Sir i have seen many teachers on youtube teaching physics And i can definatly say that your content is far more superior than other's content So don't give up sir u are bound to succeed as an educator on youtube
Good morning sir You are amazing This is the level of concepts and understanding I crave for and need Thank you very much for the precise and required clearation of concepts
The trio of you, Pankaj sir and nitin sir are literally on fire particularly in physics. Such quality of questions and knowledge was rarely found earlier on any platform. Though I am 2020 aspirant still I got to learn a lot of concepts in this subject from you all three. Thank you sir for this. ❤
Thankyou very very much sir You are clearing all our conceptual doubts which are very very essential for our jee preparation . Sir , there is a request . Can you please bring up a question on induced electric field due to change in magnetic flux ?
SIR LOOK AT 1:08 time , i think there is error in showing dotted line becoz dotted line points in radial direction not in tangential direction , tangential direction is tangent to path please correct this ,becoz it creates confusion ....hope you read this comment and reply
@@PHYSICSSIRJEE but sir read the question it says” its velocity at a point A is along the tangent to the path at point A along the dotted line shown in the first line “ but dotted line only represent component along radial not the Nett velocity rather it should be along tangent to the path of motio
You can check the problem sets of rotation on my website physicssirjee.in ... Rotation is kept free... For the rest of the chapters, you may join my "detailed" or "crash" courses on "PHYSICS SIR JEE" app
Sir are the answers options 3 , 2, 1, 3, 4 respectively? Basically I considered a general situation, applied sin rule, and got a relation between the angles Then differentiate once to find omega relation and twice to find alpha relation.
I have solved the question using POLAR COORDINATES though i have made lengthy solution becoz i have explained all the symbols used in my explanation to avoid any confusion ... and have attached the link for same below ... drive.google.com/file/d/1RvUFckQuAmhUhf7TLGXpAkjoA2HG0Riy/view?usp=drivesdk Even if anyone have confusion i will try to answer query... Cheers!!
8..35 sir, can we say that tangential acceleration is independent of reference point .Is it zero in the above question. Is there any relation between tangential acceleration a_t and angular acceleration about reference point other than Centre of circle in non uniform circular motion. kindly give reply sir.
yes tangential acceleration doesnt depend on reference point , because tangent is defined for a curve so the component will always be defined for a curve
Sir I didn't get why you used w=v perpendicular/r when r was changing but this approach turned out to be incorrect for angular acceleration. What is the reason for it?
Sir I had heard that omega of a body is independent of non rotating frame. So y does omega has diff value abt 0,0 is it because it is w of A w.r.t 0,0?
Sir, I have a confusion. We can calculate angular velocity by transverse velocity . But we can't calulate angular acceleration by transverse acceleration?
@@PHYSICSSIRJEE Hello sir, when we found omega about O to 0.2 times omega about centre. which is constant. so if we differentiate omega about O (which is constant) we get zero.
@@PHYSICSSIRJEE @PHYSICS SIR JEE - JANARDHAN - IIT JEE and Olympiad at 6:20 we get omega about O to be o.2 times of about centre. => omega about O is constant. But at 16:40 we get angular acceleration about O to be non-zero. which we should be getting zero because of constant omega about O.
Omega about O is not constant , theta used at 6:20 is one of the values of a variable angle. You have to do general calculation like what was done at end and then differentiate and finally substitute for theta value at this instant . For eg , if Omega in a problem at an INSTANT is say 2 rad/s , you won't differentiate this number and say rate is zero. Instead you find general function and differentiate that
Everyone, please chill 😀👍, he was just requesting . I am happy working where I am, especially with my students I have got . He doesn't know that , it was just an innocent request from him 🙂
Sir i have seen many teachers on youtube teaching physics
And i can definatly say that your content is far more superior than other's content
So don't give up sir u are bound to succeed as an educator on youtube
Thank you 👍☺️. Please kindly share this content in Students groups ( whatsapp and telegram) if possible 🙏
I am a very slow learner took me a large time for about an hour to grasp but understood everything.
NOW UNDERSTOOD THE 5TH PART ......THANK U SIR
Made it very simple sir🙏🙏
Learned the difference between transverse acceln and tangential acceln.
Thank you so much sir🙏🙏❤️
#78 For My Revision( No doubt you are delivering best physics content on TH-cam 🙏🏅💐)
PWAG bhi dekh sakto ho bhaiya
Thank you sirji☺❤
Sir 4th question was a gem but rest were also excellent in terms of developing deep understanding. Thankyou !
Love u sir u work so hard to give a a great content
thank you sir
Good morning sir
You are amazing
This is the level of concepts and understanding I crave for and need
Thank you very much for the precise and required clearation of concepts
Excellent explanation sir
Thank you sir for such a nice problem 🙌🙌
Thanks sir for this amazing concept:)
Beauty !!!!
Very happy that you liked it ☺️. Please kindly share it with your friends groups in telegram and whatsapp 🙏 and help the channel 👍
@@PHYSICSSIRJEE Absolutely sir
I understood the physics behind but the mathematics part of differentiation would become lot better after reading differentiation in maths this year.
😊❤
Thank you very much sir 😇
The trio of you, Pankaj sir and nitin sir are literally on fire particularly in physics. Such quality of questions and knowledge was rarely found earlier on any platform. Though I am 2020 aspirant still I got to learn a lot of concepts in this subject from you all three. Thank you sir for this. ❤
U can also check physics with akash goyal sir channel and ....physics with ambarish sir
@@vaibhavkumar5419 Yeah I forgot their names but they are also fantastic. I follow them too. 😊
@@vaibhavkumar5419 and physics galaxy by Aashish Arora sir
Thankyou very very much sir
You are clearing all our conceptual doubts which are very very essential for our jee preparation .
Sir , there is a request . Can you please bring up a question on induced electric field due to change in magnetic flux ?
To write angular accleration we couldve also used vectors rght? To right omega as r×v/(r)sqr then diffrentiate
Yes , you can👍
SIR LOOK AT 1:08 time , i think there is error in showing dotted line becoz dotted line points in radial direction not in tangential direction , tangential direction is tangent to path please correct this ,becoz it creates confusion ....hope you read this comment and reply
Dotted line in that picture points in radial direction as an extension of position vector in the Question
@@PHYSICSSIRJEE but sir read the question it says” its velocity at a point A is along the tangent to the path at point A along the dotted line shown in the first line “ but dotted line only represent component along radial not the Nett velocity rather it should be along tangent to the path of motio
@@ANURAGGUPTA-fe4ek yeah , that was a typo 👍
😊thanks!!sir
Sir please give pdf of good questions on rotation
You can check the problem sets of rotation on my website physicssirjee.in ... Rotation is kept free... For the rest of the chapters, you may join my "detailed" or "crash" courses on "PHYSICS SIR JEE" app
thank you sir!
revised 24/12/2021
If r is changing.. why did you use v=wr in finding w..
Because v is [v perpendicular ] to r at that instant. w is d theta / dt which can be with some mathematical sense be written as [v perpendicular ]/r
@@PHYSICSSIRJEE but sir in angular acceleration transverse acceleration is also perpendicular to r vector. This is something that is indigestible.
hello sir in 3rd prob why cant we diff rwcos@ and rwsin@ and find acceleration then finding their magnitude
Chewing gum analogue ❤️❤️❤️👍
😁💡
Sir are the answers options 3 , 2, 1, 3, 4 respectively?
Basically I considered a general situation, applied sin rule, and got a relation between the angles
Then differentiate once to find omega relation and twice to find alpha relation.
👍🙂👏
I have solved the question using POLAR COORDINATES though i have made lengthy solution becoz i have explained all the symbols used in my explanation to avoid any confusion ... and have attached the link for same below ...
drive.google.com/file/d/1RvUFckQuAmhUhf7TLGXpAkjoA2HG0Riy/view?usp=drivesdk
Even if anyone have confusion i will try to answer query...
Cheers!!
I lost when you wrote that first equation directly citing Russel hibbler's book. Keep it simple man.
8..35 sir, can we say that tangential acceleration is independent of reference point .Is it zero in the above question.
Is there any relation between tangential acceleration a_t and angular acceleration about reference point other than Centre of circle in non uniform circular motion.
kindly give reply sir.
yes tangential acceleration doesnt depend on reference point , because tangent is defined for a curve so the component will always be defined for a curve
Sir I didn't get why you used w=v perpendicular/r when r was changing but this approach turned out to be incorrect for angular acceleration. What is the reason for it?
Because r is changing and produces extra terms in differentiation , please refer to Morin to get a feel for these
while differentiating omega vector, because of product rule, we get extra term
Equation bhale hi general angle kr liye aa jaye( refering to the last explanation) but for 90° answer will remain that only!
Sir I had heard that omega of a body is independent of non rotating frame. So y does omega has diff value abt 0,0 is it because it is w of A w.r.t 0,0?
‘Omega of a body’ is different from omega of a point on a body w.r.t an outside point
@@PHYSICSSIRJEE okay sir. Is this same for angular acceleration?
has anyone solved it by polar coordinates??
Yes i have solved please find my comment in the comment section....
I think these questions are at par with INPHO .😇
tbh.. they are exactly a little above mediocre jee level
Excellent sir
In which institute are you teaching ??
And what is your teaching experience sir
You are ossom
Check it in the About section of this channel.
Sir, I have a confusion. We can calculate angular velocity by transverse velocity . But we can't calulate angular acceleration by transverse acceleration?
Because a = r alpha doesn't follow from v= r omega when r is variable
@@PHYSICSSIRJEE Hello sir,
when we found omega about O to 0.2 times omega about centre. which is constant. so if we differentiate omega about O (which is constant) we get zero.
Timestamp of your doubt ?
@@PHYSICSSIRJEE
@PHYSICS SIR JEE - JANARDHAN - IIT JEE and Olympiad
at 6:20 we get omega about O to be o.2 times of about centre.
=> omega about O is constant.
But at 16:40 we get angular acceleration about O to be non-zero.
which we should be getting zero because of constant omega about O.
Omega about O is not constant , theta used at 6:20 is one of the values of a variable angle. You have to do general calculation like what was done at end and then differentiate and finally substitute for theta value at this instant .
For eg , if Omega in a problem at an INSTANT is say 2 rad/s , you won't differentiate this number and say rate is zero. Instead you find general function and differentiate that
ofc, the thing that I do gotta be wrong. JK. loved the video sir
opp
Sir will you join unacademy plus..I want to study from you for jee...🙏🏼🙏🏼
Right now, not possible, as I am already working with an offline institute 🙂
Prmo maths you are dumbest person i have ever seen
Everyone, please chill 😀👍, he was just requesting . I am happy working where I am, especially with my students I have got . He doesn't know that , it was just an innocent request from him 🙂
I am sorry sir...😭😭 Plz forgive me 🙏🏼🙏🏼
Sir i hope you can be eligible for monitisation please do it sir you will get upto 1,64,235.7988 ruppes