Derivative of Natural Logarithm Functions Calculus 1 AB
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- เผยแพร่เมื่อ 7 ก.พ. 2025
- I introduce finding the derivative of natural log functions. I then work through 8 examples with increasing difficulty finishing with the last example that involves implicit differentiation.
EXAMPLES at 11:19 12:30 13:07 17:07 22:04 24:03 26:03 Implicit example 28:07
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11 years later your videos are still making rounds :)... Taking Calculus 1 in Conroe, Tx and your videos are posted for the whole class. Aaaaannnndd lemme tell you the pain I would have if they were not! Thank you so much for all the videos I've watched over the last 6 weeks, you and I got an A!!
Really helpful! My teacher even plays some of these videos in class. You are now my part time calculus teacher.
AWESOME Gavin Quinton welcome to my part-time TH-cam classroom!
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There are a few topics in each course that I have not made videos for because I don't teach them to my classes, but for now I am done. I am teaching Algebra 1 for the first time in a long time next year and AP Calculus for the first time as well. So all my planning and new videos are going to be for those two subjects for the next school year. I do have my videos in subject playlists that you can find on my channel's homepage.
Love your energy! It's always a pleasure to see someone who enjoys the topic so much.
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I am reviewing Calculus and preparing to teach it this upcoming year which means I am making these videos as I work through the book I will be teaching from. Anything beyond the latest video has 20 years of cobwebs waiting to be dusted off. That being said I looked forward into my book to find parametric equations. I have an answer, but I don't know if it is correct. Do you have an answer I could check my work with?
:( Well...I clearly can't just jump ahead my book. I am enjoying the process of relearning calculus though. I wish I was farther into Calculus to be more helpful. If you are able to, when you get a solution worked out can you send me a picture of it through my Facebook fan page please. Thank you for watching and your support. I appreciate it very much!
Thoroughly enjoyed this video! Thanks so much! I could understand the breakup of logs thanks to the explanations you gave back when I learned PreCalc 2 with you. By the way, I just recently had my test on derivatives and got 100%. BAMM!!! :) My Calculus professor recommended me for the Honor Students Roll and I will be accepted this March when the new trimester begins. Up next, integrals and log integration and differentiation test! I'll keep you posted on the results!
OMGoodess that's AWESOME news, what an "honor" Rafael Montecristo !
...and congratulations on that 100%! You sure do know how to make a teacher proud:)
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Some teachers use a flipped classroom approach and have the students watch the video so they can spend class time discussing the problems and allow students to work "together" on learning:)
wow this was amazing! I had no idea what I was doing until I watched your video! Thanks so much!
+2vintage thanks for the continued support and choosing this channel to study with...please spread then word too:D
I think the answer is -1/2(tan(t)-cot(t)) If this is correct and you would like to see my work, send me message through my Facebook dot com/ProfRobBob fan page and I will reply with a picture.
Thank you, mr tarrou, today i had a test, and because of this, i could do those problems, and get a 100 :)
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wow Prof Rob Bob can disappear confusion and frustration, appear solution on the board with magic. :P
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Hi Prof! ProfRobBob
I just have a question, in the example f(x)=(ln(2x-1)^2)^3 I understand perfectly what u did. However, when u get the ln(2x-1)= 2/2x-1 Could you cancel the # 2 and simplify to 1/x-1???? is it the same? or should i avoid canceling?
For the trigonometry example at 26:03, the derivative of the absolute value of (cos x-1),isn't it sinx,since the absolute value of (-sin x) is (sin x)?
The absolute value function is not there after taking the derivative. The derivative ln(abs(u)) is u'/u, not abs(u'/u)
ohh,thanks!That makes sense then.
this is very neat. i love your videos. you make it easier for me kudos
thanks for studying and supporting!
congrats btw of the silver play award
thanks, it took almost 5 years but it's really awesome to finally have it in my hands!...thanks for your continued support too:)
This guy is great! "GO DO YOUR HOMEWORK!" Love it.
I hope that earns us a new subscriber too!
Thanks for choosing this free educational channel to study with:)
when you get to the implicit differentiation (second step after expanding using logarithm properties), can you write:
2yy' + (2x/x^2) + (yy'/y) = 0 ? (I think I get to the same answer that route).
at 21:28 is the 1/2 ln (X^3-2) suppose to be 1/2 ln (X^3-2)^(-1/2) ?
No, I used the power property of logs to move the exponent of 1/2 down as a coefficient…not the power rule for derivatives. Thank you for watching and your support:)
Oh ok thx :D
Could u please answer this question :
x=2 ln cot t and y=tan t + cot t
I gotta find out dy/dx.
on the second example why couldn't you simplify the 8x/4x^2... like you did on the fourth example?
Yes I did:)
14:42 CHALK DOWN!
...glad to see you made it that far:) ...LOL
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Mr Tarrou! My maths book tells me that the derivative of lnx is 1/x. so if f(x)=ln(x)
then f'(x)=1/x, how can this be?
+Isabella Leandersson really good question. 10/10 ign
Critical!!!! how to find the derivative of In(y)=X*SIN(X)*In(X) The firs thing that comes to my mind is the product rule , BUT how can i apply it on three functions????the function was y=(x^x)^sinx
He kind of looks like Boogie from Big Brother. Great GREAT VIDEO!
First to hear that one but we both LOVEd Boogie from Big Brother!
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kind of...just more handsome :)
Yall mind if I Bam on these problems
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Anything for you Mr T
THANKS!
Wow I didn't understand a thing but you were good 10/10 ign
+Roger Angeles at least you watched...BAM!!!
No, the answer is cot (2t).
chalk down!!😂😂lol
+Pascual Moreno :)
"Chalk Down!"
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"Chalk down" was not worthy of a like and subscribe?! Tron Arclight
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ch0bits ...I don't know...the words just come out randomly?! :)
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I hope you are not one of them:)
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@@codey2238 thanks!
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