotes
Real quick , for the first question, why did the answer end up being 50? I get how we got to 49 but I dont understand why it would round up to 50 since 49 is an integer aswell isnt it?
The inequality is k>49 not > or = to 49. So the next least integer value would be 50
@@JZTESTPrep ohhhhhh right the least possible value that's greater than 49. Thanks. One more question though for number 20. How did you get-15, and 7 I was a bit lost there.. thanks again 🙏
Yeah no problem. So from the equation we get the center point as (-4,19) and our radius is 11 and we’re asked to find A which is an x-coordinate. So if our radius is 11 then the point A needs to be within the range of x = -15 and x = 7. Lmk if that makes sense
@@JZTESTPrep oh ok so if we add or subtract 11 by the x axis it will give us our possible values for A in the X axis. I was adding and subtracring by 19 aswell so I got confused. Thanks man🙏
8:54 is the question flawed? AC=BC. horizontal distance from A to c is 1 and it should be the same for C to B. AB is the horizontal so its 1+1?
Think of it as a right triangle. We can use Pythagorean theorem to find the length of AB because we know the length of AC and BC.
Also we found AC and BC doing this as well because we are given the distance from the center point
9:34 where is that -1 from ??x-cordinate ?? Isn't -3 and 1 x coordinate,,
And wheres the value of a ??i am so lost 😭
The x-coordinate of the vertex is -1.
6:47 min how to come ( -15 , 7 )
The x-coordinate of the center is -4 and the radius is 11 so the value must be within the range of x=-15 and x=7
For number 1 why did u answer it 50
Because K can’t equal 49 since it’s K>49 and since K is an integer constant the next smallest integer value would be 50.
These sat questions?
Yes
@@JZTESTPrep that’s rough
got em all right. Im cooking on the test tomorrow.
so how was ur module 2 math, was it easier or harder than this videos
@@8wtqd8ye like the last 5-6 questions were this difficulty. But I missed one of the super easy questions cus I forgot what complementary angles were😭 and I had one question I had no idea about in module 1. So I got only 2 wrong in math
What was your score @@shriB.B
@@shalomagbuza4059 1490 yessir 790m 700e
8:32 isnt a b c all supposed to be squared why c only???, thats not pythagorean theorem, problem is my way doesnt get the answer too :(
Because A and B are already squared. 1 squared is 1 and sqrt of 102 squared is just 102
I’m cooked
Don’t worry, you’ll do great. You’re already taking the initiative to prepare yourself which puts you ahead of most people.
Hi everyone! if you found this to be helpful, join the google classroom (code: mvi6sng) to access SAT & ACT practice resources
Bro, you're awesome! I mean it bro .... I scored perfect 800 on Math during practice test on blue book, I didn't see such good questions that helps us to catch up!
"This class is full. Contact the teacher for more information.'
next time id prefer if you dont just "plug in" and do the conventional method as well.
For which question. For Q4 you would just solve it the same way without plugging in but I think using a number to visualize it is better.
For Q5 it’s not like I just plugged in for no reason either. I don’t really see any easier way to solve it but lmk if you find an easier method
bro what is that last formula -b/a? IK about -b/2a. HELP PLSSSSSSSSSSSSSSSSSSSS (Q10)
Look up sum of zeroes formula on google
it is the sum of solutions. The SAT will like directly reference it in some questions
I don’t understand the first problem
How so?
I do not get how you got 50 on the first problem at all.
You can either do it 2 ways, Desmos, or by hand, he chose to do by hand, but let’s face it, you will use desmos whenever you can to save energy,
For desmos, set 1 side of the equation to y = x(kx - 56) and a second part as y = -16. From there, create a slider just before the parabola touches the line, that is the fastest way to do the problem
2nd he just used the descrimmant formula to determine the value, it’s a lot more work you can you easily google that up
Yes I agree Desmos is easier but I wouldn’t say doing it by hand is that much more work
im scared
Wow I never knew c/a is the product of solutions, and -b/a is the sum of solutions, the more you know, tho I just chuck it into desmos lol
hi for the -b/a it’s question 10 right? how did u do it using desmos 😢
@@yesyes.66 I mean for number 10, it might be a bit difficult to use desmos, when I meant desmos, I meant generally but it is possible.
If you want to do it in desmos, you just plug in the equations separately. y=3x+p,
y=2x^{2}-16x+6p, and y=5x^2-45 you will notice an slider will appear. You can immediatly deleate the y=5x^2-45 since it does not have any p variable, thus there is no slider, the sum is always 0. You also notice that when you just slide the p slider arbitrarly (I just slid it to 0, 1, and 2) you notice that the sum is always 8 (thats why the sum of solutions formula -b/a does not reqiure the c value, since this is a parabola). So since you know that the sum is = 20/3, (20/3)-8 = 1.333. So now all you gotta do is slide p value until the y=3x+p intersects at 1.333 point, that should be easy as this is a whole number) however if you want to be more precise, or even faster this way, you can hand solve it since the intersection is at the x-intercept, (1.333,0), by plugging that into y=3x+p, which gives you 4, but you can also just slide it to 4 on desmos if you dont want to "waste your braincells on easier demos question" lol
@@yesyes.66 We have same problem bro💀🤝. I also don't know how to use desmos
Desmos can do most of this questions lol
please which ones and how 😭😢
this can all be done in desmos lmfaooo
Can u drop ur ig or somethin so i can ask u about this pls
damn u cant just say that and not elaborate 💔😔
pls tell us how
Bro I’m going into 7th grade( I know I’m young idc) and my school offers the sat to 7th graders. I’m taking algebra 1 in school and the friends I have who took it in 7th grade scored around a 1000 composite idk what they got in math. Are there any tips or ways I could study to get a better score, I have a lot of time on my hands and if anyone else took the sat at a young age I would appreciate any specific tips, thanks .
It’s definitely helpful to start early, but I wouldn’t recommend dedicating all your free time to the SAT since you are only in 7th grade. If you’re currently scoring in the 1000 range, your priority should be mastering the core concepts tested.
For that, I’d suggest using Khan Academy, as it provides lessons on everything you need for both math and reading. If you’re looking to improve your grammar, Erica Meltzer’s book is a great resource, or you could check out free grammar rule lists online.
For reading, make it a habit to read both in and out of school to improve your ability to summarize and comprehend texts. Once you feel comfortable with the basics, start taking practice tests every few weeks using College Board’s Bluebook platform.
After that, focus on drilling questions from the SAT question bank, especially in areas where you’re consistently missing points. Review videos or explanations for those specific sections (College Board will show you which ones).
Improving your score really comes down to consistent practice. As you work through problems, you’ll start to notice patterns in how the SAT asks questions, which will help you develop the skills you need for a good score. I know it sounds like simple advice but it’s really all it takes to improve on the SAT.