L12E63 Control Systems Lecture 12, Exercise 63: The root-locus method

MECE3350 Control Systems Lecture 12, Exercise 63: The root-locus method.
Lecture here: • Control Systems, Lectu...
Lecture notes here: www.biomechatr...

[@mastrau]

2:54 I got managed to get 2s^3+4.74s^2+2.88s, resulting in the only breakaway point being 0, similar to the previous example.

[@biomechlab]

upon expanding the top of the equation you should get 2s^3+4.8s^2+2.88s = 0, so something went wrong with the s^2 term. Dividing both sides of the equation by 2 gives s^3+2.4s^2+1.44s =0

[@mastrau]

@@biomechlab oh ok thank you, ill check my work over again